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OCR GCSE Biology Revision

Explore OCR GCSE Biology revision topics. Check the official specification for complete requirements for your exam year and route.

Qualification code: J247

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Course details

OCR · GCSE BiologyJ247Exam years · 2027

Assessment The assessment includes Paper 1, Paper 2 and Paper 3; see the official specification for the full structure.

Tick a point after revising it. Progress is saved on this device and does not measure mastery.

Reviewed course guidance

Revision points, with the explanation beside them

Open a point to read what to know, how to use it in an assessment, a plain-language explanation and a self-check. Answers stay hidden until you choose to reveal them.

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Examination tier

  • Foundation Tier
  • Higher Tier

Qualification at a glance: tier entry and assessment papers

Topic group

Cell as a working unit

1 revision points
  • Core

    Scope: Core · §2c B1.1a–b (supporting cell structures)

    Open revision guidance

    What to know

    • Animal and plant eukaryotic cells share a membrane, cytoplasm, ribosomes and a nucleus; plant cells also have a cellulose wall, chloroplasts and a large permanent vacuole.
    • Bacterial cells are smaller prokaryotes: circular DNA lies free in the cytoplasm, and some have plasmids and a cell wall.

    What to do in an assessment

    • When a micrograph shows a nucleus and membrane-bound organelles, identify a eukaryote
    • use the wall and chloroplasts to distinguish a plant cell.

    In plain language

    When a micrograph shows a nucleus and membrane-bound organelles, identify a eukaryote; use the wall and chloroplasts to distinguish a plant cell.

    Self-check

    Why can a bacterium have DNA but no nucleus?

    Show the answer

    Its DNA is present as a circular loop in the cytoplasm; prokaryotes do not enclose DNA in a nucleus.

Topic group

Specialisation and scale

1 revision points
  • Core

    Scope: Core · §2c B2.1c and B2.2a (supporting specialisation and scale)

    Open revision guidance

    What to know

    • A specialised cell has structures adapted to a job: a red blood cell has a biconcave shape and haemoglobin; a root hair cell has a long extension; a sperm cell has a flagellum and many mitochondria.
    • Magnification is image size divided by actual size, using matching units; 1 mm = 1000 µm.

    What to do in an assessment

    • For a microscopy calculation, convert both measurements to the same unit before dividing
    • then state the magnification with no unit.

    In plain language

    For a microscopy calculation, convert both measurements to the same unit before dividing; then state the magnification with no unit.

    Self-check

    A 40 µm cell is drawn 8 mm long. What is the magnification?

    Show the answer

    8 mm = 8000 µm; 8000 ÷ 40 = ×200.

Topic group

Microscopy and evidence

1 revision points
  • Core

    Scope: Core · §2c B1.1a, B1.1c and B2.2a (supporting microscopy and scale)

    Open revision guidance

    What to know

    • A light microscope reveals cells and larger structures; an electron microscope resolves smaller organelles because electrons have a much shorter wavelength.
    • A labelled biological drawing records observed proportions and clear structures rather than artistic shading.

    What to do in an assessment

    • State the specimen, magnification or scale bar, and the visible evidence that supports an identification
    • do not infer an organelle that cannot be resolved.

    In plain language

    State the specimen, magnification or scale bar, and the visible evidence that supports an identification; do not infer an organelle that cannot be resolved.

    Self-check

    Why might an electron micrograph show more detail than a light micrograph?

    Show the answer

    Its higher resolving power can separate structures that are too close together to appear distinct under a light microscope.

Topic group

Membranes and transport

1 revision points
  • Core

    Scope: Core · §2c B2.1a (supporting membrane transport)

    Open revision guidance

    What to know

    • Diffusion is net particle movement from higher to lower concentration. Osmosis is net water movement through a partially permeable membrane from a more dilute to a more concentrated solution.
    • Active transport moves substances against a concentration gradient using energy from respiration and membrane-carrier proteins.

    What to do in an assessment

    • Describe the direction, membrane and gradient separately
    • a plant cell in a concentrated solution loses water and becomes flaccid, whereas a dilute solution can make it turgid.

    In plain language

    Describe the direction, membrane and gradient separately; a plant cell in a concentrated solution loses water and becomes flaccid, whereas a dilute solution can make it turgid.

    Self-check

    A cell takes up mineral ions when their concentration is lower outside than inside. Which process explains this?

    Show the answer

    Active transport, because ions move against their concentration gradient and energy is needed.

Topic group

Enzymes and rate

1 revision points
  • Core

    Scope: Core · §2c B1.2f–g (supporting enzyme activity)

    Open revision guidance

    What to know

    • Enzymes are protein catalysts: a substrate fits the enzyme active site, forms an enzyme–substrate complex, and product leaves.
    • High temperature or an extreme pH can alter the active site shape; the substrate then fits less well and the rate falls.

    What to do in an assessment

    • For an enzyme graph, identify the optimum and describe both sides of the curve
    • separate the collision-rate effect of warming from denaturation above the optimum.

    In plain language

    For an enzyme graph, identify the optimum and describe both sides of the curve; separate the collision-rate effect of warming from denaturation above the optimum.

    Self-check

    Why does very high temperature reduce enzyme activity irreversibly?

    Show the answer

    Bonds maintaining the protein structure break, changing the active site so the substrate no longer fits.

Topic group

Digestion and absorption

1 revision points
  • Core

    Scope: Core · §2c B1.3d–f (supporting digestion of biological molecules; digestive anatomy is enrichment)

    Open revision guidance

    What to know

    • Amylase breaks starch into sugars, proteases break proteins into amino acids, and lipases break lipids into fatty acids and glycerol.
    • Bile is made by the liver and stored in the gall bladder; it neutralises acidic chyme and emulsifies fat into droplets with a larger surface area.

    What to do in an assessment

    • Link each digestive enzyme to its substrate and products
    • explain that villi provide a large area, thin epithelium and blood supply for rapid absorption.

    In plain language

    Link each digestive enzyme to its substrate and products; explain that villi provide a large area, thin epithelium and blood supply for rapid absorption.

    Self-check

    How does emulsification help lipid digestion without chemically digesting fat?

    Show the answer

    It breaks large fat globules into small droplets, increasing the surface area on which lipase can act.

Topic group

Gas exchange and breathing

1 revision points
  • Core

    Scope: Core · §2c B2.2b and B1.3a (supporting oxygen transport and respiration; lung anatomy is enrichment)

    Open revision guidance

    What to know

    • Alveoli have a large surface area, a moist one-cell-thick wall and dense capillaries; ventilation and blood flow maintain steep oxygen and carbon-dioxide gradients.
    • Inhalation contracts the diaphragm and external intercostal muscles, increasing chest volume and lowering pressure so air enters.

    What to do in an assessment

    • When comparing a healthy and damaged lung, connect a changed surface or diffusion path to the direction of gas movement and then to blood concentration.

    In plain language

    When comparing a healthy and damaged lung, connect a changed surface or diffusion path to the direction of gas movement and then to blood concentration.

    Self-check

    Why does emphysema reduce oxygen uptake?

    Show the answer

    Alveolar walls are damaged, reducing exchange area, so oxygen diffuses into blood more slowly.

Topic group

Blood and circulation

1 revision points
  • Core

    Scope: Core · §2c B2.2c–e (supporting the circulatory system and blood)

    Open revision guidance

    What to know

    • The heart has a right and left side separated by a septum; valves prevent backflow, and the left ventricle has a thick wall to drive blood around the body.
    • Arteries carry blood away from the heart under high pressure, veins return blood and have valves, and capillaries have thin walls for exchange.

    What to do in an assessment

    • Trace a named route in order, stating whether blood is oxygenated at each point
    • pulmonary arteries are an exception to the usual oxygen content of arteries.

    In plain language

    Trace a named route in order, stating whether blood is oxygenated at each point; pulmonary arteries are an exception to the usual oxygen content of arteries.

    Self-check

    Why is the left ventricular wall thicker than the right?

    Show the answer

    It must generate greater pressure to pump blood around the whole body rather than only to the lungs.

Topic group

Transport in plants

1 revision points
  • Core

    Scope: Core · §2c B2.2f–j (supporting plant transport)

    Open revision guidance

    What to know

    • Xylem vessels are dead, hollow tubes reinforced with lignin; they carry water and mineral ions from roots towards leaves.
    • Phloem transports dissolved sugars by translocation between sources and sinks; this movement can occur in either direction in different sieve tubes.

    What to do in an assessment

    • Distinguish transpiration (water loss from leaves) from translocation (sugar movement)
    • explain how evaporation from mesophyll pulls water up xylem.

    In plain language

    Distinguish transpiration (water loss from leaves) from translocation (sugar movement); explain how evaporation from mesophyll pulls water up xylem.

    Self-check

    Which tissue moves sucrose from a leaf to a growing root?

    Show the answer

    Phloem, by translocation from the source leaf to the sink root.

Topic group

Photosynthesis and limiting factors

1 revision points
  • Core

    Scope: Core · §2c B1.4a–f (supporting photosynthesis)

    Open revision guidance

    What to know

    • Photosynthesis transfers light energy into chemical energy: carbon dioxide and water form glucose and oxygen. Chlorophyll in chloroplasts absorbs light.
    • Light intensity, carbon-dioxide concentration and temperature can limit the rate; increasing one factor stops helping once a different factor is limiting.

    What to do in an assessment

    • Use the curve to identify the limiting factor in each region
    • explain that a plateau signals another resource or enzyme-controlled step now limits rate.

    In plain language

    Use the curve to identify the limiting factor in each region; explain that a plateau signals another resource or enzyme-controlled step now limits rate.

    Self-check

    Why can extra light stop increasing photosynthesis at high intensity?

    Show the answer

    Another factor such as carbon dioxide or temperature has become limiting, so light is no longer the rate-limiting factor.

Topic group

Respiration and energy

1 revision points
  • Core

    Scope: Core · §2c B1.3a–f (supporting respiration)

    Open revision guidance

    What to know

    • Aerobic respiration uses glucose and oxygen and produces carbon dioxide and water, releasing a high yield of ATP. Anaerobic respiration also uses glucose but occurs without oxygen and yields less ATP.
    • In human muscle, anaerobic respiration forms lactate; fermentation in yeast and plants produces ethanol and carbon dioxide. Oxygen debt describes extra oxygen later used to restore resting conditions.

    What to do in an assessment

    • Do not say breathing itself releases energy: ventilation supplies oxygen, while cellular respiration in cells transfers energy for muscle contraction and other processes.

    In plain language

    Do not say breathing itself releases energy: ventilation supplies oxygen, while cellular respiration in cells transfers energy for muscle contraction and other processes.

    Self-check

    Why does a sprinter continue breathing rapidly after a race?

    Show the answer

    Additional oxygen is taken in to help remove or process lactate and restore the body to its resting state.

Topic group

Pathogens and transmission

1 revision points
  • Core

    Scope: Core · §2c B6.3d–f (supporting pathogen transmission and diseases)

    Open revision guidance

    What to know

    • A pathogen is a disease-causing microorganism. Bacteria can reproduce rapidly and may release toxins; viruses reproduce inside host cells and damage them.
    • Transmission can occur through air, water, direct contact or vectors; hygiene, isolation and vector control interrupt transmission routes.

    What to do in an assessment

    • In an unfamiliar outbreak, distinguish evidence of transmission from symptoms
    • identify a control measure that blocks the actual route.

    In plain language

    In an unfamiliar outbreak, distinguish evidence of transmission from symptoms; identify a control measure that blocks the actual route.

    Self-check

    Why will handwashing not directly cure an infection already inside tissues?

    Show the answer

    It reduces transfer of pathogens from hands but does not remove pathogens already reproducing inside the body.

Topic group

Defences, immunity and medicines

1 revision points
  • Core

    Scope: Core · §2c B6.3j–o (supporting defences, immunity and medicines)

    Open revision guidance

    What to know

    • Physical barriers include skin, mucus and cilia. White blood cells can engulf pathogens or make specific antibodies that bind antigens.
    • Vaccination exposes the immune system to antigens so memory cells enable a faster response on later exposure. Antibiotics treat susceptible bacteria, not viruses.

    What to do in an assessment

    • Explain the memory-cell sequence when comparing first and later exposures
    • do not claim a vaccine instantly prevents all infection.

    In plain language

    Explain the memory-cell sequence when comparing first and later exposures; do not claim a vaccine instantly prevents all infection.

    Self-check

    Why do antibiotics not treat influenza?

    Show the answer

    Influenza is caused by a virus, and antibiotics target bacterial structures or processes rather than viruses.

Topic group

Nervous coordination

1 revision points
  • Core

    Scope: Core · §2c B3.1a–h (supporting nervous coordination)

    Open revision guidance

    What to know

    • A stimulus is detected by a receptor; impulses travel along sensory neurones to the central nervous system and then along motor neurones to an effector.
    • A reflex arc produces a rapid, automatic response; at a synapse, neurotransmitter crosses the gap and triggers a new impulse.

    What to do in an assessment

    • Order the pathway using receptor → sensory neurone → CNS/relay neurone → motor neurone → effector
    • link speed to protection from harm.

    In plain language

    Order the pathway using receptor → sensory neurone → CNS/relay neurone → motor neurone → effector; link speed to protection from harm.

    Self-check

    What crosses a synapse to pass the signal between neurones?

    Show the answer

    A neurotransmitter chemical diffuses across the synaptic gap and binds to receptors on the next neurone.

Topic group

Hormones and homeostasis

1 revision points
  • Core

    Scope: Core · §2c B3.2a–i and B3.3a–j (supporting hormones and homeostasis)

    Open revision guidance

    What to know

    • Hormones are chemical messengers carried in blood; a target cell responds when it has the matching receptor. Insulin lowers blood glucose by increasing uptake and conversion to glycogen.
    • Homeostasis maintains internal conditions near suitable levels by negative feedback: a deviation triggers responses that oppose the change.

    What to do in an assessment

    • For a control-system question, name the detected change, hormone, target response and how that response reverses the original change.

    In plain language

    For a control-system question, name the detected change, hormone, target response and how that response reverses the original change.

    Self-check

    After a meal, how does insulin help lower blood glucose?

    Show the answer

    It promotes glucose uptake by cells and conversion of glucose to glycogen, especially in liver and muscle.

Topic group

Kidneys and water balance

1 revision points
  • Core

    Scope: Core · §2c B3.3g–j (supporting kidney water balance)

    Open revision guidance

    What to know

    • Kidneys filter blood; useful glucose, needed ions and most water are reabsorbed, while urea and excess substances are excreted in urine.
    • ADH changes the permeability of collecting ducts, adjusting how much water returns to blood; more ADH produces a smaller volume of more concentrated urine.

    What to do in an assessment

    • When interpreting urine data, distinguish solute concentration from total urine volume and explain the response to dehydration.

    In plain language

    When interpreting urine data, distinguish solute concentration from total urine volume and explain the response to dehydration.

    Self-check

    What happens to urine after dehydration raises blood water conservation?

    Show the answer

    More ADH makes collecting ducts more permeable, so more water is reabsorbed and urine volume falls while it becomes more concentrated.

Topic group

Reproduction and development

1 revision points
  • Core

    Scope: Core · §2c B3.2c–f and B5.1f–h (supporting reproduction and development)

    Open revision guidance

    What to know

    • Sexual reproduction combines gametes and produces genetically varied offspring; fertilisation joins nuclei. Asexual reproduction uses one parent and usually produces genetically similar offspring.
    • In flowering plants, pollen reaches a stigma, a pollen tube grows to an ovule, and male and female nuclei fuse.

    What to do in an assessment

    • Follow each structure and event in sequence
    • keep pollination (pollen transfer) distinct from fertilisation (nuclear fusion).

    In plain language

    Follow each structure and event in sequence; keep pollination (pollen transfer) distinct from fertilisation (nuclear fusion).

    Self-check

    What is the difference between pollination and fertilisation?

    Show the answer

    Pollination transfers pollen to a stigma; fertilisation is fusion of the male and female gamete nuclei.

Topic group

Genes, inheritance and cell division

1 revision points
  • Core

    Scope: Core · §2c B2.1b and B5.1a–m (supporting genes, inheritance and cell division)

    Open revision guidance

    What to know

    • A gene is a DNA base sequence coding for a polypeptide; alleles are alternative versions of a gene. Chromosomes carry genes in the nucleus.
    • Mitosis makes two genetically identical cells for growth and repair; meiosis makes haploid gametes with genetically varied combinations.

    What to do in an assessment

    • Use a genetic diagram with defined allele symbols and parental genotypes
    • state whether a result is probability, not a guaranteed family outcome.

    In plain language

    Use a genetic diagram with defined allele symbols and parental genotypes; state whether a result is probability, not a guaranteed family outcome.

    Self-check

    Two heterozygous parents are Aa. What is the chance of an aa offspring?

    Show the answer

    The combinations are AA, Aa, Aa, aa, so one of four outcomes is aa: 25% for each conception.

Topic group

Variation, selection and evolution

1 revision points
  • Core

    Scope: Core · §2c B5.2a–f (supporting variation, selection and evolution)

    Open revision guidance

    What to know

    • Variation can be genetic, environmental or both. Mutations create new alleles; meiosis and fertilisation generate new allele combinations.
    • Natural selection occurs when heritable variants differ in survival or reproduction; advantageous alleles become more common over generations.

    What to do in an assessment

    • Explain a selection example as variation → selection pressure → differential reproduction → change in allele frequency, not as an organism choosing to adapt.

    In plain language

    Explain a selection example as variation → selection pressure → differential reproduction → change in allele frequency, not as an organism choosing to adapt.

    Self-check

    How can antibiotic resistance become common in a bacterial population?

    Show the answer

    A resistant variant survives antibiotic treatment and reproduces; its resistance allele is passed on, increasing in frequency.

Topic group

Ecology, cycles and biodiversity

1 revision points
  • Core

    Scope: Core · §2c B4.1a–j and B6.1a–d (supporting ecology and biodiversity)

    Open revision guidance

    What to know

    • A food chain shows energy transfer; producers capture light, and biomass is lost between trophic levels through respiration, waste and uneaten material.
    • Decomposers break down dead material and recycle mineral ions; photosynthesis and respiration move carbon between atmospheric and living pools.

    What to do in an assessment

    • For a biodiversity investigation, identify the sampling unit, use random or systematic sampling appropriately, and compare counts with equal effort and area.

    In plain language

    For a biodiversity investigation, identify the sampling unit, use random or systematic sampling appropriately, and compare counts with equal effort and area.

    Self-check

    Why is less energy available at a higher trophic level?

    Show the answer

    Organisms use energy in respiration and movement, and material is lost in waste, so not all biomass is transferred to the next level.

Topic group

Practical planning and data

1 revision points
  • Core

    Scope: Core · Specification §2b Topic B7 Practical skills and Appendix 5 mathematical skills

    Open revision guidance

    What to know

    • A fair test changes an independent variable, measures a dependent variable and controls relevant variables; repeats help reveal anomalies and improve reliability.
    • Choose a range and suitable intervals, record units, calculate a mean only after considering anomalies, and plot points with correctly labelled axes.

    What to do in an assessment

    • For a practical evaluation, link a limitation to its effect on the result and propose a feasible improvement
    • safety controls must address the named hazard.

    In plain language

    For a practical evaluation, link a limitation to its effect on the result and propose a feasible improvement; safety controls must address the named hazard.

    Self-check

    Why repeat measurements at each temperature in an enzyme investigation?

    Show the answer

    Repeats reveal variation or anomalies and allow a more reliable mean estimate at each temperature.

Topic group

Selective breeding and genetic modification

1 revision points
  • Core

    Scope: Core · §2c B6.2c–g (supporting selective breeding and genetic modification)

    Open revision guidance

    What to know

    • Selective breeding chooses parents with useful inherited features and repeats the cross over generations; it can reduce genetic variation and increase inherited health problems.
    • Genetic modification inserts or changes a gene to introduce a desired feature, but its ecological and ethical consequences require evaluation.

    What to do in an assessment

    • Compare method, timescale, source of genetic change and possible risks; do not describe selective breeding as the same process as gene editing.

    In plain language

    Compare method, timescale, source of genetic change and possible risks; do not describe selective breeding as the same process as gene editing.

    Self-check

    Why can repeated selective breeding reduce variation?

    Show the answer

    Only a small set of parents is chosen each generation, so fewer alleles are passed on and harmful recessive alleles may become common.

Topic group

Reproductive hormones and cycles

1 revision points
  • Core

    Scope: Core · §2c B3.2c–f (supporting reproductive hormones and cycles)

    Open revision guidance

    What to know

    • FSH stimulates maturation of an ovarian follicle; oestrogen rebuilds the uterus lining and suppresses FSH; LH triggers ovulation; progesterone maintains the lining.
    • Hormone concentrations change over the menstrual cycle, so use a graph to identify peaks and the events they cause.

    What to do in an assessment

    • When interpreting a hormone graph, describe timing and effect rather than claiming that a hormone concentration alone proves pregnancy.

    In plain language

    When interpreting a hormone graph, describe timing and effect rather than claiming that a hormone concentration alone proves pregnancy.

    Self-check

    Which hormone surge triggers ovulation?

    Show the answer

    A peak in luteinising hormone (LH) triggers ovulation.

Topic group

Plant reproduction and seed formation

1 revision points
  • Core

    Scope: Core · §2c B5.1f (supporting reproduction; seed-formation detail is enrichment)

    Open revision guidance

    What to know

    • Pollen grains carry male nuclei; after pollination a pollen tube grows through the style to an ovule, where a male nucleus fuses with the egg nucleus.
    • Seeds contain an embryo and food store; dispersal reduces competition with the parent plant.

    What to do in an assessment

    • Trace the sequence from anther to stigma to ovule and distinguish pollination from fertilisation.

    In plain language

    Trace the sequence from anther to stigma to ovule and distinguish pollination from fertilisation.

    Self-check

    What grows from the pollen grain after it lands on a compatible stigma?

    Show the answer

    A pollen tube grows down the style towards an ovule, carrying the male nucleus.

Topic group

Ecological relationships and nutrient cycles

1 revision points
  • Core

    Scope: Core · §2c B4.1a–c and B4.1g (supporting ecological relationships and nutrient cycles)

    Open revision guidance

    What to know

    • Decomposers secrete enzymes onto dead material and absorb soluble products, returning mineral ions to soil or water.
    • In the carbon cycle, photosynthesis removes carbon dioxide, respiration and decomposition return it, and combustion transfers stored carbon to the atmosphere.

    What to do in an assessment

    • Explain a cycle with named processes and direction of transfer; connect a human activity to the pool it changes.

    In plain language

    Explain a cycle with named processes and direction of transfer; connect a human activity to the pool it changes.

    Self-check

    How do decomposers return carbon to the atmosphere?

    Show the answer

    They respire while breaking down organic material and release carbon dioxide.

Topic group

Human impacts and conservation

1 revision points
  • Core

    Scope: Core · §2c B6.1a–d (supporting human impacts and conservation)

    Open revision guidance

    What to know

    • Habitat loss, pollution, overharvesting and climate change can reduce population size and biodiversity.
    • Conservation can protect habitats, manage harvesting or maintain genetic diversity; strategies involve ecological evidence and trade-offs.

    What to do in an assessment

    • Use a local example to state the pressure, affected population and evidence that a proposed management action helps.

    In plain language

    Use a local example to state the pressure, affected population and evidence that a proposed management action helps.

    Self-check

    Why can a wildlife corridor help a fragmented population?

    Show the answer

    It can reconnect habitats, allowing organisms to move between groups and maintaining gene flow.

Topic group

Sampling populations fairly

1 revision points
  • Core

    Scope: Core · §2c B6.1a and B4.1f; Topic B7 PAG 3 (supporting population sampling)

    Open revision guidance

    What to know

    • Quadrats estimate abundance or percentage cover in a defined area; random placement reduces selection bias. Transects reveal change along an environmental gradient.
    • The same quadrat area, sampling rule and effort are needed for a fair comparison between sites.

    What to do in an assessment

    • Calculate mean density per unit area and state sample size; explain whether random sampling or a transect matches the question.

    In plain language

    Calculate mean density per unit area and state sample size; explain whether random sampling or a transect matches the question.

    Self-check

    Why use systematic quadrats along a transect from shore inland?

    Show the answer

    The transect samples a defined gradient, showing how abundance changes with distance from the shore.

Topic group

Microscope practical and drawing

1 revision points
  • Core

    Scope: Core · §2c B1.1a and B1.1c; Topic B7 PAG 1 (supporting microscope method and drawing)

    Open revision guidance

    What to know

    • Prepare a thin specimen, focus first at low power, then increase magnification; use a scale bar or calibrated eyepiece for measurement.
    • A scientific drawing uses clear single lines, no shading, accurate relative proportions and labels that touch the relevant structure.

    What to do in an assessment

    • Record magnification and scale; make a labelled drawing from what is visible and avoid naming structures beyond the microscope resolution.

    In plain language

    Record magnification and scale; make a labelled drawing from what is visible and avoid naming structures beyond the microscope resolution.

    Self-check

    Why begin focusing with the lowest-power objective?

    Show the answer

    It gives a wider field of view and makes the specimen easier and safer to locate before magnifying further.

Topic group

Osmosis investigation and variables

1 revision points
  • Core

    Scope: Core · §2c B2.1a; Topic B7 PAG 8 (supporting osmosis investigation)

    Open revision guidance

    What to know

    • To compare water movement, cut equal-sized tissue pieces, measure initial mass, place them in known concentrations for a fixed time, then blot and reweigh.
    • Percentage change in mass allows comparison; a zero change estimates the solution concentration with similar water potential to the tissue.

    What to do in an assessment

    • Keep dimensions, solution volume, time and temperature controlled; repeat each concentration and plot mean percentage change.

    In plain language

    Keep dimensions, solution volume, time and temperature controlled; repeat each concentration and plot mean percentage change.

    Self-check

    What does zero percentage mass change suggest?

    Show the answer

    There is no net water movement, so the external solution and tissue have similar water potential.

Topic group

Higher-tier content

1 revision points
  • Higher

    Scope: Higher · Version 4.0 whole Higher-only learning outcomes: B1.2d, B1.2e, B1.4f, B3.1g–h, B3.2b, B3.2d, B3.2f, B3.2i, B3.3d, B3.3i–j, B5.1e, B6.1d, B6.2e, B6.3i, B6.3m–n; Higher-only bold details within mixed-tier B3.2h

    Open revision guidance

    What to know

    • B1.2d–e: During transcription, a gene's DNA base sequence is copied into complementary messenger RNA in the nucleus. At a ribosome, translation reads the mRNA in triplets; transfer RNA brings amino acids in the order specified by the code. A DNA base change can alter a codon and therefore the amino-acid sequence and protein shape. B1.4f: When several factors affect photosynthesis together, a graph may rise with one factor then plateau because another becomes limiting; identify the changing factor and plateau before explaining the rate.
    • B3.1g–h: Evidence about brain function can come from case studies, but injury is not a controlled experiment: damage may affect connected regions and ethically induced lesions are not acceptable. Treating nervous-system damage is difficult because nerve tissue has limited repair, nearby tissue may be irreversibly harmed and the relevant structure can be hard to reach. B3.2b,d,f: Thyroxine and adrenaline act as hormones; thyroxine participates in negative feedback controlling metabolic rate. FSH, LH, oestrogen and progesterone change across the menstrual cycle and interact to mature follicles, trigger ovulation and maintain or rebuild the uterus lining. Hormone treatment can stimulate egg maturation/ovulation in some infertility cases; discuss success and multiple-pregnancy risks rather than treating it as a guaranteed outcome.
    • Higher-only bold details within B3.2h: gibberellins can promote growth and germination; ethene promotes fruit ripening and can affect flower opening or leaf shedding. B3.2i is Higher-only in full and covers selective herbicides, rooting/cuttings, parthenocarpic (seedless) fruit and dormancy control. B3.3d,i–j: Glucagon raises blood glucose when it falls, opposing insulin. ADH makes kidney tubules/collecting ducts more permeable, increasing water reabsorption. Dehydration, excess water or high salt alter blood water balance; kidneys adjust urine concentration and thirst helps correct the imbalance.
    • B5.1e: A variant in coding DNA may change a protein's amino-acid sequence and activity, including an enzyme active site; a variant in non-coding DNA can change gene expression. B6.1d: Judge evidence linking environmental change, including water availability and atmospheric gases, to distribution changes; correlation alone does not establish the cause. B6.2e: For a gene-transfer account, restriction enzymes cut donor and vector DNA to make compatible sticky ends, ligase joins them, and a plasmid vector carries the gene into bacteria; antibiotic-resistance markers can identify transformed cells. B6.3i,m–n: Plant infection can be recognised from symptoms or microscopy in the field and confirmed in a laboratory by detecting pathogen DNA or antigen. Monoclonal antibodies are made by fusing an antibody-producing lymphocyte with a tumour cell, selecting/cloning a hybridoma and collecting the specific antibody. Labelled antibodies can detect pregnancy antigens or disease markers and may target cancer cells, but treatment effects and risks must be evaluated.

    What to do in an assessment

    • In a translation question, show the sequence DNA gene → complementary mRNA codons → amino-acid sequence → protein; explain that a mutation may have no effect, change function, or stop a protein being made.
    • For a hormone graph or control question, name the measured change, the hormone response, its target and how feedback restores the range. In a source-evaluation question, distinguish an observed association from evidence of a causal mechanism.
    • Keep the genetic-engineering sequence in order (cut, join, transfer, select) and explain the marker's purpose. For monoclonal-antibody applications, connect the antibody's specific binding to the detected antigen or targeted cell, then weigh the evidence and limitations.

    In plain language

    Higher questions often join a molecular cause to a whole-organism outcome. A changed DNA sequence can change the protein made; that can alter a cell process and then a phenotype. Hormonal control instead uses feedback: a sensed change triggers a response that opposes it. When writing a longer explanation, make each causal link explicit rather than listing terms.

    Self-check

    A coding-DNA substitution changes one codon but not the measured phenotype. Give one reason for that result and one way a different substitution could affect phenotype.

    Show the answer

    The changed codon may still specify the same amino acid, or the altered amino acid may not affect the protein's function. Another substitution could change an amino acid at an enzyme active site, altering substrate binding and therefore the phenotype.

Topic group

Assessment and exam use

1 revision points
  • Core

    Scope: Core · Specification overview, J247/01–04 assessment tables and synoptic assessment note

    Open revision guidance

    What to know

    • Candidates are entered for one tier only: Foundation Papers 1 and 2 (grades 5–1) or Higher Papers 3 and 4 (grades 9–4). Each tier has two 90-mark, 1 hour 45 minute written papers; each is 50% of the total GCSE.
    • Paper 1 or 3 assesses B1–B3 plus B7 practical skills. Paper 2 or 4 assesses B4–B6 and B7, with assumed knowledge from B1–B3; the second paper also includes synoptic assessment.

    What to do in an assessment

    • Check your entry tier before using a paper or practice question. Use the correct paper pair and include B1–B3 knowledge when a Paper 2/4 question links it to later topics.
    • Revise practical method and data skills for both papers; B7 is assessed in the written exams, not a separate practical exam.

    In plain language

    The two tiers are different paper pairs, not four papers that everyone sits. Within a chosen tier, Paper 1/3 focuses on cells through organism systems, while Paper 2/4 focuses on communities through global challenges and can connect back to the earlier biology.

    Self-check

    A Higher candidate is preparing for the paper that assesses B4–B6. Which paper is it, and what earlier knowledge may still be needed?

    Show the answer

    It is J247/04. It assesses B4–B6 and B7, with assumed knowledge of B1–B3 and synoptic links.

Topic group

Working scientifically

1 revision points
  • Core

    Scope: Core · Specification §§5e: WS1.1a–i, WS1.2a–e, WS1.3a–i, WS1.4a–f and WS2a–d

    Open revision guidance

    What to know

    • WS1.1 scientific thinking: new technology can collect new evidence and change explanations (a); use representational, spatial, descriptive, computational or mathematical models to solve problems and make predictions, while recognising model limits (b); explain both science's benefits and questions it cannot currently answer (c); discuss ethical issues (d), everyday/technological applications (e), and personal, social, economic and environmental implications (f); make decisions from evidence and arguments (g); evaluate practical and societal risk, including how perception relates to evidence and consequences (h); recognise peer review and communicate results to different audiences (i).
    • WS1.2 experimental strategies: use scientific ideas to form a testable hypothesis (a); plan a procedure to observe, test or explore it (b); choose suitable techniques, instruments, apparatus and materials (c); use sampling when needed to obtain representative evidence (d); evaluate the method and propose justified improvements or follow-up work (e).
    • WS1.3 analysis: present observations descriptively, in tables, diagrams or graphs (a); translate between forms (b); calculate and represent mean, mode or median (c); describe distributions and estimate uncertainty (d); interpret verbal, diagrammatic, graphical, symbolic or numerical evidence to identify patterns, make inferences and conclusions (e); relate explanations to hypotheses (f); evaluate accuracy, precision, repeatability and reproducibility (g); identify random and systematic errors (h); communicate the rationale, method, findings and reasoned conclusion (i).
    • WS1.4 scientific language and quantities: use accurate vocabulary, terminology and definitions (a); understand how scientific quantities are determined (b); use SI units and appropriate nomenclature (c); use powers of ten and prefixes from tera/giga/mega/kilo through milli/micro/nano (d); interconvert units (e); and report a suitable number of significant figures (f).
    • WS2 practical skills: follow instructions while manipulating apparatus correctly, measuring accurately and working safely (a); make and keep appropriate records of observations and measurements using different apparatus and methods (b); present results descriptively, in tables, diagrams or graphs (c); communicate the rationale, method, findings and reasoned conclusions in paper or electronic verbal, diagrammatic, graphical, numerical or symbolic form (d).

    What to do in an assessment

    • When asked for an improvement, name the specific source of error, explain how it affects the result, then propose a change that reduces that error while retaining the variable being tested. Distinguish random variation from a systematic bias; repeats can reveal the former but do not automatically remove the latter.
    • Use a table with headings and units, plot the independent variable on the x-axis, choose even scales, and draw a suitable line or curve. Quote data points and units when describing a trend; explain whether evidence supports the hypothesis and avoid claiming proof from one association.
    • For sampling, state the quadrat/transect or other method, where samples are placed, what is counted, how enough representative data will be obtained, and how sampling effort is kept comparable.
    • For a claim about a biological treatment or technology, separate the evidence from opinion, consider who benefits or may be harmed, practical and environmental consequences, uncertainty and risk, then justify a decision for its intended audience.

    In plain language

    A good investigation is more than a recipe: it asks a clear question, gathers measurements fairly, and tests whether the evidence really supports an explanation. In exam answers, connect each choice to its purpose, and connect each limitation to the data it could distort.

    Self-check

    A class measures oxygen bubbles from pondweed at one distance from a lamp, with one reading each. Name two weaknesses and one practical improvement for each.

    Show the answer

    One distance gives little range, so measure several planned distances while controlling other factors. A single reading cannot show variation or an anomaly, so repeat each distance and calculate a mean after checking anomalous results.

Topic group

Mathematical and data skills

1 revision points
  • Core

    Scope: Core · Specification §5f Appendix 5: biology-relevant mathematical skills M1a–d, M2a–h, M3a and d, M4a–d, M5c; all topic-specific BM outcomes

    Open revision guidance

    What to know

    • Appendix 5 Biology skills are M1a–d (decimal and standard form, ratios/fractions/percentages, estimates); M2a–h (significant figures, arithmetic means, frequency tables/diagrams/bar charts/histograms, scientific sampling, simple probability, mean/mode/median, scatter-plot correlation and orders of magnitude); M3a and M3d (the listed comparison/approximation symbols and simple algebra); M4a–d (translate graph/numeric forms, y = mx + c, plot variables, find slope/intercept); and M5c (areas of triangles/rectangles and surface area/volume of cubes). Biology does not import Chemistry/Physics-only equation rearrangement, tangents to curves or area-under-curve skills.
    • The arithmetic mean is total ÷ number of observations, the median is the middle value after ordering, and the mode is the most frequent value. A frequency table records counts; bar-chart bars for separate categories have gaps, while histogram bars for grouped continuous data touch.
    • Count significant figures from the first non-zero digit and round to the requested number at the end: 2.346 to 3 significant figures is 2.35. Keep a suitable unit with a measured or calculated quantity.
    • BM1.1i–iii: compare cell sizes and scales using matching units, estimate when boundaries or measurements are uncertain, and use standard form (for example, 0.0000034 m = 3.4 × 10⁻⁶ m). BM1.2i–ii and BM1.4i: calculate reaction rate as change per time with a compound unit; BM1.4ii–iv: translate, plot and interpret photosynthesis data with labelled axes, appropriate scales and cited values. BM1.4v: apply the inverse-square model, intensity ∝ 1/distance²; doubling lamp distance gives about one-quarter intensity.
    • BM2.1i: use percentiles to locate a value within an ordered data set and calculate percentage gain/loss of tissue mass as (final − initial) ÷ initial × 100%. BM2.2i–iv: calculate cube SA:V, use rates such as volume/time, calculate a rate and plot, draw and interpret an appropriate biological graph. BM3.1i, BM3.2i–ii and BM3.3i: extract graph/table values and translate numerical hormone or homeostasis data into a graph and back.
    • BM4.1i–v: calculate decomposition rate and percentage mass change, use fractions/percentages, plot suitable graphs and interpret evidence from charts, graphs and tables. BM5.1i–iii: use direct proportions and ratios in genetic crosses, calculate outcome probabilities, and interpret inheritance data. BM6.1i–v: calculate arithmetic means, understand and use percentiles, plot and interpret environmental data, and apply representative-sampling principles; BM6.2i: interpret food-security data in charts/graphs/tables.
    • BM6.3i–v: translate health data between graphical and numerical forms, construct/read frequency tables and charts, apply sampling principles, identify correlation in a scatter diagram without assuming causation, and calculate culture/agar cross-sectional area with πr². For example, a 4 mm radius gives π × 4² ≈ 50 mm².

    What to do in an assessment

    • Write the equation, substitute values with units, show the arithmetic, then check whether the size and direction of the result make biological sense. Convert units before calculating; for magnification use image size ÷ actual size, and for a mean use total ÷ number of readings.
    • For M5c, rectangle area = length × width, triangle area = ½ × base × perpendicular height, and a cube of side s has surface area 6s² and volume s³. For surface area/volume, calculate both in consistent units before dividing: a cube of side 2 cm has SA 24 cm² and volume 8 cm³, so SA:V = 3:1. For change in mass, retain the sign: (2.20 − 2.50) ÷ 2.50 × 100 = −12%, meaning tissue lost mass.
    • On a graph label axes with quantity and unit, use an appropriate scale, plot points accurately and translate between graph and numbers. For a straight line identify slope and intercept (y = mx + c); describe scatter as positive, negative or no clear correlation rather than asserting causation.
    • For a ratio or percentage identify the denominator first. A 12-to-3 ratio simplifies to 4:1; 12 as a percentage of 60 is 12 ÷ 60 × 100 = 20%. For a simple genetic cross, count the favourable outcomes over all equally likely outcomes and state the predicted probability, not a guaranteed family result.
    • Use the Biology M3a symbols precisely: = means equal, < or > means smaller/larger, << or >> means much smaller/larger, ∝ means proportional to, and ~ means approximately. For example, y ∝ x means y changes in direct proportion to x. Estimate first to catch misplaced decimal points or implausible orders of magnitude.

    In plain language

    The maths supports the biology: it lets you compare cell sizes, describe change, summarise repeated measurements and judge patterns. Convert first, keep track of the denominator, and carry units through every step.

    Self-check

    A potato cylinder changes from 2.50 g to 2.20 g. Calculate the percentage mass change to 2 significant figures and interpret its sign.

    Show the answer

    (2.20 − 2.50) ÷ 2.50 × 100 = −12%. The negative sign means the tissue lost mass, consistent with net water leaving the cells.

Topic group

Practical skills

8 revision points
  • Core

    Scope: Core · Topic B7, PAG 1 Microscopy

    Open revision guidance

    What to know

    • PAG 1 requires using suitable apparatus, microscopy and magnification to observe biological specimens and make labelled scientific drawings. It also covers accurate measurement and recording of length, area, mass, time, temperature, liquid/gas volume and pH.
    • A clear biological drawing uses single pencil lines, correct proportions, no shading and straight label lines that identify visible structures. Record the magnification or scale information given; never label a structure that the image does not resolve.

    What to do in an assessment

    • Prepare a slide safely, focus from low to higher power, select a representative field and record what is visible. Use image size ÷ actual size only after converting to the same unit.
    • If one eyepiece graticule division equals 10 µm after calibration and a cell spans 7 divisions, its estimated length is 70 µm. State that this is an estimate because edges and resolution limit precision.

    In plain language

    The practical is about observing carefully and recording evidence clearly. A drawing should preserve the specimen's proportions, while a calculation should show how image dimensions relate to the real specimen.

    Self-check

    A cell image is 24 mm wide; its actual width is 80 µm. Calculate magnification.

    Show the answer

    24 mm = 24,000 µm; 24,000 ÷ 80 = ×300.

  • Core

    Scope: Core · Topic B7, PAG 2 Testing for biological molecules

    Open revision guidance

    What to know

    • PAG 2 combines qualitative tests for biological molecules with safe heating and suitable apparatus. The specification expects reagent tests to be used in more complex problem-solving contexts, including continuous sampling during an investigation.
    • Benedict's solution changes from blue towards green/yellow/orange/brick-red when heated with reducing sugar; iodine changes orange-brown to blue-black with starch; Biuret changes blue to lilac/purple with protein; an emulsion test gives a cloudy white layer with lipid.
    • For the iodine test, add iodine solution to a food sample. For protein, add Biuret reagent (or sodium hydroxide followed by dilute copper sulfate); a lilac/purple result indicates protein. For lipid, shake the sample with ethanol, then add water; a cloudy white emulsion indicates lipid. Keep ethanol away from flames.

    What to do in an assessment

    • Use separate clean samples and equal measured volumes. Add Benedict's solution to a sample and heat it in a hot-water bath; record the resulting colour/precipitate. Add iodine directly for starch; use the alkali/copper-sulfate sequence or Biuret reagent for protein; use ethanol followed by water for the lipid emulsion test. Do not heat ethanol or use it near a flame.
    • Record the observed colour/layer as evidence, not just 'positive'; include negative or known positive controls where useful. In a continuous enzyme investigation, take timed aliquots and quench or test each sample consistently. Keep temperature, pH, volumes and sampling interval controlled so colour-change timing is comparable.

    In plain language

    Each reagent is evidence for a particular molecule. A valid result needs a consistent amount of sample and reagent, appropriate heating where required, and an observation recorded in enough detail to compare samples.

    Self-check

    A heated food sample changes Benedict's solution from blue to orange. What does that support, and what does it not prove?

    Show the answer

    It supports the presence of reducing sugar. It does not identify which sugar is present or give its concentration without a calibrated quantitative method.

  • Core

    Scope: Core · Topic B7, PAG 3 Sampling techniques

    Open revision guidance

    What to know

    • PAG 3 requires suitable sampling to investigate organism distribution and abundance in an ecosystem by direct fieldwork, including both biotic and abiotic factors. Quadrat, transect and environmental measurements answer different questions.
    • Random quadrats reduce location-selection bias when estimating abundance in a habitat; a belt transect records changes along a gradient. Abiotic readings such as light, moisture or temperature help interpret why organisms vary.

    What to do in an assessment

    • Define the study area, choose random coordinates for an abundance estimate or a fixed transect for a spatial gradient, use the same quadrat area and count rule, and repeat enough placements to compare sites.
    • Calculate mean abundance per quadrat or frequency (% quadrats occupied = occupied quadrats ÷ total quadrats × 100). Measure the named abiotic factor at each sample point and compare like with like.

    In plain language

    A sample is useful only if its method matches the question. Random locations estimate what is typical; a transect shows how a community changes across a place. Measuring the habitat condition alongside organisms can reveal a pattern, but does not by itself prove a cause.

    Self-check

    You want to test whether plant abundance changes from a dry path to a damp stream edge. Which sampling arrangement best shows the gradient, and what else should you measure?

    Show the answer

    Use a transect from the path to the stream with quadrats at consistent intervals, and measure soil moisture at each point. Replicate transects to check that the pattern is not unique to one line.

  • Core

    Scope: Core · Topic B7, PAG 4 Rates of reaction

    Open revision guidance

    What to know

    • PAG 4 includes safe heating devices (Bunsen burner, water bath or electric heater) and measuring rates by suitable methods such as gas production, water uptake or an indicator colour change. OCR lists enzyme, photosynthesis, respiration and yeast-fermentation contexts elsewhere in the specification.
    • Rate is change in measured quantity divided by elapsed time. Select a method that produces a measurable signal and compare trials with the same start point, volumes and sampling intervals.

    What to do in an assessment

    • For gas production, record volume at equal time intervals; for an initial rate, calculate the gradient near time zero. If 18 cm³ is produced in 3 minutes, mean rate = 6 cm³ min⁻¹.
    • Control temperature, pH, substrate concentration, organism/enzyme amount and apparatus leakage as relevant. Repeat, identify anomalies using a stated reason, and compare means or graph shapes.

    In plain language

    A rate is not just the final amount. It tells how quickly the amount changes. Use equal intervals and a reliable signal, and keep conditions constant so a rate difference can be attributed to the factor being tested.

    Self-check

    An enzyme reaction produces 12 cm³ gas in 40 seconds. What is its mean rate, and what additional data would help estimate its initial rate?

    Show the answer

    12 ÷ 40 = 0.30 cm³ s⁻¹. Record several gas volumes at short, equal time intervals near the start and use the gradient of that early section.

  • Core

    Scope: Core · Topic B7, PAG 5 Photosynthesis

    Open revision guidance

    What to know

    • PAG 5 covers appropriate apparatus and measurement of biological processes, safe and ethical use of plants or animals to measure physiological responses, rate measurement through gas production/water uptake/indicator colour change, safe heating, and accurate length, area, mass, time, temperature, volume and pH measurements.
    • A pondweed oxygen-volume method can test light intensity, but lamp distance changes both light and potentially temperature; measure or control temperature and keep carbon dioxide, plant length and time constant.

    What to do in an assessment

    • Allow the specimen to acclimatise, vary one independent factor over a sensible range, measure oxygen volume over the same time, repeat at each level and plot mean rate against the factor.
    • Change lamp distance using a measured scale. If light intensity is estimated as proportional to 1/distance², state that this is a model and avoid claiming light alone explains a plateau when another factor may limit.

    In plain language

    To find what controls photosynthesis, change one condition at a time and count oxygen made in a fixed period. If the rate stops rising, another resource such as carbon dioxide or temperature may now be limiting.

    Self-check

    At 20 cm a pondweed produces 10 units of oxygen per minute; at 10 cm it produces 16, not 40. Give a sound interpretation.

    Show the answer

    The rate rises when the lamp is closer, so light may have been limiting. It does not follow the simple inverse-square expectation exactly; another limiting factor, heating, or measurement variation could explain the smaller increase.

  • Core

    Scope: Core · Topic B7, PAG 6 Physiology, responses and respiration

    Open revision guidance

    What to know

    • PAG 6 requires safe and ethical use of organisms to measure physiological response and safe use of suitable heating devices. OCR gives pulse, ventilation and recovery after exercise as an example; no learner should be pushed beyond safe limits.
    • A response changes with workload and recovery time. Standardise the exercise, rest period, counting interval and posture, and account for fitness and individual differences.

    What to do in an assessment

    • Measure resting pulse, perform a safe standard activity, measure pulse immediately and at regular recovery intervals, then plot pulse against time. Repeat the same protocol or compare participants only with appropriate consent and risk controls.
    • A recovery time can be estimated from the graph where pulse returns close to baseline; explain the chosen criterion instead of calling one noisy reading 'recovered'.

    In plain language

    Exercise increases oxygen demand, so pulse and ventilation rise. Their return toward resting values can be measured over time; fair comparison needs the same workload and careful attention to safety.

    Self-check

    Why should the exercise and the time of pulse measurement be standardised when comparing recovery?

    Show the answer

    Different workloads and measurement times change the response, so they would confound the comparison. A common protocol makes recovery patterns more fairly comparable.

  • Core

    Scope: Core · Topic B7, PAG 7 Microbiological techniques

    Open revision guidance

    What to know

    • PAG 7 includes observing and measuring biological change, using magnification/microscopes and labelled drawings, safe heating apparatus, and accurate measurement of length, area, mass, time, temperature, volume and pH. Its example is testing antimicrobial agents against a bacterial lawn.
    • Aseptic technique reduces contamination and exposure: disinfect surfaces, use sterile equipment and keep culture containers closed except for the shortest necessary handling. Follow the centre's approved risk assessment and disposal procedure.

    What to do in an assessment

    • Compare agents using equal inoculum, agar, disc size, placement and incubation conditions; include an appropriate control. Measure the diameter of each clear inhibition zone in millimetres and repeat.
    • A larger clear zone suggests greater inhibition under those test conditions, not necessarily a better medicine in a patient; diffusion through agar and concentration also affect the zone.

    In plain language

    A clear area around an antimicrobial disc shows that visible bacterial growth was inhibited there. Fair comparisons need equal conditions, contamination control and careful measurement; the plate is not a direct model of treatment inside a person.

    Self-check

    Why is measuring the clear-zone diameter not enough to prove one antibiotic will treat an infection better in a patient?

    Show the answer

    Zone size also depends on concentration and diffusion through agar. A plate test does not account for safe dose, absorption, the patient's body or clinical outcomes.

  • Core

    Scope: Core · Topic B7, PAG 8 Transport in and out of cells

    Open revision guidance

    What to know

    • PAG 8 requires apparatus and techniques for observing and measuring biological processes and accurate measurements of length, area, mass, time, temperature, liquid/gas volume and pH. OCR suggests potato-chip mass or length changes in solutions of different water potentials.
    • Water moves by osmosis across partially permeable cell membranes. A plant tissue piece may gain mass in a dilute solution and lose mass in a concentrated one; the concentration giving no net change estimates the isotonic point for the tissue.

    What to do in an assessment

    • Cut equal-size chips, blot and record starting mass, immerse each in a labelled measured solution for a fixed time and temperature, blot consistently and reweigh. Repeat concentrations and plot mean percentage mass change against solution concentration.
    • Calculate (final mass − initial mass) ÷ initial mass × 100%. A line crossing zero identifies the approximate no-net-mass-change concentration; uncertainty in the crossing means report an estimate, not an exact cell concentration.

    In plain language

    A potato chip changing mass gives indirect evidence about water moving into or out of cells. Keep the chips and timing alike, then compare percentage changes so different starting masses do not distort the result.

    Self-check

    A chip changes from 3.00 g to 3.30 g. What is its percentage mass change and what does the positive sign suggest?

    Show the answer

    (3.30 − 3.00) ÷ 3.00 × 100 = +10%. The tissue gained mass, consistent with net water entering its cells.

Topic group

B1.1 Cell structures

3 revision points
  • Core

    Scope: Core · §2c B1.1a

    Open revision guidance

    What to know

    • A light microscope uses an eyepiece and objective lenses, a stage and illumination to magnify a prepared slide. A thin specimen lets light pass through; a cover slip holds it flat and limits movement.
    • Stains add contrast to colourless cells or highlight particular structures/tissues. Magnification = image size ÷ actual size; both lengths must first use the same units.

    What to do in an assessment

    • Focus at low power first, then increase magnification and refocus. Record a labelled drawing from what is visible, not from an assumed textbook image.
    • For magnification, convert (for example) mm to µm before dividing; magnification has no unit.

    In plain language

    A microscope makes small cells visible; a stain improves contrast. A magnification answer is a ratio, so image and real sizes need matching units.

    Self-check

    An image is 6 mm long and the cell is 30 µm long. What is magnification?

    Show the answer

    6 mm = 6000 µm; 6000 ÷ 30 = ×200.

  • Core

    Scope: Core · §2c B1.1b

    Open revision guidance

    What to know

    • Eukaryotic animal and plant cells have a nucleus containing chromosomes/genes, mitochondria with respiration enzymes, ribosomes for protein synthesis and a cell membrane with receptors that selectively controls exchange.
    • Plant cells additionally have chloroplasts containing chlorophyll and a cellulose wall. Prokaryotic bacteria lack a nucleus; their genetic material includes a circular chromosome and may include plasmids. Their membrane and ribosomes perform cellular functions.

    What to do in an assessment

    • Link each named structure to its function and distinguish prokaryote from eukaryote using the location/form of genetic material, not cell size alone.

    In plain language

    Cell parts have different jobs. Plants have additional structures for support and photosynthesis; bacterial DNA is not enclosed in a nucleus.

    Self-check

    Which two structures enable a plant cell to photosynthesise and resist bursting?

    Show the answer

    Chloroplasts contain chlorophyll to absorb light; the cellulose cell wall supports the cell and resists expansion.

  • Core

    Scope: Core · §2c B1.1c

    Open revision guidance

    What to know

    • A transmission electron microscope uses electrons rather than visible light and can resolve much smaller, closely spaced structures. Higher resolution let biologists distinguish and study sub-cellular structures beyond the useful resolution of light microscopes.
    • Micrographs are evidence of visible structures; magnification and resolution are different: magnification enlarges an image, while resolution separates nearby detail.

    What to do in an assessment

    • Compare equivalent views by naming the extra structures resolved in the electron micrograph; do not claim every electron micrograph is a larger magnification.

    In plain language

    Electron microscopes revealed cell detail that light microscopes could not distinguish because their resolving power is lower.

    Self-check

    How did electron microscopes improve knowledge of cells?

    Show the answer

    Their greater resolving power makes much smaller, closely spaced sub-cellular structures distinguishable.

Topic group

B1.2 DNA and enzymes

7 revision points
  • Core

    Scope: Core · §2c B1.2a

    Open revision guidance

    What to know

    • DNA is a large polymer: a long molecule built by joining many smaller nucleotide monomers. Each nucleotide has a sugar, a phosphate group and one nitrogen-containing base.
    • Do not describe DNA itself as a protein or as a sugar; the repeated nucleotide units form a different kind of biological molecule.

    What to do in an assessment

    • When asked how a polymer is built, identify the repeating nucleotide monomers rather than naming DNA's coded products.

    In plain language

    DNA is a long chain made from many repeating nucleotide building blocks.

    Self-check

    What is the monomer unit of DNA?

    Show the answer

    A nucleotide, containing a sugar, phosphate group and base.

  • Core

    Scope: Core · §2c B1.2b

    Open revision guidance

    What to know

    • DNA consists of two nucleotide strands twisted around one another as a double helix. The sugar–phosphate backbone is on the outside and bases face inward.
    • The paired strands are complementary, so the sequence on one strand determines the matching sequence on the other.

    What to do in an assessment

    • In a model or diagram, show two twisted strands and paired bases inside; do not draw a single strand or place the backbone in the centre.

    In plain language

    DNA looks like a twisted ladder: two outer backbones and paired bases forming the rungs.

    Self-check

    What overall shape do the two DNA strands form?

    Show the answer

    A double helix.

  • Core

    Scope: Core · §2c B1.2c

    Open revision guidance

    What to know

    • DNA uses four nucleotide types, distinguished by their bases. Adenine pairs with thymine (A–T); cytosine pairs with guanine (C–G). Each nucleotide also contains a sugar and phosphate group.
    • The base order stores information. Complementarity lets the sequence on one strand specify the order on its partner.

    What to do in an assessment

    • Complete a DNA sequence by pairing A with T and C with G; count bases carefully and preserve sequence length.

    In plain language

    Four base letters form matching pairs: A with T, and C with G.

    Self-check

    What complementary strand pairs with A-C-G-T?

    Show the answer

    T-G-C-A.

  • Higher

    Scope: Higher · §2c B1.2d (Higher only)

    Open revision guidance

    What to know

    • During transcription, the DNA around a gene unzips and a complementary messenger-RNA copy is made in the nucleus. mRNA carries that coded sequence to a ribosome in the cytoplasm.
    • During translation, the ribosome reads mRNA codons; transfer RNA brings the corresponding amino acids, which are joined in the coded order to form a protein.

    What to do in an assessment

    • Keep the stages and locations distinct: DNA to mRNA in the nucleus; mRNA sequence to amino-acid sequence at a cytoplasmic ribosome.

    In plain language

    A gene is copied into mRNA, then the mRNA instructions are used to assemble a protein.

    Self-check

    Where does transcription occur, and what does it produce?

    Show the answer

    In the nucleus; it produces a complementary mRNA copy of the gene.

  • Higher

    Scope: Higher · §2c B1.2e (Higher only)

    Open revision guidance

    What to know

    • A gene's base sequence is read in triplets: each three-base codon on mRNA corresponds to an amino acid or a stop signal. The codon order therefore determines the order of amino acids in a protein, and that amino-acid sequence determines how the protein folds and its resulting shape and function.
    • A changed base may change a codon and an amino acid, potentially altering a protein's shape; the effect depends on the change and protein.

    What to do in an assessment

    • Explain the chain of cause: DNA base order → triplet codons → amino-acid order → protein shape → function. Avoid claiming every mutation changes a protein or phenotype.

    In plain language

    The order of DNA bases is read in triplets that specify amino acids; their order helps determine the protein's shape and job.

    Self-check

    How could a changed base in a gene affect an enzyme?

    Show the answer

    It may alter a triplet codon and amino acid, changing the enzyme's folding and active-site shape so substrate binding or catalysis changes.

  • Core

    Scope: Core · §2c B1.2f

    Open revision guidance

    What to know

    • An enzyme investigation measures product made or substrate remaining over time, or compares reaction time under controlled conditions. Suitable endpoints include starch disappearance with iodine or gas/colour change, depending on the reaction.
    • A fair comparison changes one factor, controls temperature, pH, volumes and concentrations, repeats trials, then compares rates rather than final amounts alone.

    What to do in an assessment

    • For a fixed amount of substrate, rate can be estimated as amount changed ÷ time; for time to a fixed endpoint, a shorter time means a faster reaction. Plot suitable numerical results and identify anomalies.

    In plain language

    Measure how quickly an enzyme changes its substrate, changing one condition at a time and keeping the rest fair.

    Self-check

    A reaction reaches the same endpoint in 20 s at one temperature and 40 s at another. Which was faster?

    Show the answer

    The 20 s reaction; for a fixed endpoint, rate is proportional to 1/time, so it was about twice as fast.

  • Core

    Scope: Core · §2c B1.2g

    Open revision guidance

    What to know

    • Enzymes catalyse metabolic reactions. A substrate binds at a specific active site to form an enzyme–substrate complex; products leave and the enzyme can be used again. This is the lock-and-key model of specificity.
    • Rate depends on temperature, pH, substrate concentration and enzyme concentration. Higher substrate concentration increases successful collisions until active sites are saturated; extreme pH or temperature can change active-site shape.

    What to do in an assessment

    • On a rate graph, explain an increase through more successful collisions, a plateau through saturation/another limitation, and loss of activity at harsh conditions through altered enzyme shape.

    In plain language

    An enzyme's active site fits particular substrates. Conditions affect collision frequency and whether that shape still works.

    Self-check

    Why does adding more substrate eventually stop increasing rate?

    Show the answer

    At high concentration, enzyme active sites are occupied most of the time; enzyme concentration becomes limiting.

Topic group

B1.3 Respiration

6 revision points
  • Core

    Scope: Core · §2c B1.3a

    Open revision guidance

    What to know

    • Cellular respiration is a universal chemical process that occurs continuously in living cells. It transfers energy from fuel molecules to ATP, the immediate energy source for cell processes.
    • Respiration is not the same as breathing/ventilation: cells respire; ventilation moves air into and out of lungs.

    What to do in an assessment

    • When asked why organisms respire, connect ATP to energy-requiring processes such as synthesis, active transport, movement and maintaining conditions.

    In plain language

    Every living cell releases usable energy through respiration and transfers it to ATP.

    Self-check

    Does a plant cell respire at night?

    Show the answer

    Yes. Respiration occurs continuously in living plant cells; photosynthesis needs light, respiration does not.

  • Core

    Scope: Core · §2c B1.3b

    Open revision guidance

    What to know

    • Respiration is exothermic: the reaction transfers energy to its surroundings as well as making energy available for cellular work. The energy transfer can be detected as warming in a suitable demonstration.
    • Energy is not matter and is not 'made'; chemical energy in the reactants is transferred and some becomes less useful thermal energy.

    What to do in an assessment

    • Use 'energy is released/transferred' rather than saying respiration creates energy; distinguish exothermic energy transfer from the amount conserved.

    In plain language

    Respiration transfers chemical energy out of fuel molecules; some warms the surroundings.

    Self-check

    What observation could provide evidence that a respiration-related reaction is exothermic?

    Show the answer

    A measured temperature rise in the surroundings, compared with a suitable control.

  • Core

    Scope: Core · §2c B1.3c

    Open revision guidance

    What to know

    • Glucose is the respiratory substrate in the aerobic and anaerobic processes compared here. Aerobic respiration uses glucose and oxygen, producing carbon dioxide and water with a high ATP yield; anaerobic respiration breaks down glucose without oxygen and yields less ATP.
    • In animal muscle, anaerobic respiration produces lactate. In yeast and plants, fermentation uses glucose and produces ethanol and carbon dioxide. Compare conditions, substrates, products and relative ATP yield; do not assume all organisms have identical anaerobic products.

    What to do in an assessment

    • Use word equations to compare substrate and products: glucose + oxygen → carbon dioxide + water; glucose → lactate in animal muscle; glucose → ethanol + carbon dioxide in yeast/plant fermentation. State oxygen availability and relative ATP yield.

    In plain language

    Both pathways use glucose, but aerobic respiration also uses oxygen and yields more ATP; anaerobic products depend on the organism.

    Self-check

    What substrate is used in anaerobic respiration, and how do the products compare in muscle and yeast?

    Show the answer

    Both use glucose; muscle produces lactate, while yeast produces ethanol and carbon dioxide.

  • Core

    Scope: Core · §2c B1.3d

    Open revision guidance

    What to know

    • Simple sugars are carbohydrate monomers. They can be joined to form larger carbohydrate polymers such as starch or glycogen for storage, or broken down by hydrolysis into smaller sugar units.
    • In respiration, glucose is a substrate that is broken down in a sequence of reactions; synthesis joins monomers while breakdown separates them.

    What to do in an assessment

    • Use 'monomer' for a small building unit and 'polymer' for a chain of many units; identify whether a described reaction builds or breaks a carbohydrate.

    In plain language

    Cells can join sugars into larger carbohydrates or split them apart; glucose can also be used as respiratory fuel.

    Self-check

    Is starch a monomer or a polymer of glucose units?

    Show the answer

    A polymer; it contains many linked glucose monomers.

  • Core

    Scope: Core · §2c B1.3e

    Open revision guidance

    What to know

    • Amino acids are the monomers used to build protein polymers. Joining amino acids makes a protein; breaking proteins down releases amino acids that can be reused to synthesise proteins.
    • The order and properties of amino acids help determine a protein's final shape and function.

    What to do in an assessment

    • In a digestion or cell-synthesis question, distinguish protease breakdown to amino acids from protein synthesis by joining amino acids.

    In plain language

    Proteins are built from amino-acid units and can be broken down back into those units.

    Self-check

    What are the monomers of proteins?

    Show the answer

    Amino acids.

  • Core

    Scope: Core · §2c B1.3f

    Open revision guidance

    What to know

    • Lipids are assembled from glycerol and fatty acids and can be broken down to release these component molecules. Lipase catalyses lipid digestion into fatty acids and glycerol.
    • The components can be reused in metabolism to build lipids; lipids also serve as energy stores and membrane components.

    What to do in an assessment

    • When asked for lipid digestion products, name both fatty acids and glycerol; do not confuse them with amino acids or sugars.

    In plain language

    A lipid can be split into glycerol and fatty acids, then its components reused to build lipids.

    Self-check

    Which two products are formed when lipase digests a lipid?

    Show the answer

    Fatty acids and glycerol.

Topic group

B1.4 Photosynthesis

6 revision points
  • Core

    Scope: Core · §2c B1.4a

    Open revision guidance

    What to know

    • Photosynthetic organisms, including green plants and algae, are primary producers: they use light energy to make organic food molecules from inorganic raw materials.
    • Their biomass supplies food to consumers and underpins food chains, so producer productivity supports biomass across ecosystems.

    What to do in an assessment

    • Trace a food chain from a producer; distinguish the producer's photosynthesised biomass from energy transferred between trophic levels.

    In plain language

    Plants and algae make the food biomass that supports most ecosystem food chains.

    Self-check

    Why are green plants described as producers?

    Show the answer

    They make organic food from carbon dioxide and water using light energy, supplying biomass to the rest of a food chain.

  • Core

    Scope: Core · §2c B1.4b

    Open revision guidance

    What to know

    • Photosynthesis is a two-stage process in chloroplasts. In the light-dependent stage, chlorophyll absorbs light energy and water is split, releasing oxygen. In the light-independent stage, that captured energy helps combine carbon dioxide into carbohydrate.
    • Word equation: carbon dioxide + water → glucose + oxygen (light and chlorophyll are required). The equation summarises reactants/products, not the intermediate reactions.

    What to do in an assessment

    • Label reactants, products, chloroplast location and the light/chlorophyll requirement; describe the light-dependent and light-independent stages without adding unrequired molecular detail; balance symbol equations only when requested.

    In plain language

    Chloroplasts use light energy to turn carbon dioxide and water into glucose, releasing oxygen.

    Self-check

    Name the two reactants in photosynthesis.

    Show the answer

    Carbon dioxide and water.

  • Core

    Scope: Core · §2c B1.4c

    Open revision guidance

    What to know

    • Photosynthesis is endothermic because it takes in energy from the surroundings, mainly light energy, to drive formation of energy-rich organic molecules.
    • The energy transferred becomes stored as chemical energy in products such as glucose; the plant does not create energy.

    What to do in an assessment

    • Contrast an endothermic process (energy enters the reacting system) with an exothermic process (energy transferred out); identify photosynthesis as the former.

    In plain language

    Photosynthesis absorbs light energy and stores some of it in the chemical bonds of sugars.

    Self-check

    Is photosynthesis endothermic or exothermic?

    Show the answer

    Endothermic: it absorbs energy from light.

  • Core

    Scope: Core · §2c B1.4d

    Open revision guidance

    What to know

    • Experiments can test photosynthesis by measuring oxygen production or testing leaves for starch. To test whether light is needed, destarch a plant first, cover part of a leaf, expose it to light, then decolourise and add iodine; illuminated regions containing starch turn blue-black.
    • Control plant species, exposure time, temperature, carbon dioxide and light treatment as appropriate; repeat or compare matched leaves.

    What to do in an assessment

    • Explain why destarching removes stored starch as a confounder and why an uncovered region or dark control is useful. Follow safe practical instructions for hot ethanol; never heat it directly over a flame.

    In plain language

    Remove stored starch first, change light exposure, then test whether the leaf made new starch.

    Self-check

    Why destarch a plant before testing whether light is required?

    Show the answer

    To use up starch already stored before the investigation, so starch detected afterward is evidence made during the test.

  • Core

    Scope: Core · §2c B1.4e

    Open revision guidance

    What to know

    • Light intensity, carbon-dioxide concentration and temperature affect photosynthesis rate. A low supply of one can limit the rate; once another factor limits, adding more of the first gives little further increase.
    • Rate is measured as product formed or reactant used per unit time. For a point light source, intensity is approximately proportional to 1/distance², so doubling distance gives about one-quarter intensity.

    What to do in an assessment

    • Calculate a rate as change ÷ time with units; read curve slope/plateau and keep other conditions controlled while changing one factor.

    In plain language

    The rate rises when a scarce requirement is increased, until another requirement or temperature-controlled step becomes limiting.

    Self-check

    If lamp distance doubles, approximately what fraction of its original intensity reaches the plant?

    Show the answer

    One quarter, because inverse-square intensity varies as 1/distance².

  • Higher

    Scope: Higher · §2c B1.4f (Higher only)

    Open revision guidance

    What to know

    • Light intensity, carbon-dioxide concentration and temperature interact in limiting photosynthesis rate. On a response curve, the factor increased may cease to limit once its curve plateaus; another resource or the temperature-dependent reactions then constrains rate.
    • A graph at several temperatures can show temperature changing which light or carbon-dioxide level is limiting. Infer the limiting factor from the curve's response, not from its identity alone.

    What to do in an assessment

    • Compare curves at the same setting of the other factors; cite the region/slope/plateau as evidence, then name the factor that would raise rate there.

    In plain language

    More of one requirement only helps while that requirement is the bottleneck; the bottleneck can change across conditions.

    Self-check

    A photosynthesis curve is flat as light rises, but increasing carbon dioxide raises the plateau. What limited the original plateau?

    Show the answer

    Carbon dioxide was limiting at the plateau; extra light alone could not raise the rate.

Topic group

B2.1 Supplying the cell

6 revision points
  • Core

    Scope: Core · §2c B2.1a

    Open revision guidance

    What to know

    • Diffusion is net movement of particles from higher to lower concentration. Osmosis is net water movement through a partially permeable membrane from higher water potential (more dilute) to lower water potential (more concentrated).
    • Active transport moves a substance against its concentration gradient using energy from respiration and membrane transport proteins. Examples include mineral-ion uptake by roots and glucose absorption.

    What to do in an assessment

    • For each process name the substance, direction, membrane and gradient; use water-potential language for osmosis without calculating water potential. Percentage mass change = change in mass ÷ initial mass × 100.

    In plain language

    Diffusion moves particles down a concentration gradient; osmosis does this for water across a partly permeable membrane; active transport uses energy to move against a gradient.

    Self-check

    How can a root cell take up mineral ions when their concentration is lower in the soil?

    Show the answer

    By active transport using energy and membrane transport proteins, against the concentration gradient.

  • Core

    Scope: Core · §2c B2.1b

    Open revision guidance

    What to know

    • In the cell cycle, a cell grows, copies its DNA, grows further and then divides. During mitosis, replicated chromosomes are moved apart so each new nucleus receives one copy of each chromosome; the cell then divides.
    • Mitosis produces two genetically identical daughter cells with the same chromosome number as the parent, enabling growth and repair.

    What to do in an assessment

    • Order growth → DNA replication → chromosome separation/mitosis → cell division; distinguish chromosome copying from chromosome separation.

    In plain language

    A cell copies its DNA and divides once to make two genetically matching cells.

    Self-check

    How many daughter cells does one mitotic division produce?

    Show the answer

    Two genetically identical daughter cells.

  • Core

    Scope: Core · §2c B2.1c

    Open revision guidance

    What to know

    • Differentiation is the process by which a cell changes to become specialised for a particular function. Specialised cells allow multicellular organisms to perform different tasks efficiently and form tissues and organs.
    • Examples include a red blood cell specialised for oxygen transport, a neurone for signalling and a root-hair cell for absorption.

    What to do in an assessment

    • For an example, link a specific cell feature to its job, then explain how specialisation supports the organism rather than only naming the cell.

    In plain language

    Cells become different types so each can do a particular job well.

    Self-check

    How does differentiation help a multicellular organism?

    Show the answer

    It produces specialised cell types that perform tasks efficiently and can be organised into tissues and organs.

  • Core

    Scope: Core · §2c B2.1d

    Open revision guidance

    What to know

    • Stem cells are unspecialised cells that can divide and differentiate. In animals they are found in embryos and in some adult tissues; in plants, meristems contain cells that continue dividing.
    • Location matters: embryonic stem cells and adult stem cells differ in the range of cell types they can form.

    What to do in an assessment

    • Name both animal locations and plant meristems when asked where stem cells occur; do not imply that all adult cells can become any cell type.

    In plain language

    Embryos and some adult animal tissues contain stem cells; growing regions called meristems do so in plants.

    Self-check

    Where are stem cells found in plants?

    Show the answer

    In meristems, regions such as root and shoot tips where cells divide for growth.

  • Core

    Scope: Core · §2c B2.1e

    Open revision guidance

    What to know

    • Embryonic animal stem cells can divide and differentiate into a wide range of cell types during development. Adult animal stem cells can replace or repair a more limited set of cells in particular tissues.
    • Plant meristem cells divide and differentiate to produce cells for continued growth. Stem-cell therapies may replace damaged cells, but suitability, rejection, infection and ethical issues require careful evaluation.

    What to do in an assessment

    • Match stem-cell type to development, tissue repair or plant growth; distinguish potential benefits from practical and ethical limitations.

    In plain language

    Stem cells make new cells for development, repair and plant growth, with different types able to form different ranges of tissue.

    Self-check

    What is one role of adult animal stem cells?

    Show the answer

    They divide and differentiate to replace or repair cells in particular tissues.

  • Core

    Scope: Core · §2c B2.1f

    Open revision guidance

    What to know

    • Embryonic stem cells can differentiate into many body cell types; adult stem cells are usually more restricted to a narrower group of related types. Both can divide, but their sources and developmental potential differ.
    • Use of embryonic cells raises ethical questions because obtaining them involves embryo destruction; adult cells avoid that issue but may not provide the same range or quantity.

    What to do in an assessment

    • Compare source, range of possible cell types and ethical/practical issues; avoid describing adult stem cells as wholly unable to differentiate.

    In plain language

    Embryonic stem cells can form a broader range of cells; adult stem cells are more specialised in what they can make.

    Self-check

    Which type generally has a wider differentiation potential?

    Show the answer

    Embryonic stem cells.

Topic group

B2.2 Challenges of size

10 revision points
  • Core

    Scope: Core · §2c B2.2a

    Open revision guidance

    What to know

    • As an organism grows, volume increases faster than surface area, so surface-area-to-volume ratio falls and diffusion distances to internal cells increase. Large multicellular organisms therefore need specialised exchange surfaces and transport systems.
    • For a cube of side a: surface area = 6a², volume = a³, so SA:V = 6/a. A 1 cm cube has 6 cm⁻¹; a 2 cm cube has 3 cm⁻¹.

    What to do in an assessment

    • Calculate surface area and volume in consistent units before dividing; explain why a lower ratio and longer path make diffusion alone insufficient.

    In plain language

    Large organisms have less surface relative to their volume, so they need specialised surfaces and internal transport.

    Self-check

    What is the SA:V ratio of a cube with side 3 cm?

    Show the answer

    SA = 6×9 = 54 cm²; volume = 27 cm³; ratio = 54:27 = 2:1 (2 cm⁻¹).

  • Core

    Scope: Core · §2c B2.2b

    Open revision guidance

    What to know

    • Organisms exchange oxygen and carbon dioxide for respiration/photosynthesis, water, dissolved food molecules, mineral ions and waste such as urea. The substance and direction depend on the organism's needs and its environment.
    • In animals, blood transports dissolved nutrients, urea and gases; plants move water/mineral ions in xylem and sugars in phloem.

    What to do in an assessment

    • For each unfamiliar organism, state what is transported, where it enters/leaves and what process or function requires it; do not assume all organisms exchange the same set.

    In plain language

    Transport systems move useful raw materials to cells and carry products or wastes away.

    Self-check

    Name one waste transported in human blood to an excretory organ.

    Show the answer

    Urea, carried to the kidneys for removal in urine.

  • Core

    Scope: Core · §2c B2.2c

    Open revision guidance

    What to know

    • Humans have a double circulatory system: one loop carries blood heart↔lungs for gas exchange and another carries blood heart↔body. Blood passes through the heart twice per complete circuit.
    • The pulmonary circuit links heart and lungs; the systemic circuit links heart and tissues. Vessel arrangement connects these loops so oxygen uptake at lungs supports delivery to cells.

    What to do in an assessment

    • Trace the route in order: body → vena cava → right heart → pulmonary artery → lungs → pulmonary vein → left heart → aorta → body; identify pulmonary vessels by route, not oxygen content.

    In plain language

    Blood travels in two connected loops, through the heart between the lungs and body.

    Self-check

    Why is it called a double circulation?

    Show the answer

    Blood passes through the heart twice in one complete journey around both the pulmonary and systemic circuits.

  • Core

    Scope: Core · §2c B2.2d

    Open revision guidance

    What to know

    • The heart has a right and left atrium and ventricle. The vena cava enters the right atrium; the pulmonary artery leaves the right ventricle; the pulmonary vein enters the left atrium; the aorta leaves the left ventricle. The tricuspid valve lies between the right atrium and ventricle, the bicuspid (mitral) valve between the left atrium and ventricle, and the pulmonary and aortic semilunar valves guard the ventricular exits.
    • Arteries have thick elastic/muscular walls and a relatively narrow lumen for high pressure; veins have wider lumens and valves to aid return; capillaries have very thin walls and narrow lumens for exchange. Cardiac muscle contracts to generate pressure.

    What to do in an assessment

    • Trace and label the named chambers, valves and vessels in blood-flow order; explain each vessel feature in relation to pressure, flow or exchange.

    In plain language

    The named heart chambers, valves and vessels direct blood one way; vessel wall and lumen features fit pressure and exchange.

    Self-check

    Which vessel carries blood from the right ventricle to the lungs?

    Show the answer

    The pulmonary artery.

  • Core

    Scope: Core · §2c B2.2e

    Open revision guidance

    What to know

    • Red blood cells contain haemoglobin that binds oxygen; their biconcave shape gives a large surface area and they lack a nucleus, leaving room for haemoglobin. They transport oxygen from lungs to tissues.
    • Plasma is the liquid part of blood; it carries dissolved nutrients, hormones, carbon dioxide, urea and heat, as well as blood cells and platelets.

    What to do in an assessment

    • Match each transported substance to its carrier and direction; distinguish oxygen carried mainly by haemoglobin from dissolved substances carried in plasma.

    In plain language

    Red cells carry most oxygen using haemoglobin; plasma transports many dissolved materials around the body.

    Self-check

    Which blood component carries urea from cells to the kidneys?

    Show the answer

    Plasma, with urea dissolved in it.

  • Core

    Scope: Core · §2c B2.2f

    Open revision guidance

    What to know

    • Root-hair cells are extensions of root epidermal cells that greatly increase contact area with soil water. Water enters by osmosis down a water-potential gradient; mineral ions are absorbed, including by active transport when their concentration is lower in soil.
    • A thin extension gives a large exchange area and short path into the root; mitochondria provide energy for active ion uptake.

    What to do in an assessment

    • Explain water and mineral-ion movement separately; connect the hair-like shape to surface area and the uptake mechanism to the gradient.

    In plain language

    Root hairs expose a large area to soil; they take in water by osmosis and mineral ions by transport across membranes.

    Self-check

    How can roots absorb a mineral ion against its concentration gradient?

    Show the answer

    Root cells use active transport, powered by respiration, through membrane transport proteins.

  • Core

    Scope: Core · §2c B2.2g

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    What to know

    • Transpiration is water loss from leaves, mainly by evaporation from mesophyll and diffusion of water vapour through stomata. Water uptake and evaporation create a pull through xylem.
    • Translocation is movement of dissolved sugars such as sucrose in phloem between sources and sinks; stomata are pores whose guard cells regulate gas exchange and water loss.

    What to do in an assessment

    • Do not confuse transpiration (water vapour loss) with translocation (sugar transport). Predict how opening stomata affects gas entry and water loss.

    In plain language

    Transpiration moves water through the plant and out of leaves; translocation moves dissolved food in phloem.

    Self-check

    Which process carries sucrose from a leaf to a growing root?

    Show the answer

    Translocation through phloem.

  • Core

    Scope: Core · §2c B2.2h

    Open revision guidance

    What to know

    • Xylem vessels are dead, hollow tubes with no end walls and lignified walls that resist collapse; they carry water and mineral ions mainly upward from roots.
    • Phloem sieve tubes transport dissolved sugars between sources and sinks. Sieve plates connect sieve-tube elements; companion cells support transport and metabolism.

    What to do in an assessment

    • Identify tissue from its material and direction/function; link xylem lignin to strength and hollow tubes to continuous water flow.

    In plain language

    Xylem is a reinforced water pipeline; phloem is living sugar-transport tissue linking sources with places that use or store sugar.

    Self-check

    Which tissue transports dissolved sucrose?

    Show the answer

    Phloem.

  • Core

    Scope: Core · §2c B2.2i

    Open revision guidance

    What to know

    • Light intensity, air movement and temperature affect water uptake/transpiration. More light tends to open stomata; moving air removes humid boundary-layer air; warmth increases evaporation, so each can increase water loss and water uptake if other factors are controlled.
    • High humidity or low light can reduce the water-potential/evaporation gradient; factor effects can interact.

    What to do in an assessment

    • In a comparison, state the predicted direction and mechanism, then identify the other conditions that must stay constant.

    In plain language

    Light, wind and warmth can increase water loss from leaves, pulling more water through the plant.

    Self-check

    Why can moving air increase transpiration?

    Show the answer

    It removes moist air near the leaf, maintaining a steep water-vapour gradient from inside to outside.

  • Core

    Scope: Core · §2c B2.2j

    Open revision guidance

    What to know

    • A simple potometer tracks movement of an air bubble in a capillary as a plant shoot takes up water; distance × capillary cross-sectional area gives volume, and uptake rate = volume ÷ time. It estimates water uptake, not transpiration exactly, because some absorbed water is retained or used.
    • Change one condition (light, air movement or temperature), keep shoot area/time and other factors controlled, allow acclimatisation, repeat and calculate a mean. For tissue, percentage mass change = (final − initial) ÷ initial × 100.

    What to do in an assessment

    • Read bubble displacement against the scale and time it; state units such as mm³ min⁻¹. Explain how to reset the bubble and control leaks/conditions.

    In plain language

    A potometer estimates water uptake by measuring how far a bubble moves in a known time.

    Self-check

    A bubble moves 12 mm in 3 minutes. What is its mean displacement rate?

    Show the answer

    12 ÷ 3 = 4 mm min⁻¹; convert to volume rate only if the capillary area is known.

Topic group

B3.1 Nervous coordination

8 revision points
  • Core

    Scope: Core · §2c B3.1a

    Open revision guidance

    What to know

    • The CNS is the brain and spinal cord. Sensory neurones carry impulses from receptors to CNS; relay neurones connect cells within CNS; motor neurones carry impulses to effectors such as muscles or glands.
    • Sensory and motor neurones have elongated fibres and a cell body; a sensory neurone's cell body lies along its fibre, while a motor neurone's cell body is in the CNS and its long axon reaches an effector. Myelin insulates many axons. These structures help carry impulses over distance.
    • Receptors detect stimuli. A synapse is a junction between neurones where chemical transmitter carries a signal across a gap.

    What to do in an assessment

    • Trace receptor → sensory neurone → CNS/relay → motor neurone → effector; distinguish a neurone from a nerve bundle and relate the neurone's long fibre to signal transmission.

    In plain language

    Receptors detect change, neurones carry signals, and effectors make the response.

    Self-check

    Which neurone carries an impulse from CNS to a muscle?

    Show the answer

    A motor neurone.

  • Core

    Scope: Core · §2c B3.1b

    Open revision guidance

    What to know

    • Receptors throughout the body provide information; CNS connections combine it and coordinate a suitable response by signalling effectors. Sensory, relay and motor neurones link detection to action.

    What to do in an assessment

    • Explain the full route from stimulus to response and state how CNS integration coordinates the action.

    In plain language

    The CNS receives information, processes it and sends a response to the body part that needs to act.

    Self-check

    What carries out the response after a motor impulse arrives?

    Show the answer

    An effector, such as a muscle or gland.

  • Core

    Scope: Core · §2c B3.1c

    Open revision guidance

    What to know

    • A rapid automatic reflex pathway is stimulus → receptor → sensory neurone → relay neurone in CNS → motor neurone → effector. Synapses pass the signal; a deliberate conscious decision need not precede the protective response.
    • Reaction time may be measured using a ruler-drop test; repeat trials, prevent anticipation and calculate a mean.

    What to do in an assessment

    • Name each pathway component in order and explain how an automatic route protects the body.

    In plain language

    A reflex is a fast automatic route from stimulus detection to action.

    Self-check

    What neurone links sensory and motor neurones in the CNS?

    Show the answer

    A relay neurone.

  • Core

    Scope: Core · §2c B3.1d

    Open revision guidance

    What to know

    • Cornea refracts light; iris changes pupil size; lens focuses light onto retina. Ciliary muscles and suspensory ligaments change lens curvature for accommodation.
    • Retinal receptors generate impulses; optic nerve carries them to brain. The pupil is an opening, not a muscle.

    What to do in an assessment

    • Trace light to retina and signal to brain; link each named structure to its function.

    In plain language

    The eye focuses light on receptor cells, which send signals to the brain.

    Self-check

    What happens to the lens for near vision?

    Show the answer

    Ciliary muscles contract and suspensory ligaments slacken, making the lens thicker/more curved.

  • Core

    Scope: Core · §2c B3.1e

    Open revision guidance

    What to know

    • Short sight focuses distant light in front of retina and is corrected with a concave diverging lens. Long sight focuses near light behind retina and is corrected with a convex converging lens.
    • Colour blindness is a colour-receptor response defect, not a focusing error corrected by these lenses.

    What to do in an assessment

    • Show the incorrect focus relative to retina, then explain how corrective lens changes ray convergence.

    In plain language

    Concave lenses correct short sight; convex lenses correct long sight.

    Self-check

    Which lens corrects long sight?

    Show the answer

    A convex (converging) lens.

  • Core

    Scope: Core · §2c B3.1f

    Open revision guidance

    What to know

    • Cerebrum: conscious thought, memory and voluntary action; cerebellum: movement coordination/balance; medulla: automatic functions such as breathing and heart rate.
    • Hypothalamus monitors internal conditions and links nervous/endocrine control; pituitary releases hormones that regulate target glands.

    What to do in an assessment

    • Match a named region to its function and distinguish hypothalamus from pituitary.

    In plain language

    Different brain regions control thought, movement, automatic functions and hormonal regulation.

    Self-check

    Which region coordinates balance?

    Show the answer

    The cerebellum.

  • Higher

    Scope: Higher · §2c B3.1g (Higher only)

    Open revision guidance

    What to know

    • Direct experiments may harm people, so ethical safeguards limit research. Evidence often comes from case studies of injuries that differ in location and severity and are difficult to interpret consistently.
    • A single case may show association, but cannot prove a brain region alone causes a complex behaviour.

    What to do in an assessment

    • Evaluate evidence by naming ethical limits, sample/context differences and alternative explanations; distinguish correlation from cause.

    In plain language

    Brain research is difficult because direct tests are limited and case-study evidence can be hard to interpret.

    Self-check

    Why is one injury case not conclusive evidence for one brain function?

    Show the answer

    Other tissue may be damaged and individual cases differ, so a single observation cannot isolate cause.

  • Higher

    Scope: Higher · §2c B3.1h (Higher only)

    Open revision guidance

    What to know

    • Nervous tissue has limited repair capacity; damage can be irreversible and surrounding tissue may also be injured. Brain and spinal structures are difficult to access safely, limiting treatment options.
    • Assess interventions by weighing evidence, possible functional benefit, risk and accessibility; there is no universal treatment for all nervous disease.

    What to do in an assessment

    • Use repair limitation, irreversible injury and access as distinct explanations of treatment difficulty.

    In plain language

    Nervous-system treatment is difficult because tissue repairs poorly and damaged areas can be hard to reach.

    Self-check

    Give two reasons brain damage can be hard to treat.

    Show the answer

    Nervous tissue has limited repair and damage can be irreversible; the affected region may be difficult to access.

Topic group

B3.2 Endocrine coordination

9 revision points
  • Core

    Scope: Core · §2c B3.2a

    Open revision guidance

    What to know

    • Endocrine glands release hormones, chemical messengers carried in blood. A hormone affects target cells/organs with complementary receptors; it coordinates activity more slowly and often longer-lasting than a nerve impulse.
    • Hormone travels widely in blood, but only target cells with the receptor respond.

    What to do in an assessment

    • Trace gland → hormone in blood → receptor-bearing target → response; distinguish hormone signalling from neurone impulses.

    In plain language

    Glands send chemical messages through blood; only cells with the right receptor respond.

    Self-check

    Why does one hormone not affect every cell it passes?

    Show the answer

    Only cells with the matching receptor respond to it.

  • Higher

    Scope: Higher · §2c B3.2b (Higher only)

    Open revision guidance

    What to know

    • Thyroxine from the thyroid increases basal metabolic rate and supports growth/development. Its blood level is regulated by negative feedback: low thyroxine prompts hypothalamus/pituitary signals to stimulate thyroid; rising level inhibits further stimulation.
    • Adrenaline from adrenal glands prepares the body for action by increasing heart rate and blood supply to muscles and mobilising glucose.

    What to do in an assessment

    • Draw a feedback loop with change → detector/control response → hormone → correction → reduced stimulus; explain how adrenaline effects aid rapid action.

    In plain language

    Thyroxine sets metabolic activity and is kept near a target by negative feedback; adrenaline prepares for action.

    Self-check

    What is the direction of negative feedback when thyroxine is already high?

    Show the answer

    Pituitary/hypothalamic stimulation of the thyroid is reduced, bringing thyroxine production down.

  • Core

    Scope: Core · §2c B3.2c

    Open revision guidance

    What to know

    • FSH from pituitary stimulates ovarian follicle/egg maturation; oestrogen from ovary rebuilds uterine lining and contributes to cycle control. Progesterone maintains the lining after ovulation; testosterone supports sperm production and male reproductive development.
    • Hormones coordinate gamete production and changes in reproductive organs.

    What to do in an assessment

    • Name hormone source and effect; sequence cycle events by hormone level rather than treating the menstrual cycle as a fixed set of equal stages.

    In plain language

    Hormones coordinate egg maturation, the uterus lining and sperm production.

    Self-check

    Which hormone maintains the uterine lining after ovulation?

    Show the answer

    Progesterone.

  • Higher

    Scope: Higher · §2c B3.2d (Higher only)

    Open revision guidance

    What to know

    • FSH stimulates an ovarian follicle to mature and release oestrogen. Oestrogen rebuilds the uterus lining and inhibits FSH while stimulating LH; an LH surge triggers ovulation. The follicle becomes corpus luteum, which releases progesterone to maintain the lining and suppress FSH/LH.
    • If no pregnancy occurs, progesterone falls; the lining breaks down and a new cycle begins. Hormone graphs show overlapping, changing concentrations, not isolated on/off switches.

    What to do in an assessment

    • Read axes/time before comparing hormone curves; link FSH, LH, oestrogen and progesterone peaks to events and uterine-lining change.

    In plain language

    A changing sequence of FSH, LH, oestrogen and progesterone coordinates egg release and prepares or maintains the uterus lining.

    Self-check

    Which hormone surge triggers ovulation?

    Show the answer

    Luteinising hormone (LH).

  • Core

    Scope: Core · §2c B3.2e

    Open revision guidance

    What to know

    • Hormonal methods (for example combined pill or implant) alter reproductive hormone signalling to prevent ovulation and/or fertilisation; non-hormonal options include barrier methods and copper intrauterine devices. Methods differ in effectiveness, duration, side effects and suitability.
    • Condoms also reduce transmission risk of many sexually transmitted infections; most other contraceptives do not.

    What to do in an assessment

    • Compare evidence-based effectiveness alongside access, correct use, side effects, personal suitability and STI protection; avoid treating one percentage as guaranteed protection for every user.

    In plain language

    Contraceptive methods prevent pregnancy in different ways and have different reliability, health effects and practical features.

    Self-check

    Which common method can reduce both pregnancy risk and STI transmission?

    Show the answer

    A condom, when used correctly.

  • Higher

    Scope: Higher · §2c B3.2f (Higher only)

    Open revision guidance

    What to know

    • Infertility may be treated with fertility drugs containing FSH/LH to stimulate egg maturation/ovulation. In IVF, eggs are collected, fertilised with sperm in a laboratory, then one or more embryos are transferred to the uterus.
    • Hormone treatments can increase chance of pregnancy but may cause multiple births and other risks; decisions balance evidence, safety, cost and patient circumstances.

    What to do in an assessment

    • Describe treatment sequence and explain why hormone stimulation is used; evaluate benefits against risks without implying success is certain.

    In plain language

    Fertility hormones can stimulate egg maturation; IVF fertilises eggs outside the body before an embryo is transferred.

    Self-check

    What happens to an IVF embryo after fertilisation in the laboratory?

    Show the answer

    It is transferred to the uterus for implantation and development.

  • Core

    Scope: Core · §2c B3.2g

    Open revision guidance

    What to know

    • Auxin is a plant hormone. Unequal distribution across a shoot causes cells on one side to elongate more, bending growth toward light; in roots, auxin can inhibit elongation on the lower side, bending growth downward with gravity.
    • Tropisms are directional growth responses. The growth response depends on organ and hormone concentration.

    What to do in an assessment

    • In a seedling diagram, identify stimulus, auxin redistribution, side with greater elongation and bend direction; distinguish shoot from root response.

    In plain language

    Uneven auxin makes opposite sides grow at different rates, turning a plant toward or away from a stimulus.

    Self-check

    How does unequal auxin cause a shoot to bend toward light?

    Show the answer

    More auxin accumulates on the shaded side, whose cells elongate more, bending the shoot toward light.

  • Core

    Scope: Core · §2c B3.2h (common auxin content; bold gibberellin/ethene content and listed effects Higher-only)

    Open revision guidance

    What to know

    • Common to both tiers: auxins are plant hormones that affect growth and tropisms; B3.2g covers their role in phototropism and gravitropism.
    • Higher-only bold detail: gibberellins control growth and germination; ethene promotes fruit ripening and can contribute to flower opening and leaf shedding. Ethene from ripe fruit can accelerate ripening in nearby fruit. These hormone effects depend on plant tissue and concentration.

    What to do in an assessment

    • For both tiers, identify auxin as a plant growth hormone and link it to tropisms. For Higher only, match gibberellin and ethene to their listed effects, including growth/germination, ripening, flower opening and leaf shedding.

    In plain language

    Auxin content applies to both tiers; Higher candidates also learn the listed effects of gibberellins and ethene.

    Self-check

    Common: Which hormone is linked to tropisms? Higher extension: Which listed hormone is associated with fruit ripening?

    Show the answer

    Common: auxin is linked to tropisms. Higher extension: ethene is associated with fruit ripening.

  • Higher

    Scope: Higher · §2c B3.2i (Higher only)

    Open revision guidance

    What to know

    • People use plant hormones to control growth: selective auxin herbicides target broad-leaved weeds; auxins can promote rooting in cuttings; gibberellins can alter dormancy/germination; hormone treatment can induce parthenocarpy, producing seedless fruit.
    • A useful application must be considered against effects on non-target plants, dose and crop/environmental consequences.

    What to do in an assessment

    • For each use, name the hormone/action and the desired outcome; distinguish commercial benefit from possible ecological risk.

    In plain language

    Plant growth regulators can control weeds, rooting, dormancy and production of seedless fruit.

    Self-check

    How can plant hormones help produce seedless fruit?

    Show the answer

    Treatment can induce parthenocarpy, fruit development without normal fertilisation and seed formation.

Topic group

B3.3 Homeostasis

10 revision points
  • Core

    Scope: Core · §2c B3.3a

    Open revision guidance

    What to know

    • Homeostasis maintains a stable internal environment despite internal or external change. Appropriate temperature, blood-glucose concentration and water/ion balance allow enzyme-controlled metabolic reactions to proceed at suitable rates.
    • Regulation involves detecting a change and coordinating corrective responses; it does not mean every internal value is perfectly constant.

    What to do in an assessment

    • Explain why a changed condition affects reaction rates or cells, then connect regulation to maintaining function.

    In plain language

    Homeostasis keeps internal conditions within workable limits so cells and enzymes function properly.

    Self-check

    Why does the body regulate internal temperature?

    Show the answer

    Enzyme-controlled metabolic reactions work effectively only within a suitable temperature range.

  • Core

    Scope: Core · §2c B3.3b

    Open revision guidance

    What to know

    • Skin receptors detect external temperature. In heat, sweating increases evaporative heat loss and skin arterioles dilate, bringing more blood near the surface; in cold, vasoconstriction reduces surface blood flow and shivering generates heat.
    • These effectors help restore internal temperature; sweating cools by evaporation, not simply because sweat is wet.

    What to do in an assessment

    • For hot/cold scenarios trace stimulus → response → change in heat loss/production; use vasodilation and vasoconstriction precisely.

    In plain language

    The skin detects temperature change and controls sweating and blood flow to help warm or cool the body.

    Self-check

    How does vasodilation help when body temperature is too high?

    Show the answer

    More blood flows near the skin, increasing heat transfer to the surroundings.

  • Core

    Scope: Core · §2c B3.3c

    Open revision guidance

    What to know

    • When blood glucose rises, pancreatic beta cells release insulin. It increases uptake of glucose by body cells and promotes conversion of glucose to glycogen in liver and muscle, lowering blood glucose toward its normal range.
    • Insulin acts by binding to receptors; the response is part of negative feedback.

    What to do in an assessment

    • Describe stimulus, pancreatic hormone release, target-tissue action and direction of glucose change.

    In plain language

    High blood glucose triggers insulin, which helps cells take up glucose and the liver store it as glycogen.

    Self-check

    What happens to blood glucose after insulin is released?

    Show the answer

    It falls as cells take up glucose and liver/muscle store some as glycogen.

  • Higher

    Scope: Higher · §2c B3.3d (Higher only)

    Open revision guidance

    What to know

    • When blood glucose falls, pancreatic alpha cells release glucagon. It promotes conversion of glycogen to glucose in the liver, raising blood glucose; insulin has the opposing effect when glucose is high.
    • The two hormones form negative feedback responses that keep blood glucose within a suitable range.

    What to do in an assessment

    • Use a two-row comparison: high glucose → insulin → storage/uptake → glucose falls; low glucose → glucagon → liver glycogen breakdown → glucose rises.

    In plain language

    Glucagon raises low blood sugar by helping the liver release glucose; insulin lowers high blood sugar.

    Self-check

    What does glucagon do to liver glycogen when blood glucose is low?

    Show the answer

    It promotes its breakdown to glucose, which enters the blood.

  • Core

    Scope: Core · §2c B3.3e

    Open revision guidance

    What to know

    • Type 1 diabetes occurs when pancreatic beta cells produce little/no insulin; treatment requires insulin replacement with monitored diet and glucose. Type 2 involves body cells responding less effectively to insulin and is associated with risk factors including body mass and inactivity.
    • Type 2 management can include dietary/activity changes and medication; some people also require insulin. Treatment is individual and monitored.

    What to do in an assessment

    • Compare cause before treatment; do not describe type 1 as simply lifestyle-caused or type 2 as always treated without insulin.

    In plain language

    Type 1 is a lack of insulin; type 2 is reduced response to insulin. Their management differs and needs monitoring.

    Self-check

    What is the core cause of type 1 diabetes?

    Show the answer

    Pancreatic beta cells produce little or no insulin.

  • Core

    Scope: Core · §2c B3.3f

    Open revision guidance

    What to know

    • Across a partially permeable membrane, water moves from higher water potential to lower water potential. In a more dilute external fluid, an animal cell may gain water and lyse; in a more concentrated fluid it loses water and shrinks.
    • Plant cells gain turgor in dilute fluid; in concentrated fluid they lose water and the membrane pulls from the wall (plasmolysis). Equal water potentials cause no net water movement.

    What to do in an assessment

    • Compare inside/outside water potentials qualitatively, state direction of water movement and predict cell change; no numerical water-potential calculation is required.

    In plain language

    Water movement can swell, shrink or leave a cell unchanged, depending on the surrounding solution.

    Self-check

    What happens to an animal cell in a solution with lower water potential than its cytoplasm?

    Show the answer

    Water leaves by osmosis, so the cell shrinks.

  • Core

    Scope: Core · §2c B3.3g

    Open revision guidance

    What to know

    • Kidneys filter blood and selectively reabsorb useful substances and variable amounts of water. The final urine volume and concentration therefore adjust water excretion to help maintain blood water balance.
    • Urine normally contains water, urea and mineral ions; blood cells and most proteins remain in the blood.

    What to do in an assessment

    • Relate more water reabsorption to a smaller, more concentrated urine volume, and less reabsorption to a larger, more dilute output.

    In plain language

    Kidneys adjust how much water is returned to blood and how much leaves in urine.

    Self-check

    If more water is reabsorbed by kidneys, how does urine usually change?

    Show the answer

    Its volume falls and it becomes more concentrated.

  • Core

    Scope: Core · §2c B3.3h

    Open revision guidance

    What to know

    • A nephron begins at Bowman's capsule, continues through the proximal convoluted tubule and loop of Henlé, and drains to a collecting duct. The kidney contains many nephrons and associated blood vessels.
    • Filtration begins at the capsule; selective reabsorption along tubules returns useful solutes and water to blood. Tubule structure and blood supply support exchange.

    What to do in an assessment

    • Label the required structures in filtrate order and link filtration/reabsorption to urine formation.

    In plain language

    Nephrons filter blood, reclaim useful materials and pass remaining fluid into collecting ducts.

    Self-check

    Which nephron structure carries fluid after the loop of Henlé?

    Show the answer

    The collecting duct.

  • Higher

    Scope: Higher · §2c B3.3i (Higher only)

    Open revision guidance

    What to know

    • When blood water potential is low, pituitary releases more ADH. ADH makes kidney tubules/collecting ducts more permeable to water, increasing reabsorption and producing less, more concentrated urine.
    • When blood water potential is high, less ADH is released; tubules reabsorb less water, producing more dilute urine. This is negative feedback.

    What to do in an assessment

    • Track stimulus → ADH change → tubule permeability → water reabsorption → urine volume/concentration; do not say ADH directly changes filtration rate.

    In plain language

    ADH changes how permeable kidney tubules are to water, helping the body conserve or excrete water.

    Self-check

    What happens to ADH release when the blood is too concentrated?

    Show the answer

    More ADH is released, increasing water reabsorption and making urine more concentrated.

  • Higher

    Scope: Higher · §2c B3.3j (Higher only)

    Open revision guidance

    What to know

    • Heavy sweating causes water loss and dehydration; the response includes thirst and kidney action to conserve water. Excess water intake lowers blood solute concentration, while high salt intake raises it; ADH changes kidney water reabsorption to restore balance.
    • Temperature responses include sweating/vasodilation in heat and shivering/vasoconstriction in cold. Osmotic responses and thermal responses are coordinated but are not the same mechanism.

    What to do in an assessment

    • For high sweat, excess drinking or salt intake, infer the blood-water change, predict thirst/ADH/kidney response and resulting urine; keep temperature mechanisms separate.

    In plain language

    The body combines thirst, kidneys and temperature responses to recover from dehydration, excess water, salt and heat/cold.

    Self-check

    After heavy sweating without drinking, what happens to ADH and urine?

    Show the answer

    Blood water potential falls, ADH rises and more water is reabsorbed, so urine volume decreases and concentration increases.

Topic group

B4.1 Ecosystems

10 revision points
  • Core

    Scope: Core · §2c B4.1a

    Open revision guidance

    What to know

    • Materials move between living (biotic) organisms and non-living (abiotic) stores rather than disappearing. Carbon and nitrogen cycle through organisms, soil, water and atmosphere; water also moves between land, organisms and air.
    • Matter is recycled, although energy flows through ecosystems and is eventually dissipated.

    What to do in an assessment

    • Classify a named store/process as biotic or abiotic and trace how an atom can move between them.

    In plain language

    Ecosystems continually recycle matter between organisms and their surroundings.

    Self-check

    Give one abiotic store of carbon.

    Show the answer

    The atmosphere as carbon dioxide, oceans, soil or carbonate rock.

  • Core

    Scope: Core · §2c B4.1b

    Open revision guidance

    What to know

    • Bacteria and fungi decompose dead organisms and waste. They secrete enzymes that digest large molecules outside cells and absorb the soluble products, returning mineral nutrients to soil/water.
    • Decomposer respiration releases carbon dioxide; decomposition therefore links nutrient recycling with carbon cycling.

    What to do in an assessment

    • Explain how microorganisms act on dead material and connect decomposition products to plant nutrient uptake.

    In plain language

    Microorganisms break down dead matter and return useful substances to the ecosystem.

    Self-check

    How do decomposers obtain soluble nutrients from dead leaves?

    Show the answer

    They secrete digestive enzymes onto the material, break it down, then absorb soluble products.

  • Core

    Scope: Core · §2c B4.1c

    Open revision guidance

    What to know

    • Photosynthesis removes carbon dioxide from air and fixes carbon into biomass; respiration, decomposition and combustion return it. Carbon transfer through feeding links organisms.
    • Water evaporates/transpires, condenses and precipitates; runoff and infiltration return it to water bodies. These cycles supply water and nutrients and help maintain habitats.

    What to do in an assessment

    • Trace named processes with arrow direction and explain why cycling supports organisms; distinguish carbon movement from water movement.

    In plain language

    Carbon and water move repeatedly through organisms, air, soil and water, sustaining life and habitats.

    Self-check

    Name one process that returns carbon dioxide to air.

    Show the answer

    Respiration, decomposition or combustion.

  • Core

    Scope: Core · §2c B4.1d

    Open revision guidance

    What to know

    • Decomposer enzymes work faster near suitable temperatures; water supports microbial activity, while oxygen supports aerobic decomposition. Dry, very cold or oxygen-poor conditions slow many decomposition processes.
    • In a compost test, vary one factor, control material/size and mass, measure temperature or mass loss over time, repeat and calculate rate/percentage change.

    What to do in an assessment

    • Use rate = change ÷ time and compare conditions; identify whether decomposition is aerobic or anaerobic and support conclusions with data.

    In plain language

    Warmth, moisture and oxygen affect how quickly microorganisms decompose material.

    Self-check

    Why can very dry compost decompose slowly?

    Show the answer

    Microorganisms need water for metabolism and enzyme reactions, so low water content reduces their activity.

  • Core

    Scope: Core · §2c B4.1e

    Open revision guidance

    What to know

    • An individual is one organism; a population is organisms of one species in an area; a community is all populations there; an ecosystem includes the community and its abiotic environment.
    • The levels are nested: organisms form populations, populations interact as communities, and communities interact with environmental conditions.

    What to do in an assessment

    • Choose the smallest term that includes all details in a question; include abiotic surroundings only when defining ecosystem.

    In plain language

    An ecosystem means the organisms in a place plus the non-living conditions they interact with.

    Self-check

    Does a community include abiotic factors?

    Show the answer

    No. It includes populations of different species; the ecosystem includes the community and abiotic environment.

  • Core

    Scope: Core · §2c B4.1f

    Open revision guidance

    What to know

    • Abiotic factors include temperature, light intensity, soil moisture and pH; biotic factors include predators, competitors and food availability. Each can change survival, reproduction and distribution of species.
    • A changed factor may benefit one population while disadvantaging another, altering community composition.

    What to do in an assessment

    • Classify the factor as biotic/abiotic and trace its effect through survival or reproduction to an observed distribution change.

    In plain language

    Living interactions and non-living conditions both affect which organisms can live in a community.

    Self-check

    Is soil pH biotic or abiotic?

    Show the answer

    Abiotic: it is a non-living chemical condition.

  • Core

    Scope: Core · §2c B4.1g

    Open revision guidance

    What to know

    • Predation is one organism consuming another; mutualism benefits both species; parasitism benefits one while harming a host. Competition occurs when organisms need the same limited resource.
    • Because organisms depend on food, shelter, pollination and other interactions, a change in one population can affect others.

    What to do in an assessment

    • Identify which species benefits or is harmed, then predict a linked population change through the food web or resource relationship.

    In plain language

    Species affect one another through feeding, cooperation, parasitism and competition for resources.

    Self-check

    In mutualism, which species benefit?

    Show the answer

    Both interacting species.

  • Core

    Scope: Core · §2c B4.1h

    Open revision guidance

    What to know

    • A producer (usually a photosynthetic plant/alga) forms the first trophic level. Consumers obtain biomass by feeding: primary consumers eat producers, secondary consumers eat primary consumers, and higher consumers feed at later levels.
    • Food-chain arrows show transfer of biomass/energy from food to feeder, not the direction of hunting.

    What to do in an assessment

    • Number trophic levels from producer and follow arrows in the direction food biomass moves.

    In plain language

    A trophic level is an organism's feeding position in a food chain.

    Self-check

    What is the first trophic level in a plant-based food chain?

    Show the answer

    The producer.

  • Core

    Scope: Core · §2c B4.1i

    Open revision guidance

    What to know

    • A pyramid of biomass shows total dry mass of organisms at each trophic level per area at a time. Biomass available to the next level is reduced by egestion, excretion and respiration: respiration uses organic molecules and converts some of their matter to products such as carbon dioxide and water. Heat is energy transferred, not biomass.
    • Not all consumed material is digested or converted to new biomass; less biomass is generally available at higher levels.

    What to do in an assessment

    • Read units and area/time basis, compare bar widths, and explain losses with named matter pathways rather than saying biomass simply disappears or that heat is biomass.

    In plain language

    Only part of one trophic level's organic matter becomes biomass in the next; some is egested or excreted, and some is converted by respiration into other substances.

    Self-check

    How does respiration reduce biomass available to the next trophic level?

    Show the answer

    Respiration uses organic molecules and converts some matter into products such as carbon dioxide and water. The heat released is energy transfer, not biomass.

  • Core

    Scope: Core · §2c B4.1j

    Open revision guidance

    What to know

    • Transfer efficiency (%) = biomass gained at next trophic level ÷ biomass available at previous level × 100. Example: 40 kg from 500 kg gives 8%.
    • Because biomass/energy is lost at each transfer, progressively less supports higher levels; this limits the number of trophic levels a food chain can sustain.

    What to do in an assessment

    • Use matched units and biomass quantities for adjacent levels, multiply ratio by 100 and state the implication of low transfer efficiency.

    In plain language

    Efficiency is the percentage of one level's biomass that becomes the next level's biomass.

    Self-check

    Biomass falls from 800 g m⁻² to 64 g m⁻². What is transfer efficiency?

    Show the answer

    64 ÷ 800 × 100 = 8%.

Topic group

B5.1 Inheritance

13 revision points
  • Core

    Scope: Core · §2c B5.1a

    Open revision guidance

    What to know

    • A gamete is a haploid sex cell; a chromosome is a DNA molecule carrying genes; a gene is a DNA sequence; an allele/variant is a version of a gene. Genotype is allele combination; phenotype is observable characteristic.
    • Homozygous means two same alleles, heterozygous two different; dominant allele affects phenotype when one copy is present, recessive is expressed when no dominant allele masks it.

    What to do in an assessment

    • Use allele symbols consistently; keep genotype (letters) distinct from phenotype (trait), and do not treat 'dominant' as more common or stronger.

    In plain language

    Genes have versions called alleles; the allele combination is genotype and the observed trait is phenotype.

    Self-check

    Is Bb genotype or phenotype?

    Show the answer

    Genotype; it records the alleles.

  • Core

    Scope: Core · §2c B5.1b

    Open revision guidance

    What to know

    • The genome is the entire genetic material of an organism, including all its genes and other DNA sequences. In eukaryotic cells most genome DNA is in nuclear chromosomes; some DNA is in mitochondria (and plant chloroplasts).

    What to do in an assessment

    • Define genome as all genetic material, not only one gene or only DNA that codes for proteins.

    In plain language

    An organism's genome is its complete set of genetic material.

    Self-check

    Does the genome mean only one gene?

    Show the answer

    No. It means the organism's entire genetic material.

  • Core

    Scope: Core · §2c B5.1c

    Open revision guidance

    What to know

    • Phenotype develops through interaction between genome and environment. Some variation is discontinuous with distinct categories; other traits are continuous across a range.
    • Eye colour illustrates category variation; height and body mass are influenced by many genes and environmental factors such as nutrition.

    What to do in an assessment

    • For a trait, separate genetic contribution from environmental influence and classify whether values fall into categories or a continuous range.

    In plain language

    Inherited DNA and life conditions together affect observable characteristics.

    Self-check

    Is human height usually continuous or discontinuous variation?

    Show the answer

    Continuous; values form a range.

  • Core

    Scope: Core · §2c B5.1d

    Open revision guidance

    What to know

    • A mutation is a change in genetic material and is the source of new genetic variants. Most have no effect on phenotype; some influence it and a very small number determine a characteristic.
    • Effects depend on the affected DNA and environment. Mutations are not produced because an organism needs a particular adaptation.

    What to do in an assessment

    • Distinguish mutation (DNA change) from its possible phenotypic effect; do not assume every mutation is harmful or expressed.

    In plain language

    Mutations create new genetic variants, but most do not noticeably change an organism's characteristics.

    Self-check

    Do all mutations change phenotype?

    Show the answer

    No. Most have no effect; some influence phenotype and very few determine it.

  • Higher

    Scope: Higher · §2c B5.1e (Higher only)

    Open revision guidance

    What to know

    • A coding-DNA variant may change a protein's amino-acid sequence and shape, altering activity; for an enzyme it may change active-site fit. A non-coding variant can alter whether a gene is transcribed into mRNA, changing protein production.
    • A variant's effect therefore depends on whether it changes protein structure/function or gene expression; neither route guarantees an observable phenotype.

    What to do in an assessment

    • Trace coding change → protein structure/activity or regulatory change → transcription/protein amount → possible phenotype; promoter/transcription-factor terminology is not needed.

    In plain language

    A DNA variant can change a protein itself or change how much of it a cell makes.

    Self-check

    How could a coding variant alter enzyme activity?

    Show the answer

    It may change an amino acid and active-site shape, affecting substrate binding/catalysis.

  • Core

    Scope: Core · §2c B5.1f

    Open revision guidance

    What to know

    • Asexual reproduction uses one parent and mitosis, usually making genetically similar offspring rapidly and in large numbers, but little new variation. Sexual reproduction joins gametes from two parents, generating varied allele combinations but usually takes more time and produces fewer offspring.
    • Variation in sexual populations can help some individuals survive environmental change; asexual clones can reproduce efficiently in stable conditions.

    What to do in an assessment

    • Compare parent number, gametes, speed/offspring number and variation; relate the best strategy to environmental pressures, not to a universal advantage.

    In plain language

    Asexual reproduction is fast and genetically similar; sexual reproduction creates varied offspring but requires gametes and more time.

    Self-check

    Which process usually creates more genetic variation among offspring?

    Show the answer

    Sexual reproduction, because alleles from two parents are combined.

  • Core

    Scope: Core · §2c B5.1g

    Open revision guidance

    What to know

    • A diploid cell has two sets of chromosomes, one set inherited from each parent. A haploid cell has one set; human gametes are haploid, with 23 chromosomes, while most body cells are diploid with 46.

    What to do in an assessment

    • State chromosome-set number rather than chromosome size; use haploid for gametes and diploid for body cells.

    In plain language

    Diploid means two chromosome sets; haploid means one.

    Self-check

    Are human sperm cells haploid or diploid?

    Show the answer

    Haploid; they carry one set of 23 chromosomes.

  • Core

    Scope: Core · §2c B5.1h

    Open revision guidance

    What to know

    • Meiosis halves chromosome number to form haploid gametes. When two gametes fuse at fertilisation, diploid number is restored, so chromosome number does not double each generation.
    • Meiosis also creates genetic variation in gametes through different chromosome/allele combinations.

    What to do in an assessment

    • Link reduction division to fertilisation and explain why halving is necessary; distinguish meiosis from mitosis, which preserves chromosome number.

    In plain language

    Meiosis makes gametes with half the usual chromosome sets so fertilisation restores the diploid number.

    Self-check

    Why must human gametes have 23 rather than 46 chromosomes?

    Show the answer

    Two gametes fuse at fertilisation; 23 + 23 restores the diploid total of 46.

  • Core

    Scope: Core · §2c B5.1i

    Open revision guidance

    What to know

    • For one gene, each diploid parent contributes one allele in a gamete. A homozygous parent passes one allele type; a heterozygote can pass either allele. Dominant/recessive allele combinations determine predicted phenotype.
    • For Bb × Bb with B dominant, genotypes are 1 BB : 2 Bb : 1 bb and phenotype ratio is 3 dominant : 1 recessive, assuming complete dominance.

    What to do in an assessment

    • Write parental genotypes, list gametes and combine alleles; report genotype and phenotype separately and label probability.

    In plain language

    A child inherits one allele from each parent; the pair can predict a single-gene trait.

    Self-check

    For Bb × Bb, what fraction of offspring are expected bb?

    Show the answer

    One quarter (25%), because one of four equally likely allele combinations is bb.

  • Core

    Scope: Core · §2c B5.1j

    Open revision guidance

    What to know

    • A Punnett square combines possible gametes to show expected offspring genotypes and phenotypes. Each cell is an equally likely combination only when gametes are equally likely and the cross assumptions hold.
    • Probability = number of outcomes of interest ÷ total possible outcomes; convert to percentage by multiplying by 100.

    What to do in an assessment

    • Put one parent's gametes across top and the other's down side, fill each cell, count outcomes and express expected ratio/probability—not a guaranteed family result.

    In plain language

    A Punnett square lists possible allele combinations and their expected probabilities.

    Self-check

    A trait appears in 3 of 4 square cells. What percentage probability is predicted?

    Show the answer

    3 ÷ 4 × 100 = 75%.

  • Core

    Scope: Core · §2c B5.1k

    Open revision guidance

    What to know

    • Typical human egg carries X; sperm carries X or Y. XX is typically female and XY typically male, giving an approximately 1:1 probability at fertilisation.
    • The sperm chromosome determines the XX/XY combination in this simple model; each conception is an independent probability.

    What to do in an assessment

    • Draw a 2×2 cross of X eggs with X/Y sperm and state the predicted ratio is not a guarantee for a small family.

    In plain language

    An X-bearing egg combines with an X- or Y-bearing sperm, producing an approximately even XX/XY chance.

    Self-check

    What proportion of outcomes in the simple XX × XY sex-chromosome cross are XY?

    Show the answer

    One half (50%).

  • Core

    Scope: Core · §2c B5.1l

    Open revision guidance

    What to know

    • Most phenotypic features result from several genes rather than a single-gene dominant/recessive pattern. Multiple genetic contributions can create a range of values, often also influenced by environment.
    • Height and mass are examples of continuous characteristics affected by many factors.

    What to do in an assessment

    • Do not force a polygenic continuous trait into one-gene Punnett ratios; identify multiple genes and possible environmental influence.

    In plain language

    Many characteristics, such as height, reflect many genes and environmental effects together.

    Self-check

    Is human height usually explained by one dominant allele?

    Show the answer

    No. It is polygenic and also influenced by environment.

  • Core

    Scope: Core · §2c B5.1m

    Open revision guidance

    What to know

    • Gregor Mendel used controlled crosses of pea plants and counted inherited characteristics across generations. Ratios in his data helped infer discrete inherited factors—now called alleles—and patterns of dominance.
    • Scientific understanding developed as evidence, methods and knowledge of chromosomes/DNA improved; Mendel's contribution was not fully recognised during his lifetime.

    What to do in an assessment

    • Explain how controlled crosses and repeated counts support an inheritance model; distinguish historical evidence from modern molecular explanation.

    In plain language

    Mendel's pea crosses revealed predictable inheritance patterns that became the basis of genetics.

    Self-check

    What kind of evidence did Mendel collect from pea plants?

    Show the answer

    Counts of characteristics in offspring from controlled crosses over generations.

Topic group

B5.2 Evolution

6 revision points
  • Core

    Scope: Core · §2c B5.2a

    Open revision guidance

    What to know

    • A population of one species usually contains extensive genetic variation: individuals carry different alleles and phenotypes. Variation can arise through mutation and be reshuffled by sexual reproduction.
    • Variation is among individuals in a population; an individual does not evolve during its lifetime.

    What to do in an assessment

    • When comparing populations, identify inherited variants and describe the range/frequency rather than treating a species as uniform.

    In plain language

    Individuals of the same species differ genetically, giving populations a range of characteristics.

    Self-check

    Is variation found between individuals or only between species?

    Show the answer

    Between individuals within a species as well as between species.

  • Core

    Scope: Core · §2c B5.2b

    Open revision guidance

    What to know

    • Artificial classification groups organisms by one or a few convenient observable features and need not represent evolutionary relationships. Natural classification uses a wider range of shared characteristics to group organisms in a way that reflects their relationships. Molecular phylogenetics compares DNA sequences to infer evolutionary relatedness and can revise classifications.
    • More similar DNA sequences generally indicate a more recent common ancestor, interpreted alongside other evidence.

    What to do in an assessment

    • Compare artificial and natural systems, then use DNA-sequence similarity or phylogenetic branching to infer relatedness; state that classifications are revised when stronger evidence appears.

    In plain language

    Classification can group organisms by convenient visible features or by a broader set of traits and evolutionary relationships; DNA evidence can refine those groups.

    Self-check

    How does natural classification differ from an artificial system?

    Show the answer

    Natural classification uses many shared characteristics to reflect relationships; an artificial system groups by a limited convenient feature that may not reflect evolutionary relatedness.

  • Core

    Scope: Core · §2c B5.2c

    Open revision guidance

    What to know

    • Mutations produce inherited variants. If a phenotype gives an advantage in a particular environment, its individuals are more likely to survive and reproduce, passing alleles to offspring; over generations that variant becomes more common.
    • Selection acts on existing variation in populations. Individuals do not change their genes because they need to adapt.

    What to do in an assessment

    • Write the sequence variation → selection pressure → differential reproductive success → inherited change in allele/trait frequency.

    In plain language

    Better-suited inherited variants become more common because their bearers leave more offspring.

    Self-check

    Do individual organisms evolve by changing their genes to meet a need?

    Show the answer

    No. Populations change over generations as some inherited variants lead to greater reproductive success.

  • Core

    Scope: Core · §2c B5.2d

    Open revision guidance

    What to know

    • Evolution is change in inherited characteristics of a population over generations through natural selection. If populations become sufficiently different and reproductively isolated, new species may form.
    • Environmental change can make previously successful traits disadvantageous; populations unable to compete and reproduce may decline or become extinct.

    What to do in an assessment

    • Define evolution at population level and over time; connect reproductive isolation and accumulated differences to possible speciation.

    In plain language

    Evolution is inherited population change across generations; long-term divergence can produce new species.

    Self-check

    Does evolution describe a change in one organism during its life?

    Show the answer

    No. It describes change in inherited population characteristics over generations.

  • Core

    Scope: Core · §2c B5.2e

    Open revision guidance

    What to know

    • Fossils show organisms from the past and sequences of change; their age and features provide evidence for relationships, though the fossil record is incomplete.
    • Antibiotic resistance in bacteria is observed evolution: resistant variants survive treatment and reproduce, increasing resistance alleles in the population.

    What to do in an assessment

    • Use fossil similarities/changes or measured resistance frequencies as evidence; describe selection without saying an antibiotic creates a needed mutation.

    In plain language

    Fossils and changing bacterial resistance provide evidence that populations have changed over time.

    Self-check

    How can antibiotic use increase the proportion of resistant bacteria?

    Show the answer

    Susceptible bacteria are killed more often; resistant ones survive and reproduce, passing on resistance.

  • Core

    Scope: Core · §2c B5.2f

    Open revision guidance

    What to know

    • Charles Darwin and Alfred Russel Wallace independently developed ideas about evolution by natural selection from observations of variation, inheritance and environmental pressures. Their work helped establish an evidence-based explanation of biodiversity and common ancestry.
    • Modern biology combines their selection theory with genetic evidence explaining heritable variation. Seedbanks store seeds from diverse plant populations, helping conserve biodiversity and preserving material that may support future study or restoration.

    What to do in an assessment

    • Credit both scientists and explain the lasting impact: natural selection explains adaptation, population change and relationships among organisms.
    • Explain how conserving a diverse seed collection can retain plant genetic diversity for future generations; seed storage is one part of biodiversity conservation, not a substitute for protecting habitats.

    In plain language

    Darwin and Wallace developed natural selection, a central explanation for evolution and biodiversity; seedbanks can store part of that biodiversity for the future.

    Self-check

    What mechanism did Darwin and Wallace help develop as an explanation for evolution?

    Show the answer

    Natural selection acting on heritable variation.

Topic group

B6.1 Environment

4 revision points
  • Core

    Scope: Core · §2c B6.1a

    Open revision guidance

    What to know

    • Use random quadrats to estimate abundance/distribution of stationary organisms; transects show change along an environmental gradient. Mobile animals may be sampled with pooters/nets or capture–recapture; keys aid identification.
    • For quadrats, mean density = organisms counted ÷ sampled area; scale up by habitat area. Capture–recapture estimate ≈ first capture × second capture ÷ marked recaptures, assuming mixing, no births/deaths and marks retained.

    What to do in an assessment

    • Use unbiased placement, sufficient repeats and consistent identification; show units and assumptions when scaling up or estimating a population.

    In plain language

    Sampling estimates a whole habitat from smaller representative samples; different organisms need different methods.

    Self-check

    A first sample marks 40 animals, a second catches 30, of which 10 are marked. Estimate population.

    Show the answer

    40 × 30 ÷ 10 = 120 animals, assuming a well-mixed closed population and marks retained.

  • Core

    Scope: Core · §2c B6.1b

    Open revision guidance

    What to know

    • Human effects may be positive (protected habitats/species, restoration) or negative (land-use change, habitat fragmentation, pollution and hunting). Habitat loss and overharvesting can reduce population size and genetic diversity and raise extinction risk.
    • A biodiversity impact should consider species, habitats and ecosystem interactions, not only one visible organism.

    What to do in an assessment

    • Use evidence to connect an activity to habitat/population change and then biodiversity; distinguish a local benefit from wider costs.

    In plain language

    People can reduce biodiversity through habitat damage or protect it through conservation.

    Self-check

    How can land-use change reduce biodiversity?

    Show the answer

    It can remove or fragment habitats, reducing resources and isolating populations.

  • Core

    Scope: Core · §2c B6.1c

    Open revision guidance

    What to know

    • Local/global biodiversity schemes protect species, habitats and ecosystem services; ecotourism can provide income and incentives to conserve wildlife. Challenges include agreement among governments/communities, competing land use and long-term monitoring.
    • A scheme must be monitored to check whether targets are met and whether costs/benefits are shared fairly.

    What to do in an assessment

    • Evaluate benefits and barriers for named stakeholders, including monitoring, agreements, livelihoods and ecological outcomes.

    In plain language

    Conservation can protect nature and support livelihoods, but requires cooperation and evidence that it works.

    Self-check

    Why is monitoring needed after a habitat-protection scheme begins?

    Show the answer

    To determine whether biodiversity targets are achieved and to detect problems or unintended effects.

  • Higher

    Scope: Higher · §2c B6.1d (Higher only)

    Open revision guidance

    What to know

    • Water availability and atmospheric gases can change where organisms occur. Evaluate distribution evidence by comparing measured location/abundance with environmental data and considering other variables, sampling effort and time trends.
    • A correlation between a gas or water change and species distribution is not alone proof of causation; use controlled or multiple-line evidence where possible.

    What to do in an assessment

    • Describe pattern with data, identify uncertainty/confounders and judge whether evidence supports a causal explanation.

    In plain language

    Environmental conditions can shift species ranges, but distribution data must be assessed carefully before naming a cause.

    Self-check

    Why does a map showing a species decline where a gas concentration rises not prove that gas caused the decline?

    Show the answer

    Other factors may vary too; correlation alone does not rule out confounding causes.

Topic group

B6.2 Food security

7 revision points
  • Core

    Scope: Core · §2c B6.2a

    Open revision guidance

    What to know

    • Food security means reliable access to sufficient, safe, nutritious food. It is affected by population growth, changing diets as wealth rises, new pests/pathogens, environmental change, sustainability and the cost of agricultural inputs.
    • These pressures interact: crop failure or expensive fertiliser can reduce supply and access even when global production is high.

    What to do in an assessment

    • Separate food availability from affordability/access and explain how a stated biological/economic factor affects each.

    In plain language

    Food security depends on producing enough food and ensuring people can obtain it sustainably.

    Self-check

    How can a new crop pathogen threaten food security?

    Show the answer

    It can reduce yield and supply, potentially raising prices and limiting access.

  • Core

    Scope: Core · §2c B6.2b

    Open revision guidance

    What to know

    • Hydroponics supplies mineral solutions without soil; biological control uses natural enemies of pests; fertilisers replace mineral nutrients; pesticides reduce pest damage. Gene technology may add useful crop traits.
    • Each can raise yield but may have costs: energy/water use, non-target harm, resistance, pollution, expense or ethical concern.

    What to do in an assessment

    • Compare the mechanism, yield benefit and environmental/economic trade-off for the named intervention.

    In plain language

    Different farming technologies can raise food output, but each needs assessment for cost and environmental effects.

    Self-check

    How does biological control reduce a pest population?

    Show the answer

    A natural enemy preys on, parasitises or infects the pest, reducing its abundance.

  • Core

    Scope: Core · §2c B6.2c

    Open revision guidance

    What to know

    • Humans select plants/animals with desired inherited characteristics, breed them and select suitable offspring over generations. This can increase yield, quality, disease resistance or useful livestock traits.
    • A limited breeding pool can reduce genetic variation and increase inherited health problems; environmental needs and animal welfare matter.

    What to do in an assessment

    • Describe selection across generations and evaluate the desired gain against loss of variation and welfare/ecological risks.

    In plain language

    People choose parents with useful traits so those traits become more common in later generations.

    Self-check

    Why can repeated selective breeding increase inherited health risks?

    Show the answer

    It narrows the gene pool and makes harmful alleles more likely to be inherited together.

  • Core

    Scope: Core · §2c B6.2d

    Open revision guidance

    What to know

    • Genetic engineering modifies an organism's genome to introduce a desired characteristic. A gene or DNA sequence is transferred/altered so the organism expresses a new trait.
    • It differs from selective breeding: engineering directly changes genetic material, while breeding selects existing variation over generations.

    What to do in an assessment

    • Define the genome modification and intended trait; do not call all breeding genetic engineering.

    In plain language

    Genetic engineering changes DNA directly to give an organism a chosen characteristic.

    Self-check

    What is the key difference between genetic engineering and selective breeding?

    Show the answer

    Engineering directly modifies DNA; selective breeding chooses parents with existing traits across generations.

  • Higher

    Scope: Higher · §2c B6.2e (Higher only)

    Open revision guidance

    What to know

    • A restriction enzyme cuts out the desired gene and opens a plasmid vector, producing matching sticky ends. DNA ligase joins the gene into the plasmid; the recombinant plasmid is transferred into host bacteria.
    • Bacteria are grown and selected using an antibiotic-resistance marker: cells carrying the plasmid survive the relevant antibiotic and can clone the inserted gene/express its product.

    What to do in an assessment

    • Sequence restriction enzyme → compatible sticky ends → ligase → plasmid/vector into host → selection; explain what the marker identifies.

    In plain language

    A gene is inserted into a plasmid and transferred to bacteria, then cells carrying the plasmid are selected.

    Self-check

    What does DNA ligase do in plasmid engineering?

    Show the answer

    It joins the gene fragment to the plasmid DNA.

  • Core

    Scope: Core · §2c B6.2f

    Open revision guidance

    What to know

    • Gene technology may improve yield, nutrition or pest/disease resistance, but outcomes depend on the engineered trait and farming system. Practical issues include expense, spread to wild relatives and effects on non-target organisms; ethical views include ownership, choice and fairness.
    • Do not assume genetic engineering necessarily increases pesticide use; assess evidence for each crop and context.

    What to do in an assessment

    • Evaluate benefits, practical feasibility, ecological uncertainty and ethical concerns separately; use evidence rather than a blanket claim.

    In plain language

    Genetic technology can help agriculture, but each application has its own costs, risks and ethical questions.

    Self-check

    Why is it inaccurate to say every GM crop increases pesticide use?

    Show the answer

    Effects depend on the engineered trait; a pest-resistant trait could change or reduce pesticide use, so evidence must be crop-specific.

  • Core

    Scope: Core · §2c B6.2g

    Open revision guidance

    What to know

    • Biotechnological solutions can include genetic modification of crops/livestock for yield, nutritional content or resistance, alongside other biological production methods. Their contribution to food security depends on reliable access, affordability and sustainability, not yield alone.
    • Compare a proposed solution with conventional approaches, local conditions and possible environmental impacts.

    What to do in an assessment

    • Explain how a specified biological trait could improve supply and identify evidence/constraints needed before adoption.

    In plain language

    Biotechnology may help produce more or better food, but its value depends on real-world access and sustainability.

    Self-check

    Why might a higher crop yield not by itself solve food insecurity?

    Show the answer

    People may still lack access or affordability, and production may be environmentally or economically unsustainable.

Topic group

B6.3 Health

24 revision points
  • Core

    Scope: Core · §2c B6.3a

    Open revision guidance

    What to know

    • Health includes physical and mental wellbeing; disease disrupts normal body structure or function and can reduce health. People can experience disease without all aspects of health being poor.

    What to do in an assessment

    • Explain health as broader than simply absence of infection; identify the biological effect of a named disease.

    In plain language

    Health is wellbeing; disease is a condition that disrupts normal function.

    Self-check

    Does health refer only to physical fitness?

    Show the answer

    No. It includes mental and social wellbeing as well as physical health.

  • Core

    Scope: Core · §2c B6.3b

    Open revision guidance

    What to know

    • Communicable diseases are caused by pathogens and can pass between organisms; non-communicable diseases do not spread between people as infections and may be linked to genes, lifestyle or environment.
    • A person can have both kinds at once; identify cause and transmission rather than classify by symptom alone.

    What to do in an assessment

    • Classify a disease and justify whether it is transmissible by a pathogen.

    In plain language

    Communicable diseases can spread between hosts; non-communicable conditions do not pass on as infections.

    Self-check

    Is cardiovascular disease communicable?

    Show the answer

    No; it is a non-communicable disease.

  • Core

    Scope: Core · §2c B6.3c

    Open revision guidance

    What to know

    • One disease can change susceptibility to another: HIV damages immune defence, increasing risk of infections such as tuberculosis. Some pathogens also contribute to non-communicable disease; persistent HPV infection can lead to cervical cell changes/cancer.
    • A pathogen-associated cancer is not spread from person to person as cancer; the infection may be transmissible.

    What to do in an assessment

    • Trace infection → body-system effect → increased risk of a second disease and keep pathogen transmission distinct from cancer itself.

    In plain language

    Diseases can interact; one infection may weaken defences or trigger changes that raise risk of another condition.

    Self-check

    Is cervical cancer itself contagious because HPV can be transmitted?

    Show the answer

    No. HPV infection can be transmitted; the cancer that may develop is not passed between people.

  • Core

    Scope: Core · §2c B6.3d

    Open revision guidance

    What to know

    • Viruses, bacteria, protists and fungi spread through routes such as air, water, direct contact, vectors, contaminated surfaces or plant vectors. Routes differ between animal and plant diseases.
    • Outbreak data may report pathogen numbers, infected cases and population size. For a representative sample, 24 positives among 120 tested is 20%; applied cautiously to a population of 1,000 it estimates about 200 cases. State the sampling interval and uncertainty; a biased sample does not support a reliable population estimate.

    What to do in an assessment

    • Identify pathogen type and route, then select a control measure that interrupts that route; calculate case rates with a stated denominator/time or estimate total cases from the positive proportion in a representative sample.

    In plain language

    Different pathogen groups spread by different routes, so disease control must target the actual route; representative case data can estimate outbreak size.

    Self-check

    A representative sample finds 18 infected people among 90 tested. Estimate the cases in a population of 2,000.

    Show the answer

    18 ÷ 90 = 0.20, so an estimate is 0.20 × 2,000 = 400 cases; the estimate depends on a representative sample.

  • Core

    Scope: Core · §2c B6.3e

    Open revision guidance

    What to know

    • Spread can be reduced by hygiene, sanitation, isolation, vector control, resistant plant varieties and vaccination where appropriate. Diagnosis may use symptoms/visual signs, antigen detection or pathogen-DNA tests.
    • Prevention targets transmission; diagnostic tests identify infection and do not themselves cure it.

    What to do in an assessment

    • Match control to route and host; interpret a positive antigen/DNA result as evidence of a target, considering test sensitivity/specificity.

    In plain language

    Prevent spread by interrupting transmission; use visual, antigen or DNA evidence to diagnose infection.

    Self-check

    Does a DNA test itself prevent transmission?

    Show the answer

    No. It detects pathogen genetic material; separate control measures are needed to reduce spread.

  • Core

    Scope: Core · §2c B6.3f

    Open revision guidance

    What to know

    • Know at least one human viral, bacterial and fungal infection; examples include influenza (viral), tuberculosis (bacterial) and ringworm (fungal). The specification's plant examples are tobacco mosaic virus (viral), barley powdery mildew, Erysiphe graminis (fungal), and crown gall, Agrobacterium tumefaciens (bacterial).
    • The source also requires sexually transmitted infections including HIV/AIDS. Match disease, pathogen group, host and relevant symptoms/transmission; HIV is the virus and AIDS is the condition caused by advanced HIV infection.

    What to do in an assessment

    • Build a table with disease → pathogen type → host → transmission/effect; do not confuse HIV infection with AIDS, the resulting condition.

    In plain language

    Disease examples must be linked to their pathogen group and host, not memorised as names alone.

    Self-check

    What pathogen type causes tobacco mosaic disease?

    Show the answer

    A virus.

  • Core

    Scope: Core · §2c B6.3g

    Open revision guidance

    What to know

    • A waxy leaf cuticle forms a barrier to pathogen entry and water loss; cellulose cell walls provide structural protection around plant cells. Damaged surfaces can provide entry points for infection.

    What to do in an assessment

    • Identify the physical barrier and explain how it reduces pathogen entry rather than killing pathogens chemically.

    In plain language

    The cuticle and cell wall make it harder for pathogens to enter plant tissues.

    Self-check

    Is the leaf cuticle a physical or chemical defence?

    Show the answer

    A physical barrier.

  • Core

    Scope: Core · §2c B6.3h

    Open revision guidance

    What to know

    • Plants can produce antimicrobial chemicals that inhibit or kill pathogens. These act alongside physical barriers and may be induced or present in particular tissues.

    What to do in an assessment

    • Distinguish antimicrobial chemical defence from cuticle/cell-wall barriers and explain its effect on pathogen growth.

    In plain language

    Some plants make chemicals that hinder microbes attacking their tissues.

    Self-check

    What is the role of an antimicrobial plant substance?

    Show the answer

    It inhibits or kills microorganisms, reducing infection.

  • Higher

    Scope: Higher · §2c B6.3i (Higher only)

    Open revision guidance

    What to know

    • In the field, plant disease can be diagnosed from visible symptoms and microscopy of samples. Laboratory tests can detect pathogen DNA or antigens, identifying the causal organism more specifically.
    • Symptoms may resemble nutrient deficiency or another pathogen, so a field diagnosis can require laboratory confirmation.

    What to do in an assessment

    • Compare field observation/microscopy with antigen/DNA testing; explain why the more specific test helps confirm identity.

    In plain language

    Visible signs suggest a plant disease; microscope or laboratory tests can identify the pathogen more reliably.

    Self-check

    Name two laboratory targets used to detect a plant pathogen.

    Show the answer

    Its DNA or an antigen.

  • Core

    Scope: Core · §2c B6.3j

    Open revision guidance

    What to know

    • Phagocytes engulf pathogens by phagocytosis; lymphocytes recognise antigens and produce specific antibodies, and some become memory cells. Antibodies bind matching antigens; antitoxins neutralise toxins.
    • Platelets are cell fragments that help blood clot, sealing wounds and limiting pathogen entry.

    What to do in an assessment

    • Match cell/component to defence action and distinguish antibody binding from phagocytosis and clotting.

    In plain language

    White blood cells attack or target pathogens; platelets help seal cuts.

    Self-check

    Which blood cells engulf pathogens?

    Show the answer

    Phagocytes, a type of white blood cell.

  • Core

    Scope: Core · §2c B6.3k

    Open revision guidance

    What to know

    • Skin and blood clotting form barriers; nose hairs and mucus trap particles; cilia move mucus from airways; stomach acid destroys many swallowed microbes. Tears and antimicrobial secretions also protect surfaces.
    • These defences act broadly rather than recognising one specific antigen.

    What to do in an assessment

    • Name the body site, its barrier/action and how it reduces pathogen entry or survival.

    In plain language

    Physical barriers, mucus, cilia and stomach acid block or remove many pathogens before infection.

    Self-check

    How do cilia help protect the lungs?

    Show the answer

    They move mucus containing trapped particles/pathogens toward the throat for removal.

  • Core

    Scope: Core · §2c B6.3l

    Open revision guidance

    What to know

    • Lymphocytes recognise foreign antigens and produce specific antibodies; antibodies bind matching antigens and help neutralise or mark pathogens. Some lymphocytes remain as memory cells, enabling a faster secondary response.
    • Phagocytes provide non-specific engulfing; immune defence combines specific and non-specific actions.

    What to do in an assessment

    • Explain antigen recognition → antibody response → pathogen neutralisation and distinguish first exposure from memory response.

    In plain language

    The immune system recognises pathogen markers and makes matching antibodies, then remembers some infections.

    Self-check

    Why can a second response to the same pathogen be faster?

    Show the answer

    Memory lymphocytes remain and rapidly produce the matching immune response.

  • Higher

    Scope: Higher · §2c B6.3m (Higher only)

    Open revision guidance

    What to know

    • Expose a lymphocyte to a target antigen so it produces a specific antibody; fuse it with a rapidly dividing tumour cell to form a hybridoma. Select and clone hybridoma cells, which produce identical antibodies against that one antigen.
    • The cloned antibodies can be collected and purified; production requires sterile controlled culture.

    What to do in an assessment

    • Sequence antigen exposure → antibody-producing lymphocyte → fusion → hybridoma selection/cloning → monoclonal antibody harvest.

    In plain language

    A hybridoma is cloned to mass-produce one type of antibody that binds one target.

    Self-check

    Why fuse a lymphocyte with a tumour cell?

    Show the answer

    The lymphocyte makes the specific antibody; the tumour cell enables rapid division so many copies can be produced.

  • Higher

    Scope: Higher · §2c B6.3n (Higher only)

    Open revision guidance

    What to know

    • A monoclonal antibody binds one target antigen. In pregnancy tests it detects hCG; labelled antibodies can help detect disease markers such as prostate-cancer antigens; targeted antibodies may deliver treatment to cancer cells.
    • Tests need controls and interpretation because a detected marker is evidence, not always a complete diagnosis.

    What to do in an assessment

    • Explain target binding and connect the labelled/therapeutic antibody to detection or treatment; assess benefits and possible effects on healthy cells.

    In plain language

    Monoclonal antibodies can locate a specific molecule for a test or guide a treatment toward target cells.

    Self-check

    What hormone is detected by a pregnancy test using antibodies?

    Show the answer

    Human chorionic gonadotrophin (hCG).

  • Core

    Scope: Core · §2c B6.3o

    Open revision guidance

    What to know

    • Vaccines expose the immune system to antigens safely so memory cells form and future response is faster. Antibiotics act against bacteria, antivirals interfere with viral processes, and antiseptics reduce microbes on living tissue/surfaces.
    • Antibiotics do not treat viral infections; unnecessary use selects antibiotic-resistant bacteria.

    What to do in an assessment

    • Choose a medicine for pathogen type and explain prevention (vaccine) versus treatment; avoid claiming an antibiotic cures a cold.

    In plain language

    Vaccines prepare immune memory; antibiotics target bacteria, antivirals target viruses and antiseptics reduce microbes locally.

    Self-check

    Will an antibiotic treat influenza virus?

    Show the answer

    No. Antibiotics target bacteria, not viruses.

  • Core

    Scope: Core · §2c B6.3p

    Open revision guidance

    What to know

    • Aseptic practice limits contamination of cultures and exposure to microbes: disinfect bench, use sterile tools/media, keep lids close, avoid contact with agar and secure plates inverted. Alcohol, flaming and autoclaving sterilise equipment/media under suitable protocols.
    • Work around a Bunsen burner only when required by the approved method: the warm rising air can reduce airborne particles falling onto the medium. Keep containers open for the shortest time, do not touch sterile agar or swab surfaces, and use an autoclave to sterilise suitable glassware and growth media under the centre's protocol.
    • Use approved school risk controls; cultures are incubated under safe prescribed conditions and disposed of correctly.

    What to do in an assessment

    • Explain how alcohol/disinfection, flaming, autoclaving, brief opening and careful work near the flame reduce contamination; read inhibition-zone data without opening cultures.

    In plain language

    Sterile equipment, limited exposure and safe handling keep cultures uncontaminated and reduce risk.

    Self-check

    Why keep a culture-plate lid closed as much as possible?

    Show the answer

    To reduce airborne contamination and exposure to microorganisms.

  • Core

    Scope: Core · §2c B6.3q

    Open revision guidance

    What to know

    • Potential medicines undergo preclinical tests on cells/tissues and then suitable animals to assess toxicity, dose and biological effect. Clinical trials begin with small numbers of healthy volunteers for safety/dose, then patients to test efficacy and side effects.
    • Randomisation, control/placebo groups and blinding reduce bias; trial evidence is reviewed before approval and continued monitoring may find rare effects.

    What to do in an assessment

    • Order preclinical → phased clinical tests → evaluation/approval; explain why a control and blinding improve reliability.

    In plain language

    New medicines are tested for safety first and then for effectiveness in people through controlled trials.

    Self-check

    Why may a clinical trial include a placebo control?

    Show the answer

    To compare outcomes and separate a medicine effect from expectation or natural recovery.

  • Core

    Scope: Core · §2c B6.3r

    Open revision guidance

    What to know

    • Many non-communicable diseases arise through interactions among inherited predisposition, behaviour and environment. Examples include cardiovascular disease, many cancers, bronchitis, cirrhosis and nutrition-influenced conditions such as type 2 diabetes.
    • A risk factor changes probability; it does not mean every exposed person will develop disease.

    What to do in an assessment

    • For a named disease, identify multiple contributing factors and use risk rather than certainty language.

    In plain language

    Several genetic, lifestyle and environmental factors can combine to affect disease risk.

    Self-check

    Does a risk factor guarantee that a person will develop a disease?

    Show the answer

    No. It changes likelihood; outcomes also depend on other factors.

  • Core

    Scope: Core · §2c B6.3s

    Open revision guidance

    What to know

    • Cardiovascular risk may be reduced through lifestyle change, medicines such as statins and surgical procedures such as stents or bypass. Each differs in invasiveness, speed, effectiveness, side effects and suitability.
    • Statins lower blood cholesterol; a stent keeps a narrowed artery open; bypass routes blood around a blockage.

    What to do in an assessment

    • Compare treatment mechanism, evidence, risks and long-term management rather than ranking options without patient context.

    In plain language

    Lifestyle, medicines and surgery can lower cardiovascular risk or restore blood flow, with different trade-offs.

    Self-check

    What does a coronary stent do?

    Show the answer

    It holds a narrowed artery open to improve blood flow.

  • Core

    Scope: Core · §2c B6.3t

    Open revision guidance

    What to know

    • Exercise, diet, alcohol and smoking can affect non-communicable disease incidence at local, national and global levels. For example smoking increases risk of lung disease and cardiovascular disease; diet/activity influence obesity and type 2 diabetes risk.
    • Population data show association, not necessarily causation; age, income, healthcare and other confounders may differ.

    What to do in an assessment

    • Read scale and denominator, describe correlation with values, distinguish incidence from prevalence and avoid claiming a single factor proves cause.

    In plain language

    Lifestyle patterns can change disease risk across populations, but comparisons need careful interpretation.

    Self-check

    Why does a correlation between smoking rates and cancer not alone prove cause?

    Show the answer

    Other factors may confound the relationship; stronger evidence and biological mechanism are also considered.

  • Core

    Scope: Core · §2c B6.3u

    Open revision guidance

    What to know

    • Cancer results from changes in cells that disrupt normal control of growth and division. Affected cells divide uncontrollably and may form a tumour; malignant cells can invade and spread.
    • Cancer is not generally inherited as a disease itself, though inherited variants can alter susceptibility.

    What to do in an assessment

    • Explain cancer through altered cell-cycle control and distinguish a tumour from the mutations/risk factors that produced it.

    In plain language

    Cancer cells lose normal division controls and can form tumours or spread.

    Self-check

    What change in cells leads to cancer?

    Show the answer

    Changes disrupt control of growth and division, causing uncontrolled multiplication.

  • Core

    Scope: Core · §2c B6.3v

    Open revision guidance

    What to know

    • Stem cells may replace cells damaged by disease/injury, offering treatment for conditions where specialised cells are lost. Transplants can be rejected because donor cells carry foreign antigens; immunosuppressants reduce rejection but increase infection risk.
    • Embryo use raises ethical concerns; adult or induced stem-cell sources have different potential and limitations.

    What to do in an assessment

    • Balance potential repair benefit, evidence, rejection, infection and source ethics; state whose interests/values differ.

    In plain language

    Stem cells might repair damaged tissue, but rejection, safety and ethical questions matter.

    Self-check

    Why may a transplanted stem-cell tissue be rejected?

    Show the answer

    Its antigens may be recognised as foreign by the recipient's immune system.

  • Core

    Scope: Core · §2c B6.3w

    Open revision guidance

    What to know

    • Gene technology can make human proteins such as insulin or modify cells to address disease. Potential benefits include targeted or more reliable treatment; risks include unintended changes, uncertain long-term effects, delivery difficulty and unequal access.
    • Practical and ethical considerations include safety, consent, privacy and who receives benefits.

    What to do in an assessment

    • Evaluate a specified application by intended benefit, evidence/safety, unintended effects and ethical/practical constraints.

    In plain language

    Changing or using genes can support medical treatment, but safety and fairness require careful assessment.

    Self-check

    Name one ethical issue in medical gene technology.

    Show the answer

    Consent, genetic privacy, fairness of access or potential effects on future generations.

  • Core

    Scope: Core · §2c B6.3x

    Open revision guidance

    What to know

    • Genome information may help estimate genetic susceptibility to disease and identify molecular targets for medicines tailored to particular variants. A predicted likelihood is not certainty that a person will develop disease.
    • Benefits must be weighed against privacy, discrimination, uncertain prediction and unequal access to targeted treatment.

    What to do in an assessment

    • Distinguish risk prediction from diagnosis, and explain how a drug target linked to a genome could support more personalised treatment.

    In plain language

    Genome knowledge may help predict risk and choose targeted drugs, but prediction is not destiny.

    Self-check

    Does a genetic risk result guarantee disease?

    Show the answer

    No. It estimates likelihood; environment, other genes and chance also matter.

Earlier topic checklist

These earlier topic ticks are separate from the reviewed points above and do not count towards that progress.

Biology topic list

This is a topic overview, not a complete specification checklist. Check the official course for all assessed content, options and your exam year.

The initial headings match Biology A (Gateway Science, J247), not Biology B. Other headings are broader than the official specification; confirm your course before using this overview.

Tick each item off as you revise. Ticks are saved on this device only.

These ticks keep your earlier topic checklist. They do not count towards the new reviewed requirements above. Its numbering may be internal; use the linked references above for the exact reviewed source requirements.

Foundation tier topics

Higher tier topics

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