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AQA · GCSE separate Biology

AQA GCSE Biology Revision

A topic-by-topic revision guide for the written papers. Read the explanation, try the self-check, then mark a point revised when you have worked through it.

Self-checks and worked examples are original practice, not official AQA exam questions.

8461 qualificationPaper 1 · Topics 4.1 to 4.4Paper 2 · Topics 4.5 to 4.7Checked exam years · 2027

Tick a point after revising it. Progress is local to this device and does not measure mastery.

AQA Biology · written assessment

Revision points, with the explanation beside them

Each point opens into what to learn, how to use it in an exam, and a short self-check. Answers stay hidden until you choose to reveal them.

Topic 4.1

Cell biology

Paper 113 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.1.1

    Open revision guidance

    What to know

    • Plant and animal cells are eukaryotic: each has a cell membrane, cytoplasm and genetic material enclosed in a nucleus.
    • Bacteria are prokaryotic and much smaller than eukaryotic cells. They have cytoplasm and a cell membrane surrounded by a cell wall; their genetic material is not enclosed in a nucleus.
    • A bacterium has one DNA loop and may also have one or more small rings of DNA called plasmids. A cell without a nucleus therefore still has genetic material.
    • Cell sizes span very different scales. Use centi-, milli-, micro- and nano- prefixes and standard form when comparing very small measurements; order-of-magnitude comparisons describe approximate powers of ten.

    What to do in an exam

    • Compare a plant/animal cell with a bacterial cell by naming structures and explaining the key distinction in where DNA is found.
    • For a scale question, put both measurements in compatible units, express them as powers of ten if useful, then state the approximate size ratio and what it means.

    In plain language

    The label prokaryote means that bacterial DNA is not inside a nucleus; it does not mean the cell has no DNA. A bacterium’s main DNA loop lies in the cytoplasm, and extra small DNA rings may be present as plasmids. Eukaryotic plant and animal cells keep their genetic material in a nucleus. Bacteria are also much smaller, so powers-of-ten notation makes the scale difference easier to compare.

    Self-check

    A eukaryotic cell is about 10 µm across and a bacterium is about 1 µm across. What is their approximate size ratio, and does the bacterium lack genetic material?

    Show the answer

    The eukaryotic cell is about ten times wider (10:1). No: a bacterium has a DNA loop and may also have plasmids, although neither is enclosed in a nucleus.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.1.2

    Open revision guidance

    What to know

    • Most animal cells have a nucleus, cytoplasm, cell membrane, mitochondria and ribosomes. The nucleus contains genetic material; the membrane controls exchange; cytoplasm is where many reactions occur; mitochondria are the site of aerobic respiration; ribosomes make proteins.
    • Plant cells have these animal-cell structures and often have chloroplasts and a permanent, cell-sap-filled vacuole. Chloroplasts are where photosynthesis occurs. The vacuole helps maintain cell contents and support.
    • Plant and algal cells also have a cellulose cell wall, which strengthens the cell. Bacterial plasmids are small circular DNA molecules separate from the main DNA loop. They can carry additional genes, potentially including genes for antibiotic resistance; they are not plant or animal cell structures.
    • Students must estimate and explain when estimates are useful for judging relative size or area of sub-cellular structures. Required practical 1 uses a light microscope to observe, draw and label selected plant and animal cells and include a magnification scale.

    What to do in an exam

    • Identify structures in a micrograph or diagram, then relate each named structure to its function. Distinguish a bacterial plasmid from structures in plant and animal cells, and explain how plasmid genes can give a bacterium an additional characteristic such as antibiotic resistance.
    • In practical drawings use clear single lines, labels and a magnification scale; make an estimate of relative size or area when exact measurement is not appropriate.

    In plain language

    A cell diagram is useful when it links a structure to a job. For example, a chloroplast absorbs light for photosynthesis, while mitochondria are where aerobic respiration occurs. A cellulose wall strengthens plant and algal cells. Bacterial plasmids are extra small DNA circles that can carry genes, sometimes including antibiotic-resistance genes. In the microscope practical, draw what you see clearly and estimate relative size or area when exact measurement is not appropriate.

    Self-check

    What can a bacterial plasmid do, and why might it matter when bacteria are exposed to an antibiotic?

    Show the answer

    A plasmid can carry additional genes, potentially including an antibiotic-resistance gene. A bacterium with that gene may be resistant to that antibiotic.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.1.3

    Open revision guidance

    What to know

    • Cells may be specialised for a particular function. Required animal examples are sperm cells, nerve cells and muscle cells; required plant examples are root hair cells, xylem cells and phloem cells.
    • The assessed skill is to use information provided to explain how the structures of different cell types relate to their functions in a tissue, organ, organ system or whole organism.
    • A good adaptation explanation names a structural feature and connects it to a specific advantage for the cell’s task; it is not enough to list a shape or say the cell is specialised.

    What to do in an exam

    • For an unfamiliar labelled cell, identify a feature in the supplied information and build a feature → effect → function explanation.
    • For familiar examples, connect the cell’s role to its location and the larger process, such as root-hair uptake or transport in plant tissues.

    In plain language

    Specialisation means a cell’s structure suits its job. A long extension is useful only if you explain what it allows the cell to do. In an exam, follow the chain from structure to what that structure enables, then to the function in the tissue or organism. The specification expects application to information provided, so use evidence from an unfamiliar diagram rather than relying on memorised labels alone.

    Self-check

    A root hair cell has a long projection. How should you explain why this structure is useful?

    Show the answer

    The projection gives the cell a large surface area in contact with soil, helping it absorb water and mineral ions efficiently.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.1.4

    Open revision guidance

    What to know

    • As an organism develops, cells differentiate and become different cell types. A cell differentiates by acquiring different sub-cellular structures that enable it to carry out a particular function; it becomes specialised.
    • Most types of animal cell differentiate at an early stage. Many types of plant cell retain the ability to differentiate throughout the plant’s life.
    • In mature animals, cell division is mainly restricted to repair and replacement. Differentiation is distinct from cell division: it changes the cell’s specialisation rather than simply making another cell.

    What to do in an exam

    • Explain why differentiation is important by linking it to the formation of specialised cell types needed for different functions.
    • When comparing organisms, state the different capacity and timing of differentiation in animals and plants without claiming that every plant cell or every animal cell behaves identically.

    In plain language

    An organism needs cells with different jobs, so development includes cells acquiring structures suited to their roles. That process is differentiation. A differentiated cell is specialised. Most animal cell types become specialised early, while many plant cell types can still differentiate throughout life. In mature animals, cell division is chiefly for repair and replacement; that is a different process from a cell changing into a specialised type.

    Self-check

    How does differentiation produce a specialised cell, and how does the pattern differ in plants and animals?

    Show the answer

    The cell acquires sub-cellular structures suited to a particular function. Most animal cell types differentiate early, while many plant cells retain the ability to differentiate throughout life.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.1.5

    Open revision guidance

    What to know

    • Microscopy techniques developed over time. For this specification the comparison is limited to magnification and resolution: an electron microscope has much higher magnification and resolving power than a light microscope, revealing finer detail and more sub-cellular structures.
    • Magnification = size of image ÷ size of real object. Rearrange as needed: image size = magnification × real size; real size = image size ÷ magnification. The image and real size must be expressed in the same units before division.
    • Use centi-, milli-, micro- and nano- prefixes and powers of ten to convert units; express a very large or small answer in standard form when appropriate. Magnification has no units.

    What to do in an exam

    • In a calculation, write the formula, convert both sizes to the same unit, substitute, calculate and give a sensible magnification or size with units where relevant.
    • Distinguish magnification (how much larger an image is) from resolution (ability to distinguish close points). Explain what extra detail improved resolution makes visible.

    In plain language

    A larger image does not automatically contain more detail. Magnification tells how much the image has been enlarged; resolution tells whether two nearby points can be seen as separate. Electron microscopes have much greater magnification and resolving power than light microscopes, which improved understanding of cell structures. For calculations, unit conversion comes first: dividing millimetres by micrometres without converting gives a wrong result.

    Self-check

    An image is 4 mm long and the real object is 20 µm long. Calculate magnification. Why do the units need converting?

    Show the answer

    4 mm = 4000 µm, so magnification = 4000 ÷ 20 = ×200. Both values must use the same unit for the ratio to be valid.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.1.6

    Open revision guidance

    What to know

    • With enough nutrients and a suitable temperature, bacteria can divide by binary fission as often as every 20 minutes. They can be grown in nutrient broth or as colonies on nutrient agar.
    • Uncontaminated cultures are needed to investigate disinfectants and antibiotics. Sterilise Petri dishes and culture medium before use to kill contaminating microorganisms. Sterilise an inoculating loop by passing it through a flame to kill microorganisms before transfer. Secure the Petri-dish lid with adhesive tape so it cannot fall off and increase contamination or exposure risk; store the dish upside down so condensation collects on the lid rather than dripping onto and spreading the colonies. School cultures should generally be incubated at 25 °C, a lower temperature than the human body that reduces the chance of growing many human pathogens; it reduces risk but does not make a culture harmless.
    • Calculate a circular colony or clear-zone cross-sectional area using area = πr². Given mean division time, work out the number of divisions and resulting population after a time; each division doubles the population.
    • Required practical 2 tests antiseptics or antibiotics on bacterial growth on agar plates and measures zones of inhibition.

    What to do in an exam

    • Explain how sterilising dishes, media and the loop prevents contamination, how securing and inverting the plate limit exposure and unwanted spreading, and why the specified lower incubation temperature reduces risk. Use teacher-approved safe handling and do not treat a 25 °C culture as harmless.
    • For growth, divide elapsed time by division time to find generations, then multiply the starting population by 2 for each generation. For a zone, measure radius and apply πr², not πd².

    In plain language

    A culture must contain the intended microorganism alone so that any growth difference can be linked to the treatment. Sterile dishes, media and loops limit contamination. Tape holds the lid in place, and storing the plate upside down helps prevent condensation spreading colonies. School plates are generally incubated at 25 °C rather than body temperature to reduce the risk of growing many human pathogens, but cultures must still be handled safely. Keep radius distinct from diameter in area calculations.

    Self-check

    Why are a school bacterial culture plate incubated at 25 °C and stored upside down?

    Show the answer

    The 25 °C incubation temperature reduces the chance of growing many human pathogens, while inverting the plate prevents condensation from the lid dripping onto and spreading the colonies.

  • Higher

    Scope: Higher · 4.1.1.6

    Open revision guidance

    What to know

    • For the bacterial population calculation in 4.1.1.6, Higher-tier students should be able to express the answer in standard form. Standard form is a × 10ⁿ, where 1 ≤ a < 10 and n is an integer.
    • Find the number of binary-fission generations first, then calculate the population by doubling for each generation. Convert the final value into standard form only after calculating it.

    What to do in an exam

    • Write a population such as 3,200,000 as 3.2 × 10⁶, with the first number at least 1 and less than 10.
    • Check that converting back gives the original population and retain appropriate significant figures for the data given.

    In plain language

    This Higher-only addition is about how to report a large result, not a different bacterial growth process. A population of 3,200,000 is 3.2 million, written in standard form as 3.2 × 10⁶. Count the powers of ten carefully and make sure the coefficient is between 1 and 10.

    Self-check

    Write 48,000,000 bacteria in standard form.

    Show the answer

    4.8 × 10⁷ bacteria.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.2.1

    Open revision guidance

    What to know

    • The nucleus contains chromosomes, which are made of DNA molecules. Each chromosome carries a large number of genes.
    • In body cells, chromosomes are normally found in pairs. Models and analogies can help explain their organisation, but should not replace the biological relationship: genes are carried on chromosomes and chromosomes consist of DNA.
    • This leaf concerns chromosomes and genes, not the stages of mitosis or the details of inheritance.

    What to do in an exam

    • On a cell or nucleus diagram, identify where chromosomes are located and state what chromosomes are made of.
    • Use the sequence nucleus → chromosomes → DNA → many genes on each chromosome to explain their organisation; mention paired chromosomes for a body cell.

    In plain language

    Think of a chromosome as a long DNA molecule carrying many genes. The nucleus contains chromosomes, and the chromosomes in most body cells occur in pairs. A gene is not a separate cell structure floating beside the chromosome: it is a section of DNA on a chromosome.

    Self-check

    Where are chromosomes found, what are they made of, and what do they carry?

    Show the answer

    They are found in the nucleus, are made of DNA molecules, and each carries many genes.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.2.2

    Open revision guidance

    What to know

    • The cell cycle has three overall stages: the cell grows and increases sub-cellular structures such as ribosomes and mitochondria; its DNA replicates to make two copies of each chromosome; then the cell divides.
    • During mitosis one set of chromosomes is pulled to each end of the cell and the nucleus divides. Finally the cytoplasm and cell membrane divide, producing two genetically identical cells.
    • Students need the overall stages, not the names or details of the different phases within mitosis. Mitosis supports growth and development of multicellular organisms; it also occurs in contexts such as repair and replacement.

    What to do in an exam

    • Describe the events in sequence, distinguishing DNA replication before mitosis from chromosome separation during mitosis and division of cytoplasm/membrane afterwards.
    • Recognise from a given context when mitosis is occurring, and explain why growth of a multicellular organism requires production of new cells.

    In plain language

    Before a cell splits, it must build up enough cell contents and copy its DNA. Mitosis separates the two chromosome sets so each new nucleus receives one set. The cell then divides its cytoplasm and membrane. The result is two identical cells. Do not add detailed phase names: AQA limits the required account to the three broad stages.

    Self-check

    Put these events in order: cytoplasm divides; DNA replicates; chromosomes move to opposite ends; cell grows and increases sub-cellular structures.

    Show the answer

    The cell grows and increases sub-cellular structures; DNA replicates; chromosomes move to opposite ends and the nucleus divides; the cytoplasm and membrane divide.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.2.3

    Open revision guidance

    What to know

    • A stem cell is an undifferentiated cell able to produce more cells of the same type and, by differentiation, certain other cell types. Human embryonic stem cells can be cloned and made to differentiate into most human cell types; adult bone-marrow stem cells can form several types, including blood cells.
    • Plant meristem stem cells can differentiate into any plant cell type throughout the plant’s life. Meristem stem cells can rapidly and economically clone plants, including rare species for conservation and crop plants with useful features such as disease resistance.
    • Stem-cell treatment may help conditions such as diabetes and paralysis. Therapeutic cloning makes an embryo with the patient’s genes, so its stem cells may not be rejected. Risks include transfer of viral infection; ethical or religious objections also arise. Stem-cell techniques themselves are not required knowledge.

    What to do in an exam

    • When evaluating treatment, balance possible benefit against medical risk and social/ethical concern; do not present a possible treatment as a guaranteed cure.
    • For plant cloning, explain how many genetically identical plants can be produced and connect the example to conservation or crop production.

    In plain language

    Different sources of stem cells have different potential. Meristem cells in plants retain broad differentiation ability, while adult bone-marrow cells can make several cell types and embryonic cells can make most human cell types. Therapeutic cloning aims to reduce rejection by matching the patient’s genes, but it does not remove every risk or ethical concern. A balanced answer distinguishes what the cells might help with from what is certain.

    Self-check

    Why might stem cells from a therapeutically cloned embryo be less likely to be rejected, and name one separate concern.

    Show the answer

    The embryo has the same genes as the patient, so its stem cells may be recognised as compatible. A possible concern is viral infection transfer or an ethical/religious objection.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.3.1

    Open revision guidance

    What to know

    • Diffusion is the spreading of particles in solution or gas that gives a net movement from higher to lower concentration. Examples are oxygen and carbon dioxide in gas exchange and urea moving from cells into blood plasma for kidney excretion. Rate increases with a steeper concentration gradient, higher temperature or larger exchange surface area, provided other conditions stay the same.
    • A unicellular organism has a large surface-area-to-volume ratio, allowing enough molecules to enter and leave to meet its needs. As organisms get larger, this ratio falls, so multicellular organisms need specialised exchange surfaces and transport systems.
    • The small intestine has many villi, which greatly increase surface area. Each villus has a thin, one-cell-thick surface and a rich capillary blood supply; blood carries absorbed substances away and maintains a concentration gradient. Fish gills have many filaments bearing lamellae. The many thin lamellae provide a large surface close to a dense blood supply; water flow over the gills and blood flow support gas exchange. A leaf is broad and thin, giving a large surface and short diffusion paths. Stomata allow gases to enter and leave, and air spaces among mesophyll cells expose moist cell surfaces to carbon dioxide and oxygen.
    • Other specified exchange surfaces include mammalian lungs, plant roots and leaves. Isotonic and high-energy drinks in sport are application contexts.

    What to do in an exam

    • Illustrative cube calculation, not an AQA exam value: a cube 1 mm on each side has surface area 6 mm² and volume 1 mm³, so its SA:V is 6 mm⁻¹. A cube 2 mm on each side has surface area 24 mm² and volume 8 mm³, so its SA:V is 3 mm⁻¹. Doubling side length halves the ratio.
    • For a question about a named surface, connect its large area, thin barrier or blood/water flow to a faster diffusion rate or maintained concentration gradient. Interpret net particle movement from high to low concentration.

    In plain language

    Diffusion moves particles overall from where their concentration is higher to where it is lower. Thin, broad exchange surfaces provide lots of contact and a short route, while blood or water flow helps maintain the difference in concentration. Villi absorb digested molecules, gill lamellae exchange gases, and a leaf's stomata and internal air spaces connect the outside air to moist mesophyll surfaces. A bigger organism has less surface area compared with its volume, which is why it needs specialised exchange surfaces.

    Self-check

    An illustrative cube grows from 1 mm to 2 mm on each side. How do its SA:V values compare, and name one adaptation that helps a fish exchange gases?

    Show the answer

    The 1 mm cube has SA:V 6 mm⁻¹ and the 2 mm cube 3 mm⁻¹, so doubling side length halves SA:V. Fish gill filaments have many thin lamellae with a rich blood supply and water flow.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.3.2

    Open revision guidance

    What to know

    • Osmosis is the diffusion of water from a dilute solution to a concentrated solution through a partially permeable membrane. It is net water movement; the membrane allows water through but restricts some dissolved particles.
    • A water-uptake rate is a change in water uptake divided by time. Percentage mass change = (final mass − initial mass) ÷ initial mass × 100. A negative value is a percentage loss; a positive value is a percentage gain.
    • Required practical 3 investigates how different salt or sugar concentrations affect plant-tissue mass. The specification also requires plotting, drawing and interpreting appropriate graphs.

    What to do in an exam

    • Measure mass before and after immersion, calculate signed change and percentage using the initial mass as denominator, and relate mass gain/loss to net water movement into/out of cells.
    • Plot concentration against a clearly labelled response, use a suitable scale and interpret trends. Control tissue dimensions, immersion time, solution volume/concentration and temperature; blot surface liquid consistently before weighing.

    In plain language

    Water can cross a partially permeable membrane by osmosis. If water leaves plant cells, the sample usually loses mass; if water enters, its mass usually increases. Percentage change allows samples with different starting masses to be compared fairly. Keep the sign of the answer: −10% represents a loss, not a gain. A graph near zero change indicates little net mass change under those conditions.

    Self-check

    A plant sample starts at 2.0 g and ends at 1.8 g. What is its percentage mass change?

    Show the answer

    (1.8 − 2.0) ÷ 2.0 × 100 = −10%, so it lost 10% of its initial mass.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.1.3.3

    Open revision guidance

    What to know

    • Active transport moves substances from a more dilute solution to a more concentrated solution, against the concentration gradient, and requires energy from respiration.
    • In plants it allows mineral ions to enter root hair cells from very dilute soil solutions; plants need these ions for healthy growth. In the gut, sugar molecules can move from a lower concentration into blood at a higher concentration, and are used in cellular respiration.
    • Distinguish the three transport processes: diffusion is net particle movement down a concentration gradient; osmosis is water diffusion through a partially permeable membrane; active transport moves substances against a gradient using energy.

    What to do in an exam

    • For any example, identify what moves, its direction relative to the gradient, whether a partially permeable membrane is part of the definition, and whether energy is required.
    • Explain why root uptake or gut sugar absorption can continue when diffusion alone would not give the required direction.

    In plain language

    Diffusion and osmosis produce net movement down a concentration gradient, while active transport can move substances in the opposite direction. That uphill movement needs energy transferred by respiration. Osmosis specifically concerns water crossing a partially permeable membrane; active transport can move mineral ions or sugar molecules. Use these differences, not just the word ‘transport’, to identify the process in an exam.

    Self-check

    Mineral ions move from dilute soil into a root hair cell where their concentration is already higher. Which process is this and why?

    Show the answer

    Active transport, because ions move against their concentration gradient and the movement requires energy from respiration.

Topic 4.2

Organisation

Paper 110 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.1

    Open revision guidance

    What to know

    • Cells are the basic building blocks of living organisms. A tissue is a group of cells with a similar structure and function.
    • An organ is an aggregation of tissues performing specific functions. Organs are organised into organ systems, which work together to form an organism.
    • The scale relationship applies across cells, tissues, organs and systems: each level is made from or coordinates the level below it, but tissues contain similar-functioning cells while organs combine different tissues.

    What to do in an exam

    • Classify an example by asking whether it is a cell, a group of similar-functioning cells, several tissues working together, or cooperating organs.
    • Use a clear hierarchy, for example muscle cell → muscle tissue → heart → circulatory system → organism, and explain each link rather than only listing names.

    In plain language

    Living things are organised in levels. Similar cells cooperate in a tissue, several tissues form an organ, and organs work together in an organ system. The heart is an organ because it contains different tissues, not a group of only one cell type. Being able to move between these scales helps explain how a structure contributes to a whole-body function.

    Self-check

    Why is the heart an organ rather than a tissue?

    Show the answer

    It is made of different tissues that work together to pump blood, whereas a tissue is a group of cells with similar structure and function.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.2.1

    Open revision guidance

    What to know

    • Digestive organs work together to digest food and absorb soluble products. Enzymes are proteins that catalyse specific reactions because a substrate fits an enzyme's active site. Lock-and-key is a simplified model. Enzyme activity depends on temperature and pH; equations are required as simple word equations, not chemical-symbol equations.
    • Amylase breaks starch into simple sugars. It is produced by the salivary glands, pancreas and small intestine, and acts in the mouth and small intestine. Proteases break proteins into amino acids. They are produced by the stomach, pancreas and small intestine, and act in the stomach and small intestine. Lipases break lipids into glycerol and fatty acids. They are produced by the pancreas and small intestine and act mainly in the small intestine.
    • Each enzyme has a temperature and pH range in which it works, with an optimum where its activity is greatest. At low temperature molecules move more slowly, so there are fewer successful enzyme-substrate collisions; warming towards the optimum increases rate. Above an enzyme's optimum temperature, bonds maintaining its shape can change, altering the active site so the substrate no longer fits. The enzyme is denatured. A pH away from the optimum changes the active site's shape and lowers activity; extreme pH can denature the enzyme. Different enzymes have different pH optima.
    • Digested soluble molecules are absorbed into blood and used to build carbohydrates, lipids and proteins; some glucose is used in respiration. Bile is made by the liver, stored in the gall bladder, is alkaline and neutralises stomach hydrochloric acid. It emulsifies fat into small droplets, increasing surface area; the alkaline conditions and larger area increase the rate of fat breakdown by lipase. Students calculate reaction rates.

    What to do in an exam

    • For each enzyme, name its substrate, product, production site and action site. Explain a temperature or pH graph by identifying the optimum and distinguishing a slower rate from low temperature from denaturation at high temperature or extreme pH.
    • Calculate reaction rate as quantity changed divided by time, with appropriate units. For practical 4 use Benedict's for sugars, iodine for starch and Biuret for protein. For practical 5 test starch with iodine every 30 seconds as amylase digests it across a pH range while controlling temperature.

    In plain language

    Digestion turns large food molecules into small soluble ones that can be absorbed. Each enzyme has its own job and production sites. Enzymes work fastest near their own optimum temperature and pH. Cold conditions slow molecular movement, but excessive heat or an extreme pH changes the active site; when the enzyme is denatured, its substrate no longer fits. Bile is not an enzyme: it neutralises acid and breaks fat into droplets, giving lipase more surface to act on.

    Self-check

    Where is amylase produced, and why can very high temperature stop it catalysing starch digestion?

    Show the answer

    Amylase is produced by the salivary glands, pancreas and small intestine. High temperature can change its shape and active site so starch no longer fits; the enzyme is denatured.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.2.2

    Open revision guidance

    What to know

    • The heart pumps blood in a double circulatory system. The right ventricle pumps blood to the lungs for gas exchange; the left ventricle pumps it to the rest of the body. The aorta, vena cava, pulmonary artery, pulmonary vein and coronary arteries are the named heart-associated vessels required; heart-valve names are not required. Coronary arteries supply the heart muscle itself with oxygenated blood, including oxygen and glucose for respiration.
    • Lung knowledge is limited to the trachea, bronchi, alveoli and capillary network around alveoli. Alveoli have a large surface, very thin walls and a close capillary supply; ventilation and blood flow maintain concentration gradients for gas exchange.
    • A group of cells in the right atrium controls natural resting heart rate as a pacemaker. Artificial pacemakers are electrical devices used to correct irregular heart-rate patterns.
    • Arteries carry blood away from the heart under high pressure, so their walls are thick, muscular and elastic to withstand and maintain that pressure. Veins return blood at lower pressure; their large lumen reduces resistance and valves prevent backflow. Capillaries connect the small vessels to tissues; their walls are one cell thick, giving a short diffusion distance for exchange of materials between blood and cells.

    What to do in an exam

    • Trace blood through body → vena cava → right side → pulmonary artery → lung capillaries → pulmonary vein → left side → aorta → body. Add coronary arteries as the vessels supplying the heart muscle; explain pulmonary versus systemic flow.
    • Calculate blood-flow rate as volume divided by time. Explain how thick muscular elastic artery walls suit high pressure, how a wide lumen and valves suit return flow in veins, and how a one-cell-thick capillary wall supports exchange.

    In plain language

    The heart sends blood through two linked circuits: one to the lungs and one to the body. The right ventricle serves the lung circuit; the left ventricle supplies the body. Coronary arteries supply the heart muscle. Arteries have strong elastic walls because blood leaves the heart at high pressure. Veins return blood at lower pressure through a wide lumen and use valves to stop backflow. Capillaries have walls only one cell thick, so substances have a short distance to diffuse between blood and tissues.

    Self-check

    What do the coronary arteries supply, and how do a vein's lumen and valves help blood return to the heart?

    Show the answer

    Coronary arteries supply oxygenated blood to the heart muscle. A large vein lumen reduces resistance to flow, and valves prevent blood flowing backwards.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.2.3

    Open revision guidance

    What to know

    • Blood is a tissue. Plasma is the fluid in which red blood cells, white blood cells and platelets are suspended. Know the functions of all four components.
    • Red blood cells transport oxygen using haemoglobin and their shape/absence of a nucleus supports that role. White blood cells defend against pathogens. Platelets support clotting. Plasma transports dissolved substances and the cells themselves.
    • Students should recognise different blood-cell types in a photograph or diagram and explain how each is adapted to its function. Practical skill opportunity: observe and draw blood cells under a microscope. Blood products also provide a context for considering risk.

    What to do in an exam

    • Identify a blood cell using visible features, then connect a feature to its functional advantage rather than simply naming it.
    • In questions about blood products, weigh benefits against hazards using the evidence given; do not assume that all blood components perform the same transport role.

    In plain language

    Blood has a liquid component and several cell or cell-fragment components. Plasma carries dissolved materials; red blood cells are adapted to transport oxygen; white blood cells protect against infection; platelets help blood clot. An adaptation answer explains why a feature makes the particular job more effective. A diagram question may test recognition as well as function.

    Self-check

    Which component transports most oxygen, and which carries many dissolved substances?

    Show the answer

    Red blood cells transport oxygen using haemoglobin; plasma carries many dissolved substances.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.2.4

    Open revision guidance

    What to know

    • In coronary heart disease, fatty material builds up inside coronary arteries, narrowing them. Reduced blood flow means less oxygen reaches heart muscle. Stents keep coronary arteries open. Statins lower blood cholesterol and slow fatty-material deposition, reducing the rate at which further deposits build up.
    • A stent can improve blood flow quickly, but insertion is an invasive procedure with risks such as bleeding or a clot, and an artery can narrow again. Statins require ongoing use and can cause side effects such as muscle pain or digestive symptoms, so suitability and monitoring matter.
    • A faulty valve that does not open fully restricts forward blood flow and makes the heart work harder. A valve that leaks lets blood flow backwards, reducing efficient forward circulation. Biological replacement valves generally do not require lifelong anticoagulant medicine but may wear out and need replacement. Mechanical valves are durable but usually require lifelong anticoagulants, which raise bleeding risk.
    • A donor heart or heart-and-lung transplant may treat heart failure. Donor organs are limited, and rejection is possible, so recipients need immunosuppressant drugs that increase infection risk. An artificial heart may keep a patient alive while waiting for a transplant or allow the heart to rest during recovery, but it requires major surgery and can have complications such as infection, clots or device failure.

    What to do in an exam

    • Construct the causal chain fatty deposit → narrowed coronary artery → reduced blood and oxygen supply → impaired heart-muscle function. Connect a faulty valve to restricted forward flow or backflow and reduced pumping efficiency.
    • Evaluate each option by matching its purpose to the problem, then weighing benefit against a specific risk or limitation. For example, compare the durability of a mechanical valve with its anticoagulant-related bleeding risk, or compare transplant benefit with donor availability, rejection and immunosuppression.

    In plain language

    Treatments solve different problems and each has trade-offs. Stents open narrowed arteries, while statins reduce cholesterol and slow further deposits. Faulty valves can restrict flow or let blood leak backwards. Biological valves may wear out sooner, whereas mechanical valves last longer but normally mean lifelong anticoagulants and bleeding risk. Transplants can replace a failing heart, but donor organs are scarce and rejection must be controlled; an artificial heart can bridge to transplant or support recovery, but surgery and device complications are risks.

    Self-check

    What is one disadvantage of a biological replacement valve and one disadvantage of a mechanical replacement valve?

    Show the answer

    A biological valve may wear out sooner and need replacement. A mechanical valve is durable but usually requires lifelong anticoagulant medicine, which increases bleeding risk.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.2.5

    Open revision guidance

    What to know

    • Health is a state of physical and mental well-being. Communicable and non-communicable diseases are major causes of ill health; diet, stress and life situations can also strongly affect physical and mental health.
    • Different diseases can interact: immune-system defects increase susceptibility to infection; viruses living in cells can trigger cancers; pathogen-triggered immune reactions can cause allergies such as skin rashes and asthma; severe physical ill health can lead to depression or other mental illness.
    • For disease-incidence data, translate between graphical and numerical forms, construct and interpret frequency tables, diagrams, bar charts and histograms, use scatter diagrams to identify correlation, and understand sampling principles including epidemiological sampling.

    What to do in an exam

    • Choose an appropriate representation for a data set, label axes/units, extract comparisons and describe a scatter-graph correlation without claiming that correlation alone proves cause.
    • Evaluate how cases were sampled: consider whether the sample represents the population and how sampling affects a conclusion.

    In plain language

    Health includes both physical and mental well-being, and causes of ill health can interact. A disease may alter another body system, and non-disease factors such as stress or diet can also affect health. Epidemiological data describe patterns across people; the way people were selected matters. A scatter graph may show that two variables vary together, but that pattern by itself does not prove one caused the other.

    Self-check

    A scatter graph shows that disease incidence rises as another variable rises. What can you conclude, and what can you not conclude from that graph alone?

    Show the answer

    You can identify a positive correlation. The graph alone cannot establish that one variable causes the disease; sampling and other possible factors need consideration.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.2.6

    Open revision guidance

    What to know

    • Non-communicable diseases can impose human and financial costs on an individual, a local community, a nation or globally. Diet, alcohol and smoking can change disease incidence at local, national and global scales. Risk factors are linked to increased disease rates, but do not guarantee disease in every exposed person. A causal mechanism is established for some risk factors but not all, and diseases can arise from interacting factors.
    • Diet high in saturated fat can raise blood cholesterol and contribute to fatty deposits in coronary arteries; high salt intake can raise blood pressure. Regular exercise supports cardiovascular health, improves heart and circulation fitness, and reduces risk. Obesity is a risk factor for type 2 diabetes because excess body fat can make body cells less responsive to insulin, so blood glucose is not controlled as effectively.
    • Alcohol is processed by the liver; prolonged heavy drinking can damage liver cells, impair liver function and cause disease such as cirrhosis. Alcohol also acts on the brain and nervous system, impairing judgement, coordination and reaction time; long-term heavy drinking can damage brain function.
    • Smoking damages the lungs and airways, increases risk of lung disease and lung cancer, and raises cardiovascular risk. Carbon monoxide binds to haemoglobin and reduces oxygen carried in the blood, so less oxygen reaches the heart muscle. Nicotine stimulates the heart and narrows blood vessels, increasing strain on the cardiovascular system. Tobacco smoke also contains carcinogens that can cause mutations in cells.
    • Smoking during pregnancy exposes the fetus to harmful chemicals. Carbon monoxide reduces oxygen carried in the mother's blood, and nicotine narrows blood vessels, reducing oxygen and nutrient supply to the fetus; this can restrict fetal growth and increase risks such as low birth mass and premature birth. Alcohol crosses the placenta and can disrupt fetal growth and brain development, causing lifelong developmental harm. Carcinogens, including ionising radiation, are risk factors for cancer.
    • Apply sampling principles, translate graph and numerical information, extract and interpret charts and tables, and use a scatter diagram to identify correlation in risk-factor data.

    What to do in an exam

    • For each named lifestyle factor, explain the direction of the effect and give the biological link where known. Distinguish an established mechanism from an association, and account for interacting risk factors.
    • When interpreting risk data, read graph axes carefully, compare rates rather than only totals when appropriate, and describe correlation without treating population-level risk as certainty for an individual.

    In plain language

    Lifestyle can affect disease risk through changes to organs and body processes. For example, smoking can lower oxygen delivery and expose lung cells to carcinogens, while alcohol can damage the liver and impair brain function. During pregnancy these substances can reach or affect the fetus and interfere with growth and development. A risk factor changes probability; it is not a guarantee, and several influences may combine.

    Self-check

    How can smoking and alcohol each affect an unborn baby, and what happens to the liver with prolonged heavy alcohol use?

    Show the answer

    Smoking exposes the fetus to carbon monoxide and nicotine, reducing oxygen and nutrient supply and restricting growth. Alcohol crosses the placenta and can disrupt fetal and brain development. Prolonged heavy drinking can damage liver cells and cause cirrhosis.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.2.7

    Open revision guidance

    What to know

    • Cancer results from changes in cells that lead to uncontrolled growth and division.
    • A benign tumour is a growth of abnormal cells contained in one area, usually within a membrane, and does not invade other body parts. Malignant tumour cells are cancers: they invade neighbouring tissues and can spread in the blood to other parts of the body, where secondary tumours form.
    • Scientists have identified lifestyle risk factors for different cancers and genetic risk factors for some cancers. A risk factor is not a guarantee that an individual will develop cancer.

    What to do in an exam

    • Contrast benign and malignant tumours by containment, invasion and spread; do not define them only by tumour size.
    • Explain cancer as a consequence of altered cell control, and state whether evidence describes a risk factor rather than a certain cause for every individual.

    In plain language

    Normal cell division is controlled. Changes that disrupt this control can lead to uncontrolled growth. Benign growths stay in one region; malignant cells can invade nearby tissue and travel in blood to establish secondary tumours elsewhere. Lifestyle and inherited factors can influence risk, but risk is not certainty.

    Self-check

    What makes a malignant tumour different from a benign tumour?

    Show the answer

    Malignant cells invade neighbouring tissues and can spread in the blood to form secondary tumours; benign growths stay contained in one area.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.3.1

    Open revision guidance

    What to know

    • Students explain how plant-tissue structure relates to function. The named tissues are epidermal tissue, palisade mesophyll, spongy mesophyll, xylem, phloem and meristem tissue at growing tips of shoots and roots.
    • The leaf is a plant organ. Required leaf knowledge is limited to epidermis, palisade and spongy mesophyll, xylem and phloem, and guard cells surrounding stomata.
    • A transverse leaf section can be observed and drawn. Relate a tissue’s position or structure to its role; for example, palisade mesophyll cells contain many chloroplasts for photosynthesis, while spongy mesophyll air spaces support gas exchange.

    What to do in an exam

    • On a leaf cross-section, identify only the specified tissues and structures, then connect their features and positions to photosynthesis, gas exchange, transport or protection.
    • Use a labelled scientific drawing to record a transverse section and avoid adding unsupported detailed anatomy beyond the stated limit.

    In plain language

    A leaf contains several tissues with different roles. The epidermis forms a protective surface, palisade cells capture light for photosynthesis, and spaces in spongy mesophyll help gases move through the leaf. Xylem and phloem transport substances. When interpreting a section, use the structures AQA specifies and explain why their arrangement helps the leaf work.

    Self-check

    Why are air spaces in spongy mesophyll useful to a leaf?

    Show the answer

    They allow gases to move through the leaf, supporting gas exchange for photosynthesis and respiration.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.2.3.2

    Open revision guidance

    What to know

    • Roots, stem and leaves form an organ system that transports substances. Root-hair cells take up water by osmosis and mineral ions by active transport. Xylem carries water and mineral ions from roots to stems/leaves; it consists of hollow tubes strengthened by lignin and conducts the transpiration stream.
    • Transpiration is water loss from leaves, mainly by evaporation from cells and diffusion of water vapour through stomata. Guard cells control stomatal opening, balancing gas exchange and water loss. Temperature, humidity, air movement and light intensity affect transpiration rate.
    • Phloem transports dissolved sugars from leaves to the rest of the plant for immediate use or storage. This movement is translocation. Phloem consists of elongated tubes; sap passes between cells through pores in end walls. Detailed phloem structure and transport mechanism are not required.
    • Students interpret and draw graphs, translate graph/numerical information, calculate rate, find means, consider sampling, and calculate surface areas/volumes for stomata investigations; measure transpiration by water uptake and investigate stomata/guard cells.

    What to do in an exam

    • Explain how a changing factor alters water-vapour gradients or stomatal opening; calculate rate as water uptake ÷ time, and interpret controlled repeats and sample means.
    • Distinguish the water/mineral-ion xylem pathway from sugar translocation in phloem. In a potometer-style context, water uptake is an estimate related to transpiration, not a direct measure of all water lost.

    In plain language

    Water enters roots, moves up xylem and is lost from leaves. Evaporation and diffusion through stomata create a pull that supports flow in the transpiration stream. More moving air can remove humid air near the leaf, maintaining a gradient; high humidity can reduce it. Phloem carries sugars, not water in the transpiration stream. Guard cells control stomata, so they influence both gas exchange and water loss.

    Self-check

    State one role each for xylem and phloem, and explain why a potometer does not directly measure all transpiration.

    Show the answer

    Xylem carries water and mineral ions from roots; phloem carries dissolved sugars from leaves to other parts. A potometer measures water uptake, which is related to but not identical to water lost by transpiration.

Topic 4.3

Infection and response

Paper 114 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.1

    Open revision guidance

    What to know

    • Pathogens are microorganisms that cause infectious disease. Pathogen groups include viruses, bacteria, protists and fungi; they can infect plants or animals and spread by direct contact, water or air.
    • Pathogens depend on their host for conditions and nutrients. Bacteria and viruses may reproduce rapidly inside the body. Bacteria may release toxins that damage tissues and make the host feel ill; viruses live and reproduce inside cells, causing cell damage.
    • Disease spread can be reduced by preventing contact or interrupting a transmission route. Not every microorganism is a pathogen; the term describes organisms that cause infectious disease.

    What to do in an exam

    • For a disease scenario, identify the pathogen group, how it reaches a host and the relevant harm; then explain how the proposed measure interrupts that route.
    • Distinguish bacterial toxin damage from virus reproduction and damage inside host cells.

    In plain language

    An infectious disease spreads because a pathogen reaches a host and reproduces or damages tissues. The pathogen may travel through air, water or direct contact. A bacterium may make toxins; a virus uses cells to reproduce and may damage them. A control measure works when it blocks a route, reduces contact or otherwise stops this chain.

    Self-check

    How do the specification’s descriptions of bacterial and viral harm differ?

    Show the answer

    Bacteria may produce tissue-damaging toxins; viruses live and reproduce inside cells, causing cell damage.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.2

    Open revision guidance

    What to know

    • Measles causes fever and a red skin rash; it can be serious or fatal if complications arise. It spreads in droplets from coughs and sneezes, and most young children are vaccinated against it.
    • HIV initially causes a flu-like illness. Without successful control using antiretroviral drugs, it attacks immune cells. Late-stage HIV infection (AIDS) occurs when the immune system is so damaged it can no longer deal with other infections or cancers. HIV spreads through sexual contact or exchange of body fluids such as blood, including sharing needles.
    • Tobacco mosaic virus (TMV) affects many plant species, including tomatoes. Its distinctive mosaic leaf discolouration reduces photosynthesis and plant growth.

    What to do in an exam

    • For each example, identify it as viral and connect its particular route or effect to an appropriate control or consequence.
    • Do not confuse preventing measles by vaccination with controlling HIV using antiretroviral drugs, or describe plant TMV as a human infection.

    In plain language

    These three viral examples have different effects and routes. Measles passes in respiratory droplets and can cause fever and rash. HIV spreads through sexual contact or infected body fluids and, if uncontrolled, damages immune cells; antiretroviral drugs can control it. TMV causes mosaic discolouration in leaves, reducing photosynthesis and growth. Disease-specific details make explanations accurate.

    Self-check

    How does TMV reduce plant growth, and how does HIV affect the body if it is not controlled?

    Show the answer

    TMV discolours leaves in a mosaic pattern, reducing photosynthesis. Uncontrolled HIV attacks immune cells and can lead to AIDS, when the immune system cannot deal with other infections or cancers.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.3

    Open revision guidance

    What to know

    • Salmonella food poisoning is caused by bacteria ingested in food or on food prepared unhygienically. Fever, abdominal cramps, vomiting and diarrhoea result from the bacteria and toxins they secrete. UK poultry vaccination is used to control spread.
    • Gonorrhoea is a bacterial sexually transmitted disease. Symptoms include thick yellow or green discharge from the vagina or penis and pain when urinating. It was once easily treated with penicillin, but resistant strains have appeared. Spread can be controlled by antibiotic treatment or barrier contraception such as condoms.
    • Both are bacterial diseases, but their transmission routes and control methods differ.

    What to do in an exam

    • Match each disease to its causative pathogen, transmission, symptoms and an appropriate control measure.
    • Explain why food hygiene/poultry vaccination addresses Salmonella spread, while condoms and treatment interrupt gonorrhoea transmission; do not assume penicillin remains effective against every strain.

    In plain language

    Salmonella is commonly picked up through contaminated or unhygienically prepared food and causes gastrointestinal symptoms, partly through toxins. Gonorrhoea spreads through sexual contact and can produce discharge and painful urination. Antibiotic resistance means a treatment that worked previously may not work for all current bacterial strains. Controls must match the route and organism.

    Self-check

    Name one specified way to control Salmonella spread and one way to control gonorrhoea spread.

    Show the answer

    Poultry vaccination helps control Salmonella. Gonorrhoea spread can be reduced by antibiotic treatment or a barrier method such as a condom.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.4

    Open revision guidance

    What to know

    • Rose black spot is a fungal disease. Purple or black spots develop on leaves; affected leaves often turn yellow and drop early.
    • The disease reduces photosynthesis and therefore affects plant growth. It spreads through the environment by water or wind.
    • Control can include fungicides and/or removing and destroying affected leaves.

    What to do in an exam

    • Identify the pathogen as a fungus and explain reduced growth through loss of photosynthetic leaf area.
    • Relate a control method to spread or infection: fungicide acts against the fungus, while removing and destroying infected leaves reduces sources of further spread.

    In plain language

    Black or purple patches are a symptom of rose black spot. The affected leaves can yellow and fall, leaving less leaf area for photosynthesis. Water or wind can carry the disease through the environment. Treating plants or removing affected leaves helps control the infection and its spread.

    Self-check

    Why can rose black spot reduce plant growth?

    Show the answer

    It damages leaves, which can yellow and fall early, reducing photosynthesis and therefore the plant’s ability to grow.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.5

    Open revision guidance

    What to know

    • Malaria is caused by protist pathogens. The malarial protist life cycle includes a mosquito, which acts as a vector.
    • Malaria causes recurrent episodes of fever and can be fatal. Spread is controlled by preventing mosquito vectors from breeding and by using mosquito nets to avoid bites.
    • The key transmission explanation is that the mosquito moves the pathogen between hosts; reducing vector breeding or bites reduces transmission.

    What to do in an exam

    • Classify malaria as a protist disease, not a bacterial or viral one, and state the mosquito’s vector role.
    • Explain how a net or mosquito-breeding control interrupts transmission rather than claiming that either measure directly cures an infected person.

    In plain language

    A vector carries a pathogen between hosts. In malaria, the protist’s life cycle involves a mosquito. Preventing mosquitoes from breeding reduces the number of potential vectors; nets reduce bites and contact with them. The disease itself can cause repeated fever and may be fatal, so prevention targets spread as well as treatment needs.

    Self-check

    How does a mosquito net help control malaria?

    Show the answer

    It helps prevent mosquito bites, reducing transmission by the vector that carries the malarial protist.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.6

    Open revision guidance

    What to know

    • Nonspecific human defences include the skin, nose, trachea and bronchi, and stomach. Skin forms a physical barrier. Hairs and mucus in the nose trap particles and pathogens breathed in.
    • The trachea and bronchi produce mucus that traps particles and microorganisms. Cilia lining these airways beat to waft the mucus up towards the throat, where it is swallowed. Stomach acid can destroy many swallowed pathogens.
    • If a pathogen enters the body, the immune system tries to destroy it. White blood cells defend by phagocytosis, antibody production and antitoxin production. Phagocytosis is a white blood cell engulfing a pathogen. Antibodies target pathogen antigens; antitoxins neutralise toxins. These are distinct defences.

    What to do in an exam

    • Trace the route from inhaled particle to nasal trapping or airway mucus, then ciliary movement towards the throat and swallowing; explain how this reduces the chance of pathogens reaching the lungs.
    • If a pathogen enters the body, name the white-cell response and explain its effect: engulfing removes a pathogen, antibodies target it, and antitoxins neutralise toxins it produces.

    In plain language

    Skin blocks many pathogens from entering. In the nose, hairs and mucus trap inhaled particles. Lower down, mucus in the trachea and bronchi traps them, and tiny cilia move the mucus towards the throat to be swallowed, where stomach acid can destroy many pathogens. White blood cells provide further defence by engulfing pathogens, making antibodies or making antitoxins.

    Self-check

    How do the nose and the trachea or bronchi trap and remove inhaled particles?

    Show the answer

    Nasal hairs and mucus trap particles in the nose. Mucus traps particles in the trachea and bronchi, and cilia waft the mucus towards the throat to be swallowed.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.7

    Open revision guidance

    What to know

    • Vaccination introduces a small quantity of dead or inactive pathogen to stimulate white blood cells to produce antibodies. If the same pathogen enters again, white blood cells respond quickly with the correct antibodies, helping prevent illness/infection.
    • Immunising a large proportion of a population can reduce pathogen spread as well as preventing illness in vaccinated individuals. Students evaluate global use of vaccination in disease prevention.
    • Specific vaccine schedules and side effects are not required knowledge.

    What to do in an exam

    • Explain the sequence vaccine → antibody production → faster response to the same pathogen on later entry → reduced chance of illness and spread.
    • Evaluate a population vaccination programme with evidence and relevant benefits/limitations; avoid claiming every vaccinated person is guaranteed complete protection.

    In plain language

    A vaccine prepares the immune system before the dangerous infection occurs. White blood cells make antibodies, and a later encounter with the same pathogen triggers a quicker response. When many people are immunised, there are fewer opportunities for a pathogen to spread. The effect on a population depends on the disease and evidence about the vaccination programme.

    Self-check

    Why can vaccination both protect an individual and reduce spread through a population?

    Show the answer

    It prepares a faster antibody response that can prevent illness in an individual; immunising many people leaves fewer hosts through which the pathogen can spread.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.8

    Open revision guidance

    What to know

    • Antibiotics such as penicillin kill infective bacteria inside the body and can cure bacterial disease. Specific bacteria should be treated with appropriate specific antibiotics. Antibiotics have reduced deaths from bacterial infections, but antibiotic-resistant strains are a major concern.
    • Antibiotics cannot kill viruses. It is difficult to develop drugs that kill viruses without also damaging body tissues.
    • Painkillers and other medicines can treat symptoms but do not kill pathogens. Symptom relief is therefore different from treating the cause of an infection.

    What to do in an exam

    • First identify whether the pathogen is bacterial or viral, then decide whether an antibiotic can act on it; explain the difference between pathogen treatment and symptom relief.
    • Evaluate a medicine using its effect, limitations and resistance concerns rather than saying all medicines cure the infection.

    In plain language

    An antibiotic acts against bacteria, not viruses. Even for bacterial disease, a suitable antibiotic is needed and resistant strains may survive treatment. A painkiller may make someone feel better by reducing a symptom, but it does not remove the pathogen. Viral treatment is challenging because viruses reproduce inside body cells, so harming the virus without harming the tissues is difficult.

    Self-check

    Why will an antibiotic not cure measles, and what does a painkiller do instead?

    Show the answer

    Measles is viral, and antibiotics cannot kill viruses. A painkiller can reduce symptoms but does not kill the pathogen.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.1.9

    Open revision guidance

    What to know

    • Historically, drugs came from plants and microorganisms: digitalis (heart drug) from foxgloves, aspirin (painkiller) from willow, and penicillin was discovered by Alexander Fleming from Penicillium mould. Most new drugs are synthesised by pharmaceutical chemists, although a starting chemical may still come from a plant.
    • New drugs are tested and trialled for safety and effectiveness, including toxicity, efficacy and dose. Preclinical testing uses laboratory cells, tissues and live animals. Clinical trials use healthy volunteers and patients; very low doses are given first, and further trials establish a suitable/optimum dose if safety is shown.
    • In a double-blind trial some patients receive a placebo. Results of testing and trials are published only after scrutiny by peer review, which helps check claims.

    What to do in an exam

    • Describe the testing sequence from preclinical work to cautious human clinical trials, linking dose escalation to safety and efficacy.
    • Explain why a placebo and double blinding improve a comparison, and why peer review should scrutinise results before publication.

    In plain language

    A potential medicine must be checked before routine use. Researchers first test it in laboratory settings and live animals, then begin clinical trials at very low doses. If it is safe, further trials establish effective dosing. A placebo provides a comparison, and double blinding reduces expectation effects. Peer review examines reported findings; it does not mean a medicine is automatically effective.

    Self-check

    What is the purpose of beginning a clinical trial with a very low dose and using a placebo group?

    Show the answer

    The low dose supports cautious safety testing; a placebo gives a comparison that helps identify effects attributable to the medicine.

  • Higher

    Scope: Higher · 4.3.2.1

    Open revision guidance

    What to know

    • Monoclonal antibodies come from a single clone of cells. They are identical and specific to one binding site on one protein antigen, so they can target a particular chemical or cells carrying that target.
    • Mouse lymphocytes are stimulated to make a particular antibody and combined with a particular tumour cell to make a hybridoma. A hybridoma can divide and produce the antibody. Individual hybridoma cells are cloned to make many identical antibody-producing cells; a large quantity can then be collected and purified.
    • This whole monoclonal-antibody topic is Higher Tier only in AQA GCSE Biology. The production technique is required here, unlike the separate stem-cell techniques in 4.1.2.3, which are not required.

    What to do in an exam

    • Describe the steps in sequence: stimulate lymphocytes → combine with tumour cells → form dividing antibody-producing hybridomas → clone one hybridoma → collect and purify identical antibody.
    • Explain why cloning one cell type produces antibodies with the same target specificity.

    In plain language

    A lymphocyte can make a useful specific antibody but does not provide a convenient way to make large quantities. A hybridoma combines antibody production with the ability to divide. Cloning one selected hybridoma produces many cells making the same antibody, which can then be collected and purified.

    Self-check

    Why are the antibodies collected from a monoclonal hybridoma clone identical in target?

    Show the answer

    They are made by descendants of one selected hybridoma cell, so they bind the same specific site on the same protein antigen.

  • Higher

    Scope: Higher · 4.3.2.2

    Open revision guidance

    What to know

    • Monoclonal antibodies can be used for diagnosis, including pregnancy tests; in laboratories to measure hormone/other chemical levels in blood or detect pathogens; and in research to locate/identify molecules in cells or tissues using a fluorescent dye.
    • For some diseases such as cancer, a monoclonal antibody can be joined to a radioactive substance, toxic drug or chemical that stops cells dividing, directing it towards cells with the matching antigen. Students need not recall a specific test or treatment: given information, they should explain how it works.
    • Monoclonal antibodies have caused more side effects than expected and are not as widely used as initially hoped. Evaluate benefits, risks and ethical issues.

    What to do in an exam

    • Explain application through specific antigen binding: detection, measurement, fluorescent location or delivery of an attached treatment to target cells.
    • Evaluate rather than assume perfect targeting: use supplied evidence about benefits and possible side effects, and consider practical/ethical limitations.

    In plain language

    Specific binding lets a monoclonal antibody recognise a target. A marker can make the target visible, or an attached substance can be delivered towards cancer cells with the matching antigen. The antibody does not make a treatment risk-free: side effects have been greater than expected. In exam questions, apply the information supplied rather than memorising named products.

    Self-check

    How could a monoclonal antibody be used to locate a molecule in tissue, and what limitation must an evaluation include?

    Show the answer

    It can bind specifically to the target and carry a fluorescent dye, making the target visible. Include that side effects have been greater than expected and weigh risks against benefits.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.3.1

    Open revision guidance

    What to know

    • Plants can be infected by viral, bacterial or fungal pathogens and can be damaged by insects. The required plant-disease knowledge is restricted to tobacco mosaic virus (viral), black spot (fungal) and aphids (insects).
    • Plants can also show ion-deficiency conditions. Nitrate deficiency causes stunted growth because nitrate ions are needed for protein synthesis and therefore growth. Magnesium deficiency causes chlorosis because magnesium ions are needed to make chlorophyll.
    • Deficiency and infection can both damage plants; diagnosis should use evidence rather than assuming every symptom is caused by a pathogen.

    What to do in an exam

    • Match the specified cause to the symptom: nitrate shortage → stunted growth; magnesium shortage → chlorosis; distinguish these from the named viral, fungal and insect examples.
    • Use the ion’s biological role to explain the symptom, and keep disease knowledge within the examples AQA specifies.

    In plain language

    Not every unhealthy plant has an infection. Nitrate ions help plants make proteins needed for growth, so a shortage can stunt growth. Magnesium is needed to make chlorophyll, so a shortage can cause chlorosis. The required disease examples are TMV, black spot and aphids; recognising the cause helps select an appropriate response.

    Self-check

    Which deficiency is associated with chlorosis, and what plant molecule needs the deficient ion?

    Show the answer

    Magnesium deficiency is associated with chlorosis; magnesium ions are needed to make chlorophyll.

  • Higher

    Scope: Higher · 4.3.3.1

    Open revision guidance

    What to know

    • Higher Tier students should know plant diseases can be detected from stunted growth, leaf spots, areas of decay/rot, growths, malformed stems or leaves, discolouration, or the presence of pests.
    • Identification methods include checking a gardening manual or website, taking infected plants to a laboratory to identify the pathogen, or using testing kits containing monoclonal antibodies.
    • These signs are clues, not necessarily a unique diagnosis. This Higher-only supplement does not alter the common required knowledge of TMV, black spot, aphids and specified ion deficiencies.

    What to do in an exam

    • Choose a suitable identification method for the evidence and explain what further information it can provide; a monoclonal-antibody kit tests for a specific target.
    • When interpreting symptoms, distinguish observation from confirmed cause and use additional testing/reference evidence where needed.

    In plain language

    A spot or a malformed leaf signals that something may be wrong but does not by itself identify the cause. A reference can help compare symptoms, a laboratory can identify a pathogen, and a monoclonal-antibody kit can test for a target. These are Higher-only diagnostic outcomes. At Foundation tier, none of this Higher-specific list is required as a what-to-know or self-check.

    Self-check

    Name two Higher-tier methods for identifying a plant pathogen and state why a symptom alone may not be enough.

    Show the answer

    For example, take the plant to a laboratory or use a monoclonal-antibody test kit. Similar symptoms can have different causes, so a sign alone may not establish the pathogen.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.3.3.2

    Open revision guidance

    What to know

    • Plants have physical defences against microorganism invasion: cellulose cell walls, tough waxy leaf cuticle, and layers of dead cells around stems (bark) that fall off.
    • Chemical defences include antibacterial chemicals and poisons that deter herbivores.
    • Mechanical adaptations include thorns and hairs that deter animals, leaves that droop or curl when touched, and mimicry that tricks animals. Explain the defensive effect of the feature, not only its name.

    What to do in an exam

    • Classify an example as physical, chemical or mechanical, then connect it to blocking invasion, inhibiting microbes or deterring/tricking an animal.
    • Use evidence from a plant feature to explain how it reduces damage or pathogen entry.

    In plain language

    Plants cannot move away from every threat, so they have several kinds of defence. A waxy cuticle or wall provides a barrier; antibacterial chemicals act against microbes; thorns discourage animals from feeding. Some leaves droop or curl when touched, and mimicry can mislead an animal. The category helps organise the examples, but the explanation should state what protection each one provides.

    Self-check

    Give one physical and one mechanical plant defence, with its effect.

    Show the answer

    A tough waxy cuticle is a physical barrier that helps resist pathogen invasion. Thorns are a mechanical feature that deters animals.

Topic 4.4

Bioenergetics

Paper 19 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 4.4.1.1

    Open revision guidance

    What to know

    • Photosynthesis: carbon dioxide + water → glucose + oxygen, with light energy. Recognise CO₂, H₂O, O₂ and C₆H₁₂O₆.
    • Photosynthesis is endothermic: energy is transferred from the environment to chloroplasts by light. It stores light energy as chemical energy in glucose.
    • The reaction connects plant structure and function: carbon dioxide and water are used to make glucose, and oxygen is released.

    What to do in an exam

    • Write the reactants and products in the correct direction and match each formula to its name.
    • Explain energy transfer using the word endothermic and state where light energy is transferred; do not describe energy as a product.

    In plain language

    A plant uses light energy in chloroplasts to make glucose from carbon dioxide and water. Oxygen is also produced. Because energy enters the reaction from the environment, photosynthesis is endothermic. The glucose stores chemical energy that can later be used or converted into other substances.

    Self-check

    Name the reactants and products of photosynthesis, and explain why the reaction is endothermic.

    Show the answer

    Carbon dioxide and water are reactants; glucose and oxygen are products. It is endothermic because light energy is transferred from the environment into the chloroplasts.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.4.1.2

    Open revision guidance

    What to know

    • The rate of photosynthesis is affected by temperature, light intensity, carbon dioxide concentration and amount of chlorophyll. Increasing light intensity, carbon dioxide concentration or healthy chlorophyll can raise the rate while that factor is limiting; the rate then levels off when another factor limits it. More chlorophyll can absorb more light for photosynthesis.
    • Photosynthesis is enzyme controlled. As temperature rises towards the enzymes' optimum, reactions usually speed up and the rate rises. Above the optimum, enzymes denature and their active sites change shape, so the rate falls. No single optimum temperature value is required here.
    • Required practical 6 investigates the effect of light intensity on photosynthesis using an aquatic organism such as pondweed. Oxygen production can be measured as evidence of rate; keep temperature and other conditions controlled while light intensity changes.
    • A rate is a change in measured quantity divided by time. Students measure and calculate photosynthesis rates, extract and interpret graphs involving one limiting factor, plot graphs with suitable scales and translate graph and numerical information.

    What to do in an exam

    • On a one-factor graph, identify whether the rate rises or levels off as the independent factor increases. Explain a plateau by saying that another condition has become limiting; for temperature, explain why the rate eventually declines above the optimum.
    • Calculate rate from oxygen produced divided by time or another stated measurement, with units. In practical 6 vary light intensity, measure oxygen production over a fixed time, repeat readings, control temperature and other relevant conditions, and graph rate against light intensity.

    In plain language

    Photosynthesis needs light, carbon dioxide and chlorophyll, and its enzymes work best within a suitable temperature range. Raising a limiting light or carbon dioxide supply can increase rate until another factor restricts it. More chlorophyll can capture more light. Warming towards the enzymes' optimum speeds reactions, but excessive heat changes enzyme active sites and makes the rate fall. A pondweed investigation measures oxygen while changing light and keeping other conditions steady.

    Self-check

    What happens to photosynthesis rate as temperature rises above the enzymes' optimum, and why?

    Show the answer

    The rate falls because the enzymes denature and their active sites change shape, so substrates bind less effectively.

  • Higher

    Scope: Higher · 4.4.1.2

    Open revision guidance

    What to know

    • Photosynthesis factors interact; any one may be limiting. In a graph with more than one factor, compare rates along the relevant curves and ask whether increasing a factor changes the rate at the stated conditions. A flat section means that factor is no longer limiting there; another factor limits the rate.
    • Worked illustrative graph data, not official AQA exam values: carbon dioxide levels are low, medium and high. At low light the rates are 4, 4 and 4 relative units. At high light the rates are 5, 8 and 8 relative units. At low light, adding carbon dioxide makes no difference, so light is limiting. At high light and low carbon dioxide, carbon dioxide is limiting because the rate rises from 5 to 8 when carbon dioxide increases. At medium carbon dioxide the rate is already 8, so another factor has become limiting; more carbon dioxide alone does not raise the rate.
    • Light intensity follows an inverse-square relationship with distance from the light source: intensity is proportional to 1 divided by distance squared. Doubling distance gives one-quarter intensity; halving distance gives four times intensity, assuming the same source and conditions.
    • Higher-tier students use data to relate adding heat, light or carbon dioxide in greenhouses to the maximum photosynthesis rate and cost effectiveness while maintaining profit. Compare the extra crop value with the extra running cost, and do not pay to increase a factor that is not limiting.

    What to do in an exam

    • For a two-factor graph, first fix one factor and follow the curve as the other changes. Find where the rate rises, where it plateaus and which factor could raise the rate at that point. For three-factor data, make the same comparison while holding the third factor at the stated value.
    • Illustrative greenhouse comparison, not AQA data: adding heat costs £25 per day and yields extra crop worth £20 per day, so the net change is £20 - £25 = -£5 per day. Adding light costs £40 and yields extra crop worth £55, so net change is £55 - £40 = +£15 per day. Adding carbon dioxide costs £30 and yields extra crop worth £45, so net change is £45 - £30 = +£15 per day. Compare the net changes and limiting-factor evidence; a profitable option raises income above cost, but any combination must also have total additional value greater than total cost.
    • Calculate relative light intensity from distance using the inverse-square law. If distance changes from 20 cm to 40 cm, the relative intensity is (20/40)² = 1/4.

    In plain language

    A factor is limiting when increasing it would increase the photosynthesis rate. Curves with different light or carbon dioxide levels let you test this: a flat section means adding that factor no longer helps at those conditions. Greenhouse managers also compare the value of extra crop with the cost of heat, lamps or carbon dioxide. A higher maximum rate is worthwhile only if the added income covers the extra costs and maintains profit.

    Self-check

    Using the illustrative graph, which factor limits the rate at high light and low carbon dioxide? Then calculate the net change for adding heat in the example.

    Show the answer

    Carbon dioxide is limiting because the rate rises from 5 to 8 relative units when carbon dioxide increases at high light. The heat option nets £20 - £25 = -£5 per day, so it reduces profit by £5 per day.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.4.1.3

    Open revision guidance

    What to know

    • Glucose made in photosynthesis may be used in respiration, converted to insoluble starch for storage, or used to make fat/oil for storage.
    • Glucose is also used to make cellulose, which strengthens cell walls, and amino acids for protein synthesis. To produce proteins, plants also use nitrate ions absorbed from soil.
    • Qualitative tests for starch, glucose and proteins use suitable simple reagents (AT 8). These tests establish evidence for a substance; they are distinct from the metabolic routes that make or use it.

    What to do in an exam

    • When asked for glucose fates, state the conversion/product and purpose: starch or fat/oil storage, cellulose wall strength, amino acids/proteins, or respiration.
    • Explain that plants need both glucose and nitrate ions to form amino acids for proteins; glucose alone does not supply the nitrogen-containing building material.

    In plain language

    Photosynthesis produces glucose, but a plant can use it in several ways. Some is respired, some is stored as starch or oil, and some becomes material for growth such as cellulose or proteins. Nitrate ions supply the nitrogen needed to make amino acids, which are then joined to build proteins. Knowing the fate helps explain why photosynthesis supports both energy use and growth.

    Self-check

    What does a plant need, in addition to glucose, to make amino acids for proteins?

    Show the answer

    Nitrate ions absorbed from the soil.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.4.2.1

    Open revision guidance

    What to know

    • Cellular respiration is a continuously occurring exothermic reaction in living cells. Energy transferred supplies the energy needed for living processes, including building larger molecules, movement and keeping warm. Respiration may be aerobic (uses oxygen) or anaerobic (without oxygen).
    • Aerobic equation: glucose + oxygen → carbon dioxide + water. Recognise C₆H₁₂O₆, O₂, CO₂ and H₂O. In muscles, anaerobic respiration is glucose → lactic acid. In plant and yeast cells it is glucose → ethanol + carbon dioxide. Yeast anaerobic respiration is fermentation, used to make bread and alcoholic drinks.
    • Anaerobic oxidation is incomplete and transfers much less energy per glucose molecule than aerobic respiration. Compare oxygen requirement, products and relative energy transfer.

    What to do in an exam

    • Write the pathway appropriate to the organism/cell type and compare products without assigning ethanol to human muscle or lactic acid to yeast fermentation.
    • Explain one use of transferred energy and why anaerobic respiration releases less energy than complete aerobic oxidation.

    In plain language

    Respiration is a set of reactions in cells that transfers energy; it is not the same as breathing. With oxygen, glucose is broken down to carbon dioxide and water. Without oxygen, muscles form lactic acid, while plants and yeast form ethanol and carbon dioxide. Anaerobic respiration transfers less energy because glucose is incompletely oxidised. Yeast fermentation is useful in food and drink production.

    Self-check

    Give the products of anaerobic respiration in muscle and in yeast, and which transfers less energy than aerobic respiration?

    Show the answer

    Muscle cells produce lactic acid; yeast produces ethanol and carbon dioxide. Anaerobic respiration transfers much less energy than aerobic respiration.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.4.2.2

    Open revision guidance

    What to know

    • Exercise increases demand for energy. Heart rate, breathing rate and breath volume rise to supply muscles with more oxygenated blood.
    • If oxygen supply is insufficient, muscles respire anaerobically. Incomplete glucose oxidation causes lactic acid to build up and creates an oxygen debt. During prolonged vigorous activity, muscles become fatigued and stop contracting efficiently.
    • Investigations may study exercise effects on the body using suitable measurement apparatus and safe/ethical use of human participants (AT 1, 3 and 4). The precise Higher-tier account of lactic-acid transport/removal is a separate requirement.

    What to do in an exam

    • Explain how increased heart and breathing rates help meet muscle demand; connect insufficient oxygen to anaerobic respiration and lactic-acid accumulation.
    • Interpret exercise measurements by comparing before/during/after values and identifying what was measured; do not mistake oxygen debt for the name of a disease.

    In plain language

    Active muscles need more energy, so the body increases oxygenated blood delivery by raising heart rate and breathing rate and volume. When oxygen cannot meet demand, anaerobic respiration supplements energy transfer and lactic acid accumulates. With long vigorous activity, muscles become fatigued and contract less efficiently. Keep the common explanation to these links; the detailed oxygen-debt definition is Higher-only.

    Self-check

    What happens in muscle cells when oxygen supply is insufficient during exercise?

    Show the answer

    They respire anaerobically; incomplete glucose oxidation causes lactic acid build-up and contributes to oxygen debt and fatigue.

  • Higher

    Scope: Higher · 4.4.2.2

    Open revision guidance

    What to know

    • Higher Tier students know that blood flowing through muscles transports lactic acid to the liver, where it is converted back into glucose.
    • Oxygen debt is the amount of extra oxygen the body needs after exercise to react with accumulated lactic acid and remove it from cells. This is an exact explanation beyond the common requirement to know that anaerobic respiration and lactic-acid build-up create an oxygen debt.
    • Keep the sequence clear: anaerobic respiration in muscle produces lactic acid; blood transports it to the liver; extra oxygen after exercise helps react with and remove it.

    What to do in an exam

    • In an exam response, connect lactic acid production, its transport in blood, liver conversion to glucose and the extra oxygen needed after exercise.
    • Use the defined meaning of oxygen debt rather than using it as a synonym for breathlessness or simply the oxygen used during exercise.

    In plain language

    The Higher explanation follows lactic acid after strenuous exercise. Blood carries it from muscles to the liver, where it is converted back into glucose. Oxygen debt refers to the extra oxygen needed after exercise to react with accumulated lactic acid and remove it from cells. These details are Higher-only; Foundation answers do not need this account.

    Self-check

    What is oxygen debt, and where does blood take lactic acid for conversion back to glucose?

    Show the answer

    It is the extra oxygen needed after exercise to react with accumulated lactic acid and remove it from cells. Blood carries lactic acid to the liver, where it is converted back into glucose.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.4.2.3

    Open revision guidance

    What to know

    • Metabolism is the sum of all reactions in a cell or the body. Energy transferred by cellular respiration supplies continual enzyme-controlled metabolic processes, including synthesis of new molecules.
    • Metabolism includes converting glucose to starch, glycogen and cellulose; forming lipids from one glycerol molecule and three fatty-acid molecules; using glucose and nitrate ions to make amino acids and then proteins; respiration; and breaking down excess proteins to form urea for excretion.
    • Sugars, amino acids, fatty acids and glycerol are important in synthesis and breakdown of carbohydrates, proteins and lipids. These reactions connect the topic’s specific food molecules and products.

    What to do in an exam

    • For a named molecule, state the relevant building block or conversion and the product, e.g. glycerol + three fatty acids → lipid.
    • Explain that metabolism includes both synthesis and breakdown, and link respiration’s energy transfer to enzyme-controlled processes rather than defining metabolism as respiration alone.

    In plain language

    Metabolism is the complete set of chemical reactions in a cell or body, not a single reaction. Some reactions build larger molecules from smaller ones; others break molecules down. Respiration transfers energy that supports many of those reactions. Plants use glucose and nitrate ions to make amino acids, and amino acids are then used to make proteins; excess protein is broken down and produces urea for excretion.

    Self-check

    How many fatty-acid molecules combine with one glycerol molecule to form a lipid, and what can excess protein be broken down to form?

    Show the answer

    Three fatty-acid molecules; excess protein can be broken down to form urea for excretion.

  • Higher

    Scope: Higher · 8.2.6

    Open revision guidance

    What to know

    • Higher-tier students understand and use inverse proportion, specifically the inverse square law, for light intensity in the photosynthesis context. Light intensity ∝ 1/d², where d is distance from the light source.
    • If distance is multiplied by a factor k, intensity is divided by k². For example, doubling distance reduces intensity to one quarter; halving distance increases it fourfold.
    • This mathematical outcome is Higher-only. The standard practical method and comparison of light intensity effects are common to both tiers.

    What to do in an exam

    • Calculate relative light intensity with the inverse-square relationship, keeping distance units consistent; compare the relative intensity at two distances using (d₁/d₂)².
    • Use a practical graph/data set carefully: measured oxygen production may also depend on other limiting conditions, so do not assume distance is linearly related to rate.

    In plain language

    Light spreads out as it travels from a source, so intensity falls with the square of distance. Moving a lamp twice as far away does not halve light intensity; it makes it one quarter as great. This Higher-tier relationship helps describe the light conditions in practical 6, but observed photosynthesis can also be limited by other factors.

    Self-check

    A lamp moves from 10 cm to 30 cm from pondweed. What fraction of the original light intensity reaches the pondweed?

    Show the answer

    Distance triples, so intensity becomes 1 ÷ 3² = 1/9 of the original.

Topic 4.5

Homeostasis and response

Paper 220 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.1

    Open revision guidance

    What to know

    • Homeostasis is regulation of the internal conditions of a cell or organism to maintain optimum conditions for function in response to internal and external changes. It helps maintain conditions suitable for enzyme action and other cell functions.
    • Cells survive only within narrow physical and chemical limits. They need suitable temperature and pH and a steady supply of dissolved food and water, so the body monitors and adjusts blood and tissue conditions. In humans, the specified controlled conditions include blood glucose concentration, body temperature and water levels. Automatic control may use nervous responses, chemical responses or both.
    • A control system has receptors that detect stimuli or changes, a coordination centre that receives and processes receptor information, and effectors that bring about a response restoring optimum conditions. Examples of coordination centres are the brain, spinal cord and pancreas; effectors are muscles or glands.

    What to do in an exam

    • For a control-system question, identify the change, receptor, coordination centre, effector and response in order. Explain how the response helps return the condition towards its optimum.
    • Distinguish detecting a change from coordinating information and carrying out the response; a hormone or nerve impulse is not itself an effector.

    In plain language

    Cells work best within a limited range of internal conditions. Homeostasis keeps those conditions suitable even when the surroundings or the body's activity change. A sensor detects a change, a control centre processes information, and a muscle or gland acts to correct it. The response is useful because it reduces the original disturbance rather than simply noticing it.

    Self-check

    Define homeostasis and name the three basic parts of a control system.

    Show the answer

    Homeostasis is regulation of internal conditions to maintain optimum conditions for function in response to internal and external changes. The system has receptors, a coordination centre and effectors.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.2.1

    Open revision guidance

    What to know

    • The nervous system lets people respond to their surroundings and coordinate behaviour. Receptors detect stimuli; electrical impulses travel along neurones to the central nervous system (CNS), which consists of the brain and spinal cord. The CNS coordinates effectors, such as contracting muscles or glands secreting hormones.
    • In a reflex arc, a receptor sends an impulse along a sensory neurone to the CNS. At a synapse, a chemical transmitter carries the signal across the gap to a relay neurone, then across another synapse to a motor neurone. The motor neurone carries the impulse to an effector, which produces a response. A reflex is rapid and automatic and does not involve the conscious part of the brain, helping protect the body from harm.
    • Required practical activity 7 investigates how a factor affects human reaction time. One workable method is to drop a ruler without warning and record the distance at which a partner catches it; repeat trials and compare reaction-time data using the method or conversion data provided. A fair investigation changes one factor, controls other relevant conditions, repeats measurements and compares results. Reaction-time results can be shown numerically or graphically; nervous-system data can also be interpreted from tables, charts and graphs.

    What to do in an exam

    • Trace a reflex pathway in order and identify the direction of impulses: receptor, sensory neurone, CNS relay neurone, motor neurone, effector and response. A synapse is the junction where the signal passes between neurones.
    • For a ruler-drop investigation, keep the ruler, hand position and release procedure consistent, record catch distance, repeat and compare means where appropriate. Identify the factor changed, measured outcome and controls; choose labelled axes and a suitable scale, and translate a plotted value back into a numerical reaction time.
    • Original graph-reading practice, not AQA data: suppose repeated tests give mean reaction times of 180 ms without a distraction and 220 ms while attention is divided. The difference is 40 ms, and the larger time means a slower response. The comparison only supports an effect of distraction if other relevant conditions were controlled.

    In plain language

    A reflex gives a fast response without waiting for a conscious decision. The signal travels into the spinal cord or brain through a sensory neurone, passes across connections between neurones and leaves along a motor neurone to a muscle or gland. The practical tests reaction time, so keep the comparison fair and present the measurements clearly. If a graph is given, use its axes and units rather than guessing from the line.

    Self-check

    Put the main reflex-arc structures in order from stimulus detection to response, and state one reason reflexes are important.

    Show the answer

    Receptor, sensory neurone, relay neurone in the CNS, motor neurone, effector and response. Reflexes are rapid and automatic, helping protect the body without requiring a conscious decision.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.2.2

    Open revision guidance

    What to know

    • The brain controls complex behaviour and contains billions of interconnected neurones. Different regions carry out different functions.
    • Be able to identify the cerebral cortex, cerebellum and medulla on a brain diagram and describe their functions. The cerebral cortex is involved in conscious thought, memory and intelligence; the cerebellum coordinates muscle movement and balance; the medulla controls automatic functions such as breathing and heart rate.
    • The required diagram skill is to recognise the named regions and connect each region with its function, rather than treating the brain as one undifferentiated control centre.

    What to do in an exam

    • On a labelled or unlabelled brain diagram, locate the cerebral cortex as the large folded outer region, the cerebellum at the lower rear, and the medulla at the base connecting towards the spinal cord.
    • Match a behaviour or function in a question to the relevant brain region, then explain that specialised regions work as parts of an interconnected brain.

    In plain language

    The brain is made of many connected neurones, but its regions do different jobs. The cortex is associated with conscious thought and memory, the cerebellum helps coordinate movement and balance, and the medulla controls vital automatic processes. A diagram question may test both where a region is and what it does, so learn each location-function pair.

    Self-check

    Which brain region coordinates movement and balance, and which controls automatic functions such as breathing?

    Show the answer

    The cerebellum coordinates movement and balance. The medulla controls automatic functions such as breathing.

  • Higher

    Scope: Higher · 4.5.2.2

    Open revision guidance

    What to know

    • Studying patients with brain damage can show which abilities are affected when a region is damaged. This can help locate a problem and support diagnosis or treatment planning, but damage may affect connected regions too, so the evidence must be interpreted carefully. Electrical stimulation can trigger a response and help map function, but inserting electrodes or stimulating tissue is invasive and can damage delicate tissue.
    • Structural MRI scans show anatomy and can help identify a lesion or other physical damage. Functional activity mapping, for example functional MRI, estimates which regions are active during a task from associated changes in blood flow and oxygenation; it is not the same as an ordinary structural image. Scanning is non-invasive, while electrical stimulation and brain surgery involve intervention and risks such as tissue damage, bleeding or infection. The brain's complexity and delicacy make both investigation and treatment difficult.

    What to do in an exam

    • Match method to evidence and benefit: patient damage can help diagnose and locate affected function; structural MRI shows anatomy or damage and can inform treatment planning; functional MRI uses blood-flow/oxygenation changes to map activity during tasks; electrical stimulation can reveal a response but requires an invasive procedure.
    • Evaluate a procedure by weighing the diagnostic or planning benefit against invasiveness and risk to interconnected, delicate tissue. A non-invasive scan avoids risks of entering brain tissue but has different limits from direct stimulation or surgery.

    In plain language

    A scan can show the brain's structure without entering it, while activity mapping looks for regions involved in a task. Observing what changes after damage or stimulation can help connect a region with a function. These methods can help diagnosis and treatment planning, but damage to one area may affect connected areas, and probes or surgery can harm delicate tissue. Choose a method by considering both the information it provides and its risks.

    Self-check

    How does structural MRI differ from functional activity mapping, and give one benefit and one risk of investigating the brain.

    Show the answer

    Structural MRI shows anatomy and possible physical damage; functional MRI maps regions whose activity changes during a task. Mapping can help locate damage, diagnose a problem or plan treatment. Electrical stimulation or surgery can damage delicate tissue, while a scan is non-invasive.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.2.3

    Open revision guidance

    What to know

    • The eye is a sense organ with receptors sensitive to light intensity and colour. The cornea refracts incoming light; the iris controls pupil size and so the amount of light entering; the retina contains light receptors; the optic nerve carries impulses from the retina to the brain. The sclera is the tough outer layer that protects the eye.
    • Accommodation changes lens shape to focus near or distant objects on the retina. For a near object, ciliary muscles contract, suspensory ligaments loosen and the lens becomes thicker, refracting light strongly. For a distant object, ciliary muscles relax, ligaments pull tight and the lens is thinner, refracting light less strongly. In dim light, radial muscles in the iris contract and circular muscles relax, making the pupil dilate so more light enters.
    • Myopia (short sight) and hyperopia (long sight) occur when light does not focus on the retina. Spectacle lenses can refract rays onto the retina; other treatments include hard or soft contact lenses, laser surgery changing corneal shape, and a replacement lens.

    What to do in an exam

    • Label the retina, optic nerve, sclera, cornea, iris, ciliary muscles and suspensory ligaments, then relate each named structure to its function. For a dim-light question, state radial iris muscles contract, circular muscles relax, and the pupil dilates.
    • In a ray diagram, myopic (short-sighted) eyes focus light in front of the retina and are corrected with a diverging, concave spectacle lens; hyperopic (long-sighted) eyes focus behind the retina and are corrected with a converging, convex lens. Trace rays to show that correction brings focus onto the retina. Do not confuse near-object lens thickening with distant-object lens thinning.

    In plain language

    The eye bends light so a focused image forms on the retina. The cornea and lens refract light, while the retina detects it and sends signals along the optic nerve. To look at something near, the lens gets thicker; for a distant object it becomes thinner. Short-sight and long-sight mean the focus falls in the wrong place, and corrective lenses change the path of the rays.

    Self-check

    For a near object, what happens to the ciliary muscles, suspensory ligaments and lens? What happens to the iris in dim light?

    Show the answer

    For a near object, ciliary muscles contract, suspensory ligaments loosen and the lens becomes thicker, refracting light strongly. In dim light, radial iris muscles contract and circular muscles relax, dilating the pupil to let in more light.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.2.4

    Open revision guidance

    What to know

    • Body temperature is monitored and controlled by the thermoregulatory centre in the brain. Receptors in this centre are sensitive to the temperature of the blood.
    • Temperature receptors in the skin detect changes at the body surface and send nervous impulses to the thermoregulatory centre. Information about blood and skin temperature therefore reaches the control centre, which coordinates a response.
    • If body temperature is too high, skin blood vessels dilate (vasodilation) and sweat is produced. Both responses cause energy transfer from the skin to the environment. If temperature is too low, blood vessels constrict (vasoconstriction), sweating stops and skeletal muscles contract in shivering.
    • Temperature control is part of homeostasis: keeping body conditions within a suitable range supports enzyme action and cell function.

    What to do in an exam

    • In a control diagram or scenario, distinguish the thermoregulatory centre's blood-temperature receptors from temperature receptors in the skin, and state that skin impulses travel to the centre.
    • For a hot condition, name vasodilation and sweating; for a cold condition, name vasoconstriction, stopping sweat and shivering. State the common outcome that the hot responses transfer energy from skin to the environment, without adding the Higher-tier explanation of how the response changes body temperature.

    In plain language

    The thermoregulatory centre senses blood temperature, and skin receptors send it information about the body's surface. If the body is hot, skin blood vessels widen and sweat is produced; both allow energy to transfer from skin to the surroundings. If the body is cold, vessels narrow, sweating stops and muscles shiver. The control centre coordinates these responses.

    Self-check

    Name the body responses when too hot and when too cold. What energy-transfer result is stated for vasodilation and sweating?

    Show the answer

    When too hot, blood vessels dilate and sweat is produced. When too cold, blood vessels constrict, sweating stops and skeletal muscles shiver. Vasodilation and sweating cause energy transfer from the skin to the environment.

  • Higher

    Scope: Higher · 4.5.2.4

    Open revision guidance

    What to know

    • In a hot context, vasodilation brings more blood through vessels close to the skin surface, so more energy can transfer from the warm blood and skin to cooler surroundings. Sweat cools the body when it evaporates because the phase change transfers energy away from the skin; simply producing sweat is not the same as evaporation.
    • In a cold context, vasoconstriction reduces blood flow close to the skin, so less energy is transferred from the body's core to the surroundings. Stopping sweat reduces evaporative energy loss. Shivering is rapid skeletal-muscle contraction; muscle activity releases energy, helping raise body temperature.
    • Use the direction of the temperature change in the question to explain the result: hot-weather responses increase net heat loss, while cold-weather responses conserve heat or release energy.

    What to do in an exam

    • For a hot or cold scenario, trace each response to its effect on skin blood flow, evaporation or muscle energy release, then state how this changes body temperature.
    • Use the precise terms vasodilation and vasoconstriction, and distinguish sweat production from the cooling effect of sweat evaporating.

    In plain language

    The Higher explanation connects the named response to the temperature result. In heat, more skin blood flow and evaporation allow more energy to leave. In cold, less blood near the surface and no sweat reduce energy loss, while shivering muscle activity releases energy. The context matters: describe the physical change before saying how temperature responds.

    Self-check

    During exercise on a warm day, explain how vasodilation and sweat evaporation affect body temperature. Why is evaporation important?

    Show the answer

    Vasodilation increases blood flow close to the skin, allowing more energy to transfer to the surroundings. As sweat evaporates it takes energy from the skin, increasing heat loss and lowering body temperature. Sweat that has not evaporated has not yet produced that cooling effect.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.3.1

    Open revision guidance

    What to know

    • The endocrine system consists of glands that secrete hormones directly into the bloodstream. Blood carries each hormone to a target organ, where it produces an effect. Compared with nervous responses, hormonal effects are usually slower to begin but last longer.
    • The pituitary gland in the brain is called a master gland because it secretes several hormones in response to body conditions; these can act on other glands and stimulate release of further hormones.
    • Be able to identify the pituitary gland in the brain, pancreas in the abdomen, thyroid in the neck, adrenal glands above the kidneys, ovaries in the pelvis and testes in the scrotum on a human-body diagram.

    What to do in an exam

    • Trace hormonal coordination as gland secretion into blood, transport to a target organ and a resulting effect; contrast the slower, longer-lasting hormonal response with the generally faster nervous response.
    • On a body diagram, label the six named glands by anatomical region and distinguish the endocrine gland from the organ or target it affects.

    In plain language

    Hormones are chemical messages released by glands into blood. They can travel around the body but affect target organs that respond to them. This usually takes longer than sending a nerve impulse, but the effect can last longer. The pituitary also sends hormones that influence other endocrine glands, which is why it is described as a master gland.

    Self-check

    How does a hormone reach its target, how does its response compare with a nervous response, and why is the pituitary called a master gland?

    Show the answer

    A gland secretes a hormone into the blood, which carries it to a target organ. Hormonal effects are usually slower but longer-lasting than nervous effects. The pituitary secretes hormones that can stimulate other glands to release hormones.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.3.2

    Open revision guidance

    What to know

    • The pancreas monitors and controls blood glucose concentration. If it is too high, the pancreas produces insulin. Insulin causes glucose to move from the blood into cells; in liver and muscle cells, excess glucose is converted to glycogen for storage.
    • Type 1 diabetes occurs when the pancreas fails to produce sufficient insulin. Blood glucose can become dangerously high, and Type 1 is normally treated with insulin injections. In Type 2 diabetes, body cells no longer respond properly to insulin made by the pancreas; common treatments include a carbohydrate-controlled diet and exercise. Obesity is a risk factor for Type 2 diabetes.
    • Students should compare the two forms of diabetes and interpret graphs showing insulin's effect on blood glucose in people with and without diabetes. Obesity is a risk factor associated with Type 2 diabetes, but an association in a population does not by itself prove that obesity caused diabetes in a particular person. Type 2 diabetes has multiple influences; avoid blaming or stereotyping individuals.
    • Evaluating obesity-diabetes information means checking what groups and measures were studied, whether the data show association rather than cause, and what other influences could matter. Recommendations should be evidence-based, practical, accessible and respectful of social circumstances; consider supportive options such as access to balanced food, enjoyable activity and appropriate health advice rather than stigmatizing people.

    What to do in an exam

    • For a high-glucose explanation, state pancreas releases insulin, cells take up glucose, and liver or muscle stores excess glucose as glycogen. Keep glycogen distinct from glucose.
    • Compare Type 1 and Type 2 by the cause and treatment; read graph axes, units and time points before comparing how glucose changes after insulin.
    • Original graph-reading practice, not AQA data: an invented example gives glucose values of 12, 10, 7 and 5 mmol/L at 0, 30, 60 and 120 minutes after insulin. The plotted value falls by 7 mmol/L over two hours. State the trend from the graph, but do not treat these illustrative values as clinical targets or infer that obesity alone caused someone's diabetes.
    • When evaluating obesity-diabetes evidence, distinguish correlation from causation, note that a risk factor does not determine an individual's outcome, and propose non-stigmatising recommendations that consider access and social context.

    In plain language

    Insulin helps lower blood glucose by moving glucose out of the blood and into cells. Type 1 is a shortage of insulin because the pancreas does not make enough; Type 2 is reduced response by body cells to insulin. Obesity is one risk factor linked with Type 2, not a complete explanation or a basis for blaming an individual. Good recommendations need evidence and should account for people's different circumstances.

    Self-check

    A population study finds higher Type 2 diabetes rates in a group with higher obesity rates. Does this alone prove obesity caused diabetes in each person, and what makes a recommendation fair?

    Show the answer

    No. The pattern shows an association, but by itself does not establish individual causation; other influences may contribute. A fair recommendation uses evidence, recognises that risk is not destiny, considers access and social circumstances, and offers supportive, non-stigmatising options such as accessible balanced food, enjoyable activity and appropriate healthcare.

  • Higher

    Scope: Higher · 4.5.3.2

    Open revision guidance

    What to know

    • If blood glucose falls too low, the pancreas produces glucagon. Glucagon causes stored glycogen to be converted into glucose and released into the blood, raising blood glucose.
    • Insulin and glucagon act in opposite directions in a negative-feedback cycle. A rise above the suitable level leads to insulin action that lowers blood glucose; a fall too low leads to glucagon action that raises it. As the level returns towards its normal range, the stimulus for the corrective response is reduced.
    • Negative feedback opposes a change and helps stabilise an internal condition; it is not simply a feedback message that always increases the original change.

    What to do in an exam

    • For a low-glucose question, trace low concentration to pancreatic glucagon release, glycogen conversion to glucose and increased blood glucose.
    • When given a diagram, follow arrows and state whether each hormone raises or lowers blood glucose; explain how opposite responses return the variable towards its normal level.

    In plain language

    Insulin and glucagon are opposing controls. Insulin responds to blood glucose that is too high, while glucagon responds when it is too low. Glucagon makes stored glycogen available as glucose and the glucose enters blood. Because each response counters the disturbance, the pair can keep blood glucose within a suitable range.

    Self-check

    When blood glucose is too low, which hormone is released and how does it raise the concentration?

    Show the answer

    The pancreas releases glucagon. It causes glycogen to be converted into glucose and released into the blood, raising blood glucose.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.3.3

    Open revision guidance

    What to know

    • Water leaves the body in exhaled air. Sweat removes water, ions and urea from the skin, and the body does not control water, ion or urea loss through the lungs or skin. The kidneys remove excess water, ions and urea in urine.
    • Osmosis is net movement of water through a partially permeable membrane from a more dilute solution to a more concentrated solution. If fluid outside a cell is more concentrated than its contents, water leaves and the cell shrinks. If the outside fluid is more dilute, water enters and the cell swells; an animal cell may burst if too much enters, while a plant cell wall limits expansion. Either imbalance can stop cells functioning efficiently.
    • Kidneys produce urine by filtering blood and selectively reabsorbing useful substances, including glucose, some ions and water. Students do not need the structure of a nephron or other urinary-system parts.
    • In haemodialysis, blood flows on one side of a partially permeable membrane while dialysis fluid flows on the other. Urea diffuses from blood into fluid; glucose and useful-ion concentrations in the fluid are set so needed substances are not lost from blood. Many in-centre patients have sessions of about four hours, three times a week; other schedules exist. People often need to limit fluid and some foods, and dialysis can leave them tired.
    • A kidney transplant can restore kidney function and usually means fewer food and fluid restrictions and more freedom than regular dialysis, but donor kidneys are in short supply and a person may wait months or years, using dialysis while waiting. Transplant involves major surgery and lifelong immunosuppressant medicines to reduce rejection; these weaken infection defence. Both treatments therefore have substantial but different burdens.

    What to do in an exam

    • When reading a table or bar chart of substances before and after filtration, compare the measured values and units for glucose, ions and urea; explain that useful substances are selectively reabsorbed while excess substances leave in urine. For example, glucose in filtrate but absent from urine indicates it was reabsorbed; urea present in urine is being excreted.
    • For dialysis, explain diffusion across the membrane and why the dialysis fluid is set up to remove urea without a net loss of needed glucose or ions. Compare repeated sessions and possible diet/fluid limits with transplant surgery, donor waiting, rejection and infection risks from immunosuppression; avoid claiming one treatment is best for everyone.
    • For an osmosis scenario, compare the concentration outside a cell with the cell contents. More concentrated outside means water leaves and the cell shrinks; more dilute outside means water enters, swelling the cell and potentially bursting an animal cell.

    In plain language

    Water crosses cell membranes by osmosis. A concentrated fluid outside a cell draws water out, so the cell shrinks; a dilute fluid outside sends water in, so the cell swells and an animal cell can burst. The kidneys filter blood and take useful materials back. Dialysis removes waste across a membrane in repeated treatments, while a transplant can restore kidney function but involves surgery, waiting for a donor and medicines that reduce rejection but increase infection risk.

    Self-check

    What happens to a cell in a concentrated external fluid versus a dilute external fluid? Give one practical difference between dialysis and transplant.

    Show the answer

    In concentrated external fluid, water leaves the cell and it shrinks. In dilute external fluid, water enters, making it swell and potentially burst if it is an animal cell. Haemodialysis requires repeated sessions, often around four hours three times weekly, whereas a transplant may restore kidney function with fewer food/fluid restrictions but requires a donor, major surgery and immunosuppressants.

  • Higher

    Scope: Higher · 4.5.3.3

    Open revision guidance

    What to know

    • Protein digestion produces excess amino acids that cannot be stored for later use. In the liver, excess amino acids are deaminated: the amino group is removed, forming ammonia. Ammonia is toxic, so the liver immediately converts it to urea for safe excretion by the kidneys.
    • The hormone ADH controls the body's water level by acting on kidney tubules. When blood is too concentrated, the pituitary gland releases ADH. ADH makes the kidney tubules more permeable to water, so more water is reabsorbed into the blood. This is negative feedback because the response reduces the original excess concentration.
    • Water regulation adjusts how much water is returned to blood; it does not mean the kidney makes water. The amount of water left in urine changes as reabsorption changes.

    What to do in an exam

    • Describe the nitrogenous waste sequence: excess dietary protein digestion gives amino acids, liver deamination produces toxic ammonia, conversion makes urea, and kidneys excrete urea.
    • For concentrated blood, trace pituitary ADH release to increased tubule permeability, increased water reabsorption and a less concentrated blood. Explain how this response opposes the initial change.

    In plain language

    Extra amino acids are not simply passed into urine. The liver removes their amino groups and converts the resulting toxic ammonia into urea, which can be excreted safely. ADH changes how much water kidney tubules return to blood. More ADH means more water reabsorbed when blood is too concentrated, helping restore the water balance.

    Self-check

    How does the body convert excess amino acids into a safe waste product, and what does ADH do when blood is too concentrated?

    Show the answer

    The liver deaminates excess amino acids, producing toxic ammonia, and converts the ammonia into urea for kidney excretion. The pituitary releases ADH, which increases kidney-tubule permeability so more water is reabsorbed into blood.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.3.4

    Open revision guidance

    What to know

    • At puberty, reproductive hormones cause secondary sexual characteristics to develop. Oestrogen is the main female reproductive hormone and is produced by the ovaries. At puberty, eggs begin to mature and an egg is released approximately every 28 days; this release is ovulation.
    • Testosterone is the main male reproductive hormone, produced by the testes, and stimulates sperm production.
    • Four hormones have named roles in the menstrual cycle: follicle-stimulating hormone (FSH) causes an egg to mature in an ovary; luteinising hormone (LH) stimulates egg release; oestrogen and progesterone are involved in maintaining the uterus lining. Higher-tier interactions among these hormones are a separate extension.

    What to do in an exam

    • Match each hormone to its source and role: ovarian oestrogen, testicular testosterone, FSH and egg maturation, LH and egg release, and oestrogen/progesterone and uterus lining.
    • Use approximately 28 days as the typical interval in the specification, not as a guarantee that every person's cycle is exactly that length.

    In plain language

    Reproductive hormones coordinate changes at puberty and reproduction. FSH helps an egg mature, LH triggers its release, and oestrogen and progesterone help maintain the uterus lining. Oestrogen comes mainly from the ovaries, while testosterone from the testes stimulates sperm production. The more detailed feedback relationships are Higher-only.

    Self-check

    What do FSH and LH do in the menstrual cycle, and which two hormones are involved in maintaining the uterus lining?

    Show the answer

    FSH causes an egg to mature in an ovary; LH stimulates egg release. Oestrogen and progesterone are involved in maintaining the uterus lining.

  • Higher

    Scope: Higher · 4.5.3.4

    Open revision guidance

    What to know

    • FSH from the pituitary stimulates an ovarian follicle and egg to mature. The developing follicle releases oestrogen. Oestrogen helps rebuild and maintain the uterus lining, inhibits further FSH release and stimulates LH release.
    • A rise in LH causes ovulation, the release of the mature egg. After ovulation, progesterone from the ovary helps maintain the uterus lining and inhibits release of FSH and LH. If progesterone falls, the lining is no longer maintained and the cycle can begin again.
    • Hormone concentrations change over the menstrual cycle. Graphs can show these changes; the relative timing and direction of changes help explain maturation, ovulation and maintenance of the uterus lining.

    What to do in an exam

    • Explain the sequence with hormone names and effects: FSH maturation, follicle oestrogen, LH surge and ovulation, then progesterone and uterus-lining maintenance. Include inhibitory effects when explaining control.
    • On a hormone graph, read the axes and time scale, identify rises, falls and peaks, and link their timing to cycle events. For example, a sharp LH peak around mid-cycle is associated with ovulation; a progesterone rise afterwards is associated with maintaining the uterus lining. Do not infer an event from a curve without checking which hormone is plotted, and do not assume every cycle has exactly the same length.

    In plain language

    The hormones change in a linked sequence. FSH helps an egg mature, the follicle produces oestrogen, and oestrogen helps prepare the uterus lining while also changing pituitary hormone release. A rise in LH triggers ovulation. Progesterone then helps maintain the lining. On a graph, timing matters as much as the height of each hormone level.

    Self-check

    Which hormone surge stimulates ovulation, and what does progesterone do after ovulation?

    Show the answer

    A rise in LH stimulates ovulation. After ovulation, progesterone helps maintain the uterus lining and inhibits release of FSH and LH.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.3.5

    Open revision guidance

    What to know

    • Contraception controls fertility using hormonal and non-hormonal methods. Oral contraceptive pills contain hormones that inhibit FSH production, so eggs do not mature. Slow-release progesterone from an injection, implant or skin patch inhibits egg maturation and release for months or years.
    • Barrier methods, including condoms and diaphragms, prevent sperm reaching an egg. Condoms also reduce the risk of sexually transmitted infections (STIs); a diaphragm does not provide that STI protection. Intrauterine devices may prevent implantation of an embryo or release a hormone. Spermicidal agents kill or disable sperm. Abstaining from intercourse when an egg may be in the oviduct avoids sperm meeting the egg.
    • Male sterilisation (vasectomy) blocks or seals the sperm ducts so sperm are not ejaculated; female sterilisation blocks or cuts the oviducts (fallopian tubes) so sperm cannot meet an egg. Sterilisation is intended to be permanent and reversal is not guaranteed. It requires a procedure, with recovery and operative risks, unlike a daily pill or a barrier used at each sexual encounter.
    • A pill requires remembering a daily dose; an injection, implant or patch lasts longer and reduces daily adherence demands, but still has method-specific practical limits. Hormonal methods can cause side effects, such as changes to bleeding; the combined pill also has a small blood-clot risk, and risks differ between methods and people. Sterilisation is an operation and can have complications or recovery time; it is intended to be permanent and reversal is not guaranteed. Compare evidence, STI protection, convenience, side effects, access and whether future fertility is wanted. Contraception choices also involve personal, social and ethical values, so science alone cannot choose for everyone.

    What to do in an exam

    • Classify each method as hormonal or non-hormonal and explain its action. For sterilisation, trace the physical route: vasectomy blocks sperm ducts; female sterilisation blocks or cuts oviducts. Only condoms among these barrier examples also reduce STI transmission.
    • Compare a daily pill's adherence requirement with longer-acting methods, then consider side effects, access, reversibility and personal preference. Sterilisation is permanent surgery with recovery and operative risks. Use current evidence and respect a person's circumstances; do not present a moral or social preference as a scientific conclusion.

    In plain language

    Methods differ in when and how they prevent pregnancy. A pill needs regular daily use, while an implant or injection can work for much longer before replacement or another appointment. Hormones can change bleeding; the combined pill has a small blood-clot risk, and exact risks vary by method and person. Condoms help prevent pregnancy and reduce STI risk, unlike diaphragms, pills, implants or sterilisation. Sterilisation blocks the routes sperm use, is intended to be permanent and requires a procedure. A balanced choice depends on evidence and the individual's needs, not judgement about them.

    Self-check

    What does a vasectomy block, what does female sterilisation block, and name one difference between condoms and hormonal contraception.

    Show the answer

    A vasectomy blocks or seals sperm ducts so sperm are not ejaculated; female sterilisation blocks or cuts oviducts so sperm cannot meet an egg. Condoms act as a barrier and reduce STI risk; hormonal contraception changes hormone signals and may cause side effects. A pill needs daily adherence, while some hormonal methods last longer.

  • Higher

    Scope: Higher · 4.5.3.6

    Open revision guidance

    What to know

    • A fertility drug containing FSH and LH can be given to a woman to help eggs mature and be released; she may then become pregnant in the normal way.
    • In vitro fertilisation (IVF) begins with FSH and LH treatment to stimulate maturation of several eggs. Eggs are collected from the mother and fertilised by sperm from the father in a laboratory. The fertilised eggs develop into embryos. When they are tiny balls of cells, one or two embryos are inserted into the mother's uterus.
    • Fertility treatment can give a woman the chance to have a baby of her own, but it can be emotionally and physically stressful, success rates are not high, and multiple births can result, creating risks for both babies and the mother. Evaluate treatment from both patient and doctor perspectives.

    What to do in an exam

    • Put IVF stages in order: hormone stimulation, egg collection, laboratory fertilisation, embryo development, then insertion of one or two early embryos into the uterus.
    • In an evaluation, balance the possibility of pregnancy against treatment stress, limited success rates and the risks of multiple births; distinguish a possible outcome from a guaranteed success.

    In plain language

    IVF uses hormones to mature several eggs, which are collected and fertilised outside the body. Early embryos are then placed in the uterus. The process can offer a route to pregnancy, but it can be demanding and does not always work. Transferring more than one embryo may lead to multiple births, which brings risks for the mother and babies.

    Self-check

    What happens to eggs during IVF before an embryo is placed in the uterus, and name two concerns about fertility treatment.

    Show the answer

    FSH and LH stimulate several eggs to mature; eggs are collected and fertilised with sperm in a laboratory; the fertilised eggs develop into embryos, and one or two early embryos are inserted into the uterus. Treatment can be stressful, success rates are not high, and multiple births risk the mother and babies.

  • Higher

    Scope: Higher · 4.5.3.7

    Open revision guidance

    What to know

    • Adrenaline is produced by the adrenal glands during fear or stress. It increases heart rate and boosts delivery of oxygen and glucose to the brain and muscles, preparing the body for a fight-or-flight response.
    • Thyroxine is produced by the thyroid gland. It stimulates basal metabolic rate and has an important role in growth and development. Thyroxine levels are controlled by negative feedback.
    • In negative feedback, a change in a controlled level triggers responses that oppose the change; as the level returns towards its suitable range, the corrective signal is reduced. For thyroxine, pituitary thyroid-stimulating hormone (TSH) stimulates the thyroid to release thyroxine; rising thyroxine inhibits further TSH release, so thyroxine production falls. When thyroxine is low, reduced inhibition allows more TSH and stimulates more thyroxine release.
    • Use arrows in a diagram to identify the original change, control signal, target response and resulting correction.

    What to do in an exam

    • For fear or stress, link adrenal adrenaline to increased heart rate and increased delivery of oxygen and glucose to the brain and muscles.
    • Interpret a negative-feedback diagram by tracing each arrow and explaining how the response changes the original variable. For thyroxine, state the TSH-to-thyroid stimulation and the inhibition of TSH by increased thyroxine. Do not confuse a response that opposes a change with one that amplifies it.

    In plain language

    Adrenaline prepares the body for immediate action by increasing heart rate and supplying working muscles and the brain with more oxygen and glucose. Thyroxine supports metabolism, growth and development. Its level is regulated by negative feedback, a control pattern that reduces an imbalance rather than allowing it to grow.

    Self-check

    Where is adrenaline made, and what two linked effects help prepare the body for fight or flight? How is thyroxine level negatively fed back?

    Show the answer

    Adrenaline is made by the adrenal glands during fear or stress. It increases heart rate and boosts delivery of oxygen and glucose to the brain and muscles. Pituitary TSH stimulates the thyroid to release thyroxine; when thyroxine rises it inhibits further TSH release, reducing thyroxine production. When thyroxine falls, reduced inhibition allows more TSH.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.5.4.1

    Open revision guidance

    What to know

    • Plants produce hormones to coordinate growth and responses to light (phototropism) and gravity (gravitropism, also called geotropism). Unequal distributions of auxin cause unequal growth rates in roots and shoots, so growth can bend a plant in response to a directional stimulus.
    • In a shoot exposed to light from one side, auxin accumulates more on the shaded side and promotes greater cell elongation there, bending the shoot towards light. In gravitropism, more auxin on the lower side stimulates shoot elongation, bending a shoot upwards; in roots, more auxin on the lower side inhibits elongation, so the upper side grows faster and the root bends downwards. Thus shoots and roots respond differently to the same unequal auxin distribution.
    • Required practical activity 8 investigates the effect of light or gravity on newly germinated seedlings. Record results using length measurements and careful, labelled biological drawings showing the effects.

    What to do in an exam

    • Explain a tropism through stimulus direction, unequal auxin distribution, unequal growth on the two sides and the resulting bend; use phototropism for light and gravitropism/geotropism for gravity.
    • For the practical, use comparable newly germinated seedlings, change light direction or orientation to gravity, keep other conditions as similar as possible, measure growth/length and make labelled drawings that accurately show direction and form. For example, put one set in a light-proof box with a side opening and keep a comparison set in evenly lit conditions; record which way shoots bend, measure their lengths and draw both groups.

    In plain language

    A plant can grow towards or away from a directional stimulus because the two sides do not grow equally. Auxin is distributed unevenly, and the difference in growth bends the shoot or root. In the investigation, measurements give numerical evidence and a clear biological drawing shows the visible response; label what was observed rather than adding unobserved detail.

    Self-check

    What causes unequal growth in a plant tropism, and what two forms of evidence must be recorded in required practical 8?

    Show the answer

    Unequal auxin distributions cause different growth rates in roots and shoots. Record length measurements and careful, labelled biological drawings of the seedling effects.

  • Higher

    Scope: Higher · 4.5.4.1

    Open revision guidance

    What to know

    • Gibberellins are important in initiating seed germination. Ethene controls cell division and the ripening of fruits.
    • These hormone roles are explicitly Higher-only in this leaf. The mechanisms by which gibberellins and ethene work are not required.

    What to do in an exam

    • Match gibberellins to initiating seed germination and ethene to controlling cell division and fruit ripening.
    • Do not invent a detailed mechanism for these hormones: the specification explicitly says their mechanisms are not required.

    In plain language

    For this Higher-only outcome, learn the named roles rather than a biochemical pathway. Gibberellins help initiate germination, while ethene controls cell division and fruit ripening. AQA explicitly excludes the mechanisms of how those two hormones work.

    Self-check

    What roles do gibberellins and ethene have in plants, and what does AQA say about their mechanisms?

    Show the answer

    Gibberellins are important in initiating seed germination; ethene controls cell division and fruit ripening. Their mechanisms are not required.

  • Higher

    Scope: Higher · 4.5.4.2

    Open revision guidance

    What to know

    • Plant growth hormones are used in agriculture and horticulture. Auxins are used as weed killers, in rooting powders and to promote growth in plant tissue culture.
    • Ethene is used in the food industry to control fruit ripening during storage and transport. Gibberellins can end seed dormancy, promote flowering and increase fruit size.
    • The use of auxin weed killers has biodiversity implications: killing unwanted plants can also affect other plants and organisms that depend on them. Evaluate effects using evidence and consider both the intended benefit and possible ecosystem consequences.

    What to do in an exam

    • Match each use to the hormone: auxin for weed killers, rooting powders and tissue-culture growth; ethene for controlling fruit ripening in storage/transport; gibberellins for ending seed dormancy, promoting flowering and increasing fruit size.
    • For an application or evaluation, explain the desired horticultural or agricultural outcome, then assess any effects on biodiversity using information provided. For example, weed control may reduce competition for a crop, but killing non-crop flowering plants can reduce food or habitat for other organisms; weigh the benefit against the effect on the wider community.

    In plain language

    Hormones can be used to manage crops and stored food. Auxins help with weed control, rooting and tissue culture; ethene lets the food industry manage when fruit ripens; gibberellins can change seed dormancy, flowering and fruit size. Benefits need to be considered alongside environmental effects, especially when weed killing changes plant communities.

    Self-check

    Give all three listed uses of auxins and one use each of ethene and gibberellins.

    Show the answer

    Auxins are used as weed killers, rooting powders and to promote growth in tissue culture. Ethene controls fruit ripening during storage and transport. Gibberellins can end seed dormancy, promote flowering and increase fruit size.

Topic 4.6

Inheritance, variation and evolution

Paper 224 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.1.1

    Open revision guidance

    What to know

    • Sexual reproduction involves the fusion of male and female gametes. In animals the gametes are sperm and egg cells; in flowering plants they are pollen and egg cells. Genetic information from two gametes is mixed, producing variety among offspring. Gametes form by meiosis.
    • Asexual reproduction involves one parent and no fusion of gametes, so there is no mixing of genetic information. It uses mitosis and produces genetically identical offspring called clones.
    • Meiosis forms non-identical cells, whereas mitosis forms genetically identical cells. This distinction explains why sexual offspring vary and asexual offspring are clones.

    What to do in an exam

    • For an unfamiliar organism, identify whether reproduction uses one parent without gamete fusion or involves fusion of male and female gametes. Link the process to whether genetic information is mixed and whether offspring are clones.
    • When comparing cell division, state that meiosis forms gametes and mitosis is the only cell division involved in the described asexual reproduction.

    In plain language

    Sexual reproduction combines genetic information from two gametes, so offspring are not genetically identical to either parent. Asexual reproduction makes new organisms from one parent without combining gametes, so mitosis copies the parent's genetic information into clones.

    Self-check

    A flowering plant makes new plants from fused pollen and egg cells. Is this sexual or asexual reproduction, and what cell division makes the gametes?

    Show the answer

    It is sexual reproduction because pollen and egg cells fuse. The gametes are formed by meiosis.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.1.2

    Open revision guidance

    What to know

    • Cells in reproductive organs divide by meiosis to make gametes. The genetic information is copied, then the cell divides twice to form four gametes. Each gamete has a single set of chromosomes, half the usual number, and the four gametes are genetically different from one another.
    • At fertilisation, two gametes join and restore the normal chromosome number in the new cell. That cell divides by mitosis to increase cell number; as the embryo develops, its cells differentiate.
    • You need to explain how meiosis halves chromosome number and fertilisation restores it. Detailed named stages of meiosis are not required.

    What to do in an exam

    • Explain chromosome-number continuity: one full set is reduced to a single set in each gamete, and fusion of two gametes restores the full set.
    • Sequence the events accurately: copy genetic information, divide twice to make four different gametes, fertilisation, mitosis increases cell number, then cells differentiate during embryo development. Use a chromosome model to show how the number is halved and restored.

    In plain language

    Meiosis makes sex cells with half the usual chromosome number. When two sex cells fuse, their chromosome sets combine and restore the normal number. The first cell then grows into an embryo by mitosis, and developing cells become specialised.

    Self-check

    Why does meiosis need to halve chromosome number, and what restores the normal number?

    Show the answer

    Meiosis makes gametes with a single, half-sized chromosome set so that fertilisation does not double the chromosome number in every generation. Fusion of two gametes at fertilisation restores the normal number.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.1.3

    Open revision guidance

    What to know

    • Sexual reproduction produces variation. If conditions change, some variants may be better suited and natural selection can increase their representation. Humans can speed selection by choosing parents in selective breeding, for example to increase food production.
    • Asexual reproduction needs only one parent, avoids the time and energy of finding a mate, is faster, and can produce many identical offspring when conditions are favourable. Its offspring lack the variation produced by genetic mixing.
    • Some organisms use both modes. Malarial parasites reproduce asexually in a human host and sexually in a mosquito. Many fungi reproduce asexually by spores and also sexually, which gives variation. Many plants form seeds sexually and also reproduce asexually, such as strawberry plants by runners and daffodils by bulb division.
    • The specification limits required organism-reproduction knowledge to those examples. Use information supplied in a question to discuss other organisms.

    What to do in an exam

    • Compare methods against the conditions: sexual reproduction costs time and a mate but generates variation; asexual reproduction is rapid and can multiply a successful genotype in favourable conditions.
    • For an unfamiliar organism, base the comparison on information given, then link variation or rapid clone production to the likely advantage in that situation. Use supplied historical information to explain how understanding of malaria's causes and prevention has developed.

    In plain language

    Sexual reproduction is useful when variation could help some offspring cope with change. Asexual reproduction is an efficient way to make many copies when the parent is already successful and conditions suit it. The malaria parasite, fungi and some plants can switch between strategies in different contexts.

    Self-check

    Name the host in which the malaria parasite reproduces sexually, and give one named plant example of asexual reproduction.

    Show the answer

    The malaria parasite reproduces sexually in a mosquito. Strawberry plants reproduce asexually by runners, or daffodils by bulb division.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.1.4

    Open revision guidance

    What to know

    • The genetic material in a cell nucleus is DNA, a polymer made of two strands that form a double helix. DNA is arranged in structures called chromosomes. A gene is a small section of DNA on a chromosome; each gene codes for a particular sequence of amino acids used to make a specific protein.
    • An organism's genome is its entire genetic material. The human genome has been studied, and understanding it has medical importance.
    • AQA limits discussion of the importance of the human genome to searching for genes linked to different diseases, understanding and treating inherited disorders, and tracing human migration patterns from the past.

    What to do in an exam

    • Use the scale accurately: DNA forms chromosomes, a gene is a section of DNA, and the genome means all the genetic material of an organism.
    • When asked why the human genome matters, explain an application such as identifying disease-linked genes, improving understanding or treatment of inherited disorders, or investigating past human migration.

    In plain language

    DNA is the genetic material packaged into chromosomes. A gene is one section of that DNA that provides the code for making a particular protein. The genome is the whole collection of an organism's genetic material, which can be studied for health and historical questions.

    Self-check

    What is the difference between a gene and a genome, and give one specified reason to study the human genome.

    Show the answer

    A gene is a small section of DNA on a chromosome; the genome is all the genetic material of an organism. One reason to study the human genome is to search for genes linked to disease, understand inherited disorders, or trace past human migration.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.1.5

    Open revision guidance

    What to know

    • DNA is a polymer made from repeating nucleotide units. Each nucleotide contains a common sugar and phosphate group and one attached base. DNA has four bases: A, C, G and T.
    • In a DNA strand, sugar and phosphate sections alternate, with a base attached to each sugar. The sequence of every three bases is the code for a particular amino acid. The order of bases therefore controls the order of amino acids assembled to make a particular protein.
    • For diagrams, recognise the repeating nucleotide arrangement and the relationship between base sequence and amino-acid sequence. You may be asked to interpret a DNA diagram but are not required to reproduce one.

    What to do in an exam

    • Identify the sugar, phosphate and one of four bases as the components of a nucleotide; identify A, C, G and T as the four DNA bases.
    • Explain the information sequence: base triplets specify amino acids, and the order of amino acids makes a particular protein. This common-tier card does not require protein-synthesis stages or mutation effects.

    In plain language

    DNA is a long chain made by repeating four-part-choice building blocks. Each building block has sugar, phosphate and one base. The order of bases stores instructions: groups of three specify amino acids, and the amino-acid order determines which protein is made.

    Self-check

    What three components make up a DNA nucleotide, and what does a sequence of three bases specify?

    Show the answer

    A nucleotide has a common sugar, a phosphate group and one of four bases. A sequence of three bases codes for a particular amino acid.

  • Higher

    Scope: Higher · 4.6.1.5

    Open revision guidance

    What to know

    • In complementary DNA strands, C pairs with G and T pairs with A. A gene's base sequence provides a template for protein synthesis at ribosomes. Carrier molecules bring specific amino acids, which are joined in the coded order to form a protein chain. The chain folds into a unique shape that determines how it works, for example as an enzyme, hormone or structural protein such as collagen.
    • A change in DNA structure can change the amino-acid sequence and therefore the protein made. Most mutations do not alter the protein, or change it too little to affect its appearance or function. A few produce an altered protein with a different shape: an enzyme may no longer fit its substrate, or a structural protein may lose strength.
    • A genetic variant in coding DNA can change a protein's activity. Non-coding DNA does not code for proteins; it can switch genes on or off, so variants there can change gene expression and phenotype. Not all mutations affect phenotype.
    • Detailed structures of mRNA, tRNA, amino acids and proteins are not required.

    What to do in an exam

    • Explain a coding mutation as a possible chain from altered DNA sequence to changed protein sequence or shape, then to altered function and possibly phenotype. Do not claim every mutation changes a protein or phenotype.
    • Distinguish coding variants, which may change protein activity, from non-coding variants, which may alter whether or how much a gene is expressed. Use complementary pairing C-G and T-A when interpreting a DNA diagram, and model insertions or deletions to illustrate a changed sequence.

    In plain language

    A gene's DNA sequence guides the order of amino acids in a protein. The chain folds into a shape that lets it do a job. Some DNA changes do nothing noticeable; others alter a protein or change when a gene is switched on, which can affect an organism's characteristics.

    Self-check

    How could a mutation in coding DNA affect phenotype, and how could a variant in non-coding DNA affect it?

    Show the answer

    A coding mutation may alter the protein sequence or shape and therefore its activity, changing phenotype. A non-coding variant may change how a gene is switched on or off, altering expression and phenotype. Many mutations have no phenotypic effect.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.1.6

    Open revision guidance

    What to know

    • Gamete: reproductive cell. Chromosome: DNA structure carrying genes. Gene: DNA section; allele: gene version. Genotype: allele combination; phenotype: expressed characteristic. Identical alleles are homozygous, different ones heterozygous. A dominant allele shows with one copy; a recessive one needs two and no dominant allele.
    • Single-gene examples are fur colour in mice and red-green colour blindness in humans. Most characteristics instead result from several genes interacting.
    • Worked completion, not cross construction: for a supplied Aa × aa square with A, a and a, a gamete labels already printed, combine them to fill Aa, aa, Aa, aa. The genotype ratio is 1 Aa : 1 aa; with A dominant, the phenotypes are also 1 : 1 and each has probability 1/2 (50%).
    • Pedigree inference: an affected recessive child is aa. If both parents are unaffected, each must have passed on a and must be a carrier, Aa. An unaffected sibling may be AA or Aa.

    What to do in an exam

    • Complete supplied Punnett-square cells using given gamete labels. Count outcomes as simple ratios or direct proportions; probability does not guarantee the result in a small family.
    • Use affected and unaffected relatives in a family tree to infer genotypes, distinguishing phenotype from a possible carrier genotype.

    In plain language

    A supplied square gives possible offspring; a family tree can show when an unaffected parent carries a recessive allele.

    Self-check

    If two unaffected parents have a recessive affected child, what are the parents' genotypes?

    Show the answer

    The child is aa, so each parent passed on a. As they are unaffected, both are carriers, Aa.

  • Higher

    Scope: Higher · 4.6.1.6

    Open revision guidance

    What to know

    • Higher-tier students construct a single-gene cross using a Punnett square and use probability theory to predict possible offspring. The square lays out the alleles that each parent can pass on in their gametes.
    • For a heterozygous cross Aa × Aa, each parent can pass on A or a. The four equally likely combinations are AA, Aa, Aa and aa. The genotype ratio is 1 AA : 2 Aa : 1 aa. If A is dominant, the phenotype ratio is 3 showing the dominant phenotype : 1 showing the recessive phenotype.
    • These are probabilities for each offspring. They do not ensure that a small number of actual offspring will match the predicted ratio exactly.

    What to do in an exam

    • Choose and state allele symbols, write both parental genotypes, list the possible gametes from each parent, and combine one gamete from each parent in every Punnett-square cell.
    • Count genotypes and apply dominance to calculate phenotype probabilities. Express results as a ratio, fraction or percentage and make clear which outcome is being described.

    In plain language

    To construct a genetic cross, work out which allele each parent can pass on and combine every possible pair. The resulting square shows probabilities. It predicts what could happen across many offspring, not a fixed result for every small family.

    Self-check

    For Aa × Aa where A is dominant, what is the probability that an offspring is aa, and what is the probability of the recessive phenotype?

    Show the answer

    One of the four equally likely combinations is aa, so the probability is 1/4 or 25%. Since aa expresses the recessive phenotype, that phenotype also has probability 1/4 or 25%.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.1.7

    Open revision guidance

    What to know

    • Some disorders are inherited because particular alleles are passed from parents to offspring. Polydactyly, having extra fingers or toes, is caused by a dominant allele. Cystic fibrosis is a disorder of cell membranes caused by a recessive allele.
    • Embryo screening and gene therapy may alleviate suffering. Students should make informed judgements about economic, social and ethical issues when relevant information is provided. A balanced judgement weighs possible benefits, costs and concerns rather than treating one position as the only answer.

    What to do in an exam

    • Use the stated dominant or recessive inheritance pattern in a genetic cross to identify which genotypes could show the disorder.
    • For an embryo-screening or gene-therapy question, use the supplied evidence to consider possible reduction of suffering alongside financial cost, social consequences and ethical arguments. Support a conclusion with reasons from the information.

    In plain language

    An inherited disorder can result when an offspring receives an allele associated with a condition. A dominant allele can affect someone with one copy, while a recessive allele requires two copies. Decisions about screening involve evidence as well as personal, social and ethical considerations.

    Self-check

    Which specified disorder is caused by a dominant allele, and which is caused by a recessive allele?

    Show the answer

    Polydactyly is caused by a dominant allele. Cystic fibrosis, a disorder of cell membranes, is caused by a recessive allele.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.1.8

    Open revision guidance

    What to know

    • Ordinary human body cells have 23 pairs of chromosomes. Twenty-two pairs control characteristics only; the remaining pair carries the genes that determine sex.
    • In females, the sex chromosomes are XX. In males, they are XY. An egg therefore carries an X chromosome; sperm carry X or Y. A sex-inheritance cross gives XX or XY in a 1:1 ratio, predicting equal probabilities of female and male offspring.
    • Use direct proportion and simple ratios to express outcomes of genetic crosses. A ratio describes the relative probabilities of the possible combinations.

    What to do in an exam

    • Set out the possible sex-chromosome combinations in a genetic cross and count the outcomes. Express the result as a simple ratio or proportion; one X-carrying egg and X- or Y-carrying sperm produce XX or XY combinations in a 1:1 ratio.
    • Connect each chromosome pair to the correct sex: XX is female and XY is male.

    In plain language

    Most human chromosomes are not the sex-chromosome pair. Females have two X chromosomes and males have one X and one Y. A cross shows the possible combinations in offspring, and a simple ratio summarises their likelihood.

    Self-check

    How many chromosome pairs are in an ordinary human body cell, and which sex-chromosome combinations are specified for females and males?

    Show the answer

    There are 23 pairs. Females are XX and males are XY.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.2.1

    Open revision guidance

    What to know

    • Variation means differences in characteristics between individuals in a population. An organism's phenotype develops through interaction between its genome and its environment. Differences can result from inherited genes, environmental conditions during development, or a combination of genes and environment.
    • There is usually extensive genetic variation within a population of a species. All variants arise from mutations. Most mutations have no effect on phenotype, some influence phenotype, and very few determine phenotype.
    • Mutations occur continuously. Very rarely a mutation produces a new phenotype. If that phenotype is suited to an environmental change, it can lead to a relatively rapid change in the species.

    What to do in an exam

    • When explaining an observed difference, distinguish inherited genetic causes from environmental causes, and consider that both may contribute.
    • Do not state that every mutation changes appearance. Explain that most have no phenotypic effect; a rare new phenotype may become important if it is suited to changed conditions.

    In plain language

    Individuals differ because they inherit different genetic variants, develop in different conditions, or experience both. Mutations create variants, but most have no visible effect. A rare change that helps in a changed environment can affect how the population changes over time.

    Self-check

    Name the three possible sources of variation described in this topic and state how most mutations affect phenotype.

    Show the answer

    Variation can arise from inherited genetic differences, environmental differences, or a combination. Most mutations have no effect on phenotype.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.2.2

    Open revision guidance

    What to know

    • Evolution is a change in the inherited characteristics of a population over time through natural selection. It may result in the formation of a new species. The theory states that all species of living things evolved from simple life forms that first developed more than three billion years ago.
    • Individuals in a population vary. If environmental conditions favour a variant, individuals with the corresponding phenotype are more likely to survive and reproduce. They pass inherited characteristics to offspring, so those characteristics can become more common over generations.
    • If two populations of one species become so different in phenotype that they can no longer interbreed to produce fertile offspring, they have formed two new species.

    What to do in an exam

    • Build a natural-selection explanation in order: inherited variation exists, an environmental condition favours some variants, those individuals survive and reproduce more, their inherited characteristics are passed on, and the population changes over generations.
    • Describe evolution as change in a population across generations, not an individual changing because it needs to. Identify inability to produce fertile offspring as the stated species boundary.

    In plain language

    Natural selection changes populations over generations. Individuals that already have inherited features suited to their surroundings are more likely to leave offspring. As those features are passed on, their frequency can rise in the population.

    Self-check

    What happens to a population when individuals with an inherited, advantageous variant reproduce more successfully?

    Show the answer

    They pass the variant to offspring, so the inherited characteristic can become more common and the population's inherited characteristics change over generations.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.2.3

    Open revision guidance

    What to know

    • Selective breeding, also called artificial selection, is when humans breed plants and animals for particular genetic characteristics. People have done this for thousands of years, since breeding food crops from wild plants and domesticating animals.
    • Choose parents from a mixed population because they show the desired characteristic, breed them together, then choose offspring showing the characteristic and breed those together. Repeating selection over many generations can produce offspring that all show the desired characteristic.
    • The characteristic can be chosen for usefulness or appearance. Specified aims include disease resistance in food crops, animals producing more meat or milk, domestic dogs with a gentle nature, and large or unusual flowers.
    • Selective breeding can lead to inbreeding. Some breeds may consequently be particularly prone to disease or inherited defects.

    What to do in an exam

    • Describe the repeated selection process rather than saying the organism deliberately changes: select parents, breed, select desired offspring, and repeat for many generations.
    • Explain an impact by connecting a selected characteristic to its intended use, then consider the possible inbreeding consequence of increased disease or inherited defects. When information is provided, evaluate benefits, risks and related ethical issues.

    In plain language

    People choose which organisms reproduce so a useful or attractive feature becomes more common. They keep selecting offspring with that feature over many generations. Repeated selection can also increase the chance that some breeds have inherited problems.

    Self-check

    What sequence of selection is repeated to produce a chosen characteristic, and name one risk of selective breeding.

    Show the answer

    Breed parents with the desired feature, choose offspring showing it, breed those offspring, and repeat over many generations. Inbreeding can make some breeds more prone to disease or inherited defects.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.2.4

    Open revision guidance

    What to know

    • Genetic engineering modifies an organism's genome by introducing a gene from another organism to give a desired characteristic. Genes from human or other chromosomes can be cut out and transferred into cells of another organism.
    • Plant crops have been engineered to resist disease or produce bigger, better fruits. Genetically modified (GM) crops include varieties resistant to insect attack or herbicides, and GM crops generally show increased yields. Engineered bacterial cells can produce useful substances such as human insulin for treating diabetes.
    • Possible concerns about GM crops include effects on populations of wild flowers and insects. Some people feel that effects of eating GM crops on human health have not been fully explored. Modern medical research is exploring genetic modification as a possible way to overcome some inherited disorders.
    • Students should explain potential benefits and risks in agriculture and medicine and recognise that some people object. Use the evidence and context rather than assuming all applications have identical effects.

    What to do in an exam

    • Describe the basic idea as moving a desired gene from one organism into another organism's cells so the recipient can develop a desired characteristic.
    • Evaluate a proposed use by setting out its stated benefit, possible risk or uncertainty, and the people or organisms affected. For crops, address the given yield, disease, insect, herbicide, wildlife or health evidence; for medicine, use the supplied context.

    In plain language

    Genetic engineering moves a gene between organisms to give a new feature. Crops may resist pests or herbicides, and bacteria can be given the ability to make human insulin. The benefits need to be weighed against possible environmental or health concerns and objections.

    Self-check

    Name one agricultural use and one medical use of genetic engineering from the specification, and state one concern about GM crops.

    Show the answer

    Crops can be engineered for disease resistance or bigger, better fruit; bacteria can be engineered to make human insulin for diabetes treatment. Concerns include effects on wild flowers and insects or uncertainty about effects on human health.

  • Higher

    Scope: Higher · 4.6.2.4

    Open revision guidance

    What to know

    • Higher-tier students describe the main genetic-engineering steps. Enzymes isolate the required gene and the gene is inserted into a vector, usually a bacterial plasmid or a virus.
    • The vector is used to insert the gene into the required cells. Genes are transferred to cells of animals, plants or microorganisms at an early stage of development so that the organism develops with the desired characteristic.
    • A vector carries the selected gene into target cells. The target organism can then develop from modified cells containing that gene.

    What to do in an exam

    • Put the process in order: use enzymes to isolate the gene, insert it into a plasmid or virus vector, use the vector to insert the gene into target cells, and transfer it early enough that the organism develops with the desired feature.
    • When a question gives details of a technique, identify the gene, vector, target cell and desired characteristic without adding unprovided procedural steps.

    In plain language

    A desired gene is isolated and put into a carrier, usually a bacterial plasmid or virus. The carrier takes the gene into target cells. If transfer occurs early in development, the organism can grow with the desired characteristic.

    Self-check

    What is the role of a vector, and name the two usual types of vector specified by AQA?

    Show the answer

    A vector carries the required gene into target cells. The usual vectors are a bacterial plasmid or a virus.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.2.5

    Open revision guidance

    What to know

    • Cloning produces genetically identical organisms. Plant tissue culture grows identical plants from small cell groups; it can conserve rare plants or supply commercial nurseries. Cuttings are an older, simple way to produce many plants identical to their parent.
    • Embryo transplants split developing animal-embryo cells before specialisation and transfer the identical embryos to host mothers.
    • Adult cell cloning: remove the nucleus from an unfertilised egg, insert a nucleus from an adult body cell such as skin, then use an electric shock to stimulate division. The embryo cells have the adult donor's genetic information. At the ball-of-cells stage, transfer the embryo to an adult female's womb.
    • Evaluation examples, not a fixed recall list: cloning can multiply useful crops or conserve rare plants, but uniform crops have low genetic diversity and may all be susceptible to one pathogen. Therapeutic cloning may yield patient-matched stem cells that are not rejected (AQA 4.1.2.3), but treatment is only a possibility. Animal cloning has low success; failed development or pregnancy may cause suffering. Embryo use and animal welfare raise ethical concerns; no percentages are specified.

    What to do in an exam

    • Distinguish methods by cell source, then evaluate the scenario: weigh rapid multiplication or rare-plant conservation against shared disease vulnerability, animal-cloning failure/welfare, or medical embryo-use and treatment concerns.

    In plain language

    Cloning multiplies genotypes and their vulnerabilities; possible benefits must be weighed against disease, welfare and ethical risks.

    Self-check

    Name one benefit and one risk of cloning a crop.

    Show the answer

    Cloning multiplies useful or rare plants, but low diversity may leave them vulnerable to one pathogen.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.3.1

    Open revision guidance

    What to know

    • Charles Darwin proposed evolution by natural selection after observations on a worldwide expedition, years of experimentation and discussion, and links to developing knowledge of geology and fossils. Within a species, individuals vary; those with characteristics best suited to their environment are more likely to survive and breed successfully; they pass those characteristics to the next generation.
    • Darwin published On the Origin of Species in 1859. The proposal was controversial and only gradually accepted because it challenged the idea that God made all living plants and animals, there was insufficient evidence at publication to convince many scientists, and the mechanism of inheritance and variation was not understood until about 50 years later.
    • Jean-Baptiste Lamarck and other earlier theories mainly proposed that changes acquired during an organism's lifetime could be inherited. In the vast majority of cases this does not happen. Study of creationism is not required.

    What to do in an exam

    • Explain natural selection as inherited variation followed by differential survival and breeding, then transmission of successful characteristics to the next generation.
    • When asked why Darwin's theory took time to be accepted, use the historical reasons: conflict with beliefs, limited evidence at the time and missing understanding of inheritance. Do not claim Darwin had knowledge of genes that was developed later.

    In plain language

    Darwin argued that populations change because individuals with helpful inherited differences are more likely to leave offspring. His idea took time to win acceptance: it challenged familiar beliefs, the evidence was incomplete, and inheritance itself was not yet understood.

    Self-check

    Give two reasons the theory of evolution by natural selection was only gradually accepted after Darwin published it in 1859.

    Show the answer

    It challenged the idea that God created living things, evidence was insufficient to convince many scientists at the time, and the mechanism of inheritance and variation was not understood until about 50 years later. Any two are sufficient.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.3.2

    Open revision guidance

    What to know

    • Alfred Russel Wallace independently proposed evolution by natural selection. Darwin and Wallace published joint writings in 1858, prompting Darwin to publish On the Origin of Species in 1859. Wallace gathered evidence for evolutionary theory worldwide and is especially known for work on warning colouration in animals and his theory of speciation.
    • Wallace did pioneering work on speciation, but evidence gathered over time has led to today's understanding. New species can arise when populations become separated and experience different conditions. Mutations create variation; different variants may be favoured in each population. Over many generations the populations become increasingly different until they can no longer interbreed to produce fertile offspring.
    • AQA expects students to describe the steps giving rise to new species and explain the impact of Darwin's and Wallace's ideas on biology.

    What to do in an exam

    • For a speciation explanation, connect separation of populations, different conditions and selection of different inherited variants over generations to increasing difference and eventual reproductive isolation.
    • For historical impact, explain that the proposals provided a mechanism for evolutionary change and helped establish natural selection and speciation as scientific explanations, while evidence and understanding developed further over time.

    In plain language

    Darwin and Wallace independently reached the idea that natural selection drives evolution, and their joint 1858 work prompted Darwin's book the next year. New species form when separated populations change in different ways until they cannot produce fertile offspring together.

    Self-check

    What happened in 1858 and 1859 in the work of Wallace and Darwin, and what is the stated biological endpoint of speciation?

    Show the answer

    Darwin and Wallace published joint writings in 1858; Darwin published On the Origin of Species in 1859. Speciation reaches the endpoint where the populations can no longer interbreed to produce fertile offspring.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.3.3

    Open revision guidance

    What to know

    • In the mid-19th century, Gregor Mendel carried out breeding experiments on plants. He observed that inheritance of each characteristic is determined by units passed to descendants unchanged. The importance of this discovery was not recognised until after his death.
    • In the late 19th century, scientists observed chromosome behaviour during cell division. In the early 20th century they noticed that chromosomes and Mendel's units behaved similarly, leading to the idea that the units, now called genes, are located on chromosomes.
    • In the mid-20th century, scientists determined DNA structure and worked out the mechanism of gene function. Work by many scientists contributed to development of gene theory.
    • Mendel's results preceded knowledge that could link his inherited units to chromosomes and genes. Later chromosome observations and gene-function research made the significance of the earlier inheritance work clearer.

    What to do in an exam

    • Put the discoveries in chronological order: Mendel's plant breeding and inherited units in the mid-19th century; chromosome behaviour in the late 19th; the link between chromosomes and Mendel's units in the early 20th; DNA structure and gene function in the mid-20th.
    • Explain delayed recognition by connecting Mendel's earlier observations with later evidence about chromosomes and genes, rather than suggesting he knew the molecular mechanism.

    In plain language

    Mendel described patterns of inherited units before scientists knew about genes or how chromosomes carried them. Later work showed that chromosome behaviour matched the patterns he had found, and research on DNA and gene function built the modern theory.

    Self-check

    What observation in the early 20th century linked Mendel's inherited units with genes?

    Show the answer

    Scientists saw that chromosomes and Mendel's inherited units behaved in similar ways during inheritance, leading to the idea that the units, now called genes, were on chromosomes.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.3.4

    Open revision guidance

    What to know

    • The theory of evolution by natural selection is now widely accepted. Evidence includes fossils and antibiotic resistance in bacteria.
    • Evidence that characteristics are passed from parents to offspring in genes supports Darwin's explanation of inherited change. Fossil records show organisms from the past, and antibiotic resistance provides an observable example of bacterial populations evolving.
    • Together, inherited genetic information, the fossil record and the evolution of resistance support the explanation that populations change over time.

    What to do in an exam

    • Describe evidence by identifying what it shows: fossils record organisms from the past and change through time; antibiotic resistance shows changes in bacterial populations; genes explain how characteristics can be inherited.
    • Use the specified lines of evidence to support evolution rather than treating one observation as a complete account of every evolutionary event.

    In plain language

    Evolution is supported by several kinds of evidence. Fossils preserve traces of past life, genes explain how traits are inherited, and changing antibiotic resistance can be seen in bacterial populations.

    Self-check

    Name the two evidence examples for evolution specified in this section, and state what genes add to the evidence.

    Show the answer

    The specified examples are fossils and antibiotic resistance in bacteria. Genes show how characteristics can be passed to offspring, supporting inherited change.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.3.5

    Open revision guidance

    What to know

    • Fossils are remains from millions of years ago found in rocks. They form when decay conditions are absent and parts remain, when minerals replace parts as they decay, or as preserved traces such as footprints, burrows and rootlet traces.
    • Many early organisms were soft-bodied and left few traces; geological activity destroyed many more. The incomplete record limits certainty about how life began.
    • Fossils show how much or little organisms changed as life developed. In an evolutionary tree, a node is a shared common ancestor; a more recent shared node means closer relationship.

    What to do in an exam

    • Identify the fossil-forming process from a description and interpret supplied charts, graphs, tables or evolutionary trees. Trace two branches to their shared node; the more recent node indicates the closer relationship, not visual spacing of branch tips.
    • Use fossils to describe change or similarity while remembering that missing fossils do not prove an organism never existed.

    In plain language

    Fossils show past life and its changes, but many organisms left no preserved remains and later geology destroyed evidence. Trees use shared ancestors to show relationships.

    Self-check

    On a tree, what does a shared node mean, and which of two pairs is closer related?

    Show the answer

    A node represents a common ancestor. The pair whose branches meet at the more recent node is more closely related; tip spacing on the page is irrelevant.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.3.6

    Open revision guidance

    What to know

    • Extinction occurs when no individuals of a species remain alive. AQA requires students to describe factors that may contribute to a species becoming extinct.
    • A population can decline when environmental conditions change faster than the population can adapt, when habitat or food is lost, or when new predators, competitors or pathogens affect survival and reproduction. A catastrophic environmental event can also cause a rapid decline. If too few individuals remain to reproduce successfully, the species may disappear.
    • These are examples of possible contributing factors, not a fixed list that explains every extinction. A particular answer should connect the factor in the question to reduced survival or reproduction.

    What to do in an exam

    • Use the scenario to identify a factor and explain a causal chain, for example changed conditions reduce survival or breeding, the population declines, and if all individuals die the species is extinct.
    • Distinguish local disappearance from the specification's definition: extinction means there are no remaining living individuals of that species.

    In plain language

    A species is extinct only when its last living individual is gone. Many pressures can reduce a population, including environmental change, loss of food or habitat, disease, predators or competition. A good explanation links the pressure to survival and reproduction.

    Self-check

    What does extinction mean, and how could a new pathogen contribute to it?

    Show the answer

    Extinction means no individuals of the species remain alive. A pathogen could reduce survival or reproduction so much that the population declines and eventually no individuals remain.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.3.7

    Open revision guidance

    What to know

    • Bacteria reproduce rapidly, so bacterial populations can evolve quickly. Mutations in bacterial pathogens produce new strains. Some strains are resistant to an antibiotic and are not killed by it. They survive and reproduce, so the proportion and number of resistant bacteria in the population rise.
    • The resistant strain can spread because people are not immune to it and there may be no effective treatment. MRSA is a named example of bacteria resistant to antibiotics.
    • To reduce development of resistant strains, doctors should not prescribe antibiotics inappropriately, for example for viral or non-serious infections; patients should complete their prescribed antibiotic course so that all infection-causing bacteria are killed and none survive to mutate into resistant strains; and agricultural antibiotic use should be restricted.
    • Developing new antibiotics is costly and slow, and is unlikely to keep up with the emergence of new resistant strains.

    What to do in an exam

    • Explain resistance by selection: variation from mutation exists, antibiotics kill susceptible bacteria, resistant bacteria survive and reproduce, and the resistant strain becomes more common.
    • For prevention, give the relevant action and its reason. Do not use antibiotics for viral illness, follow the prescribed course, and restrict agricultural use. Include cost and development time when evaluating new antibiotics.

    In plain language

    An antibiotic does not teach bacteria how to resist it. A resistant variant may already exist because of mutation. Treatment removes susceptible bacteria while resistant bacteria survive and multiply, so responsible antibiotic use helps slow the spread.

    Self-check

    Why can antibiotic treatment increase the proportion of resistant bacteria, and give one action that reduces this problem.

    Show the answer

    Susceptible bacteria are killed while resistant bacteria survive and reproduce, increasing their proportion. Avoiding inappropriate prescriptions, completing a prescribed course, or restricting agricultural antibiotic use can help reduce the problem.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.6.4

    Open revision guidance

    What to know

    • Linnaeus's hierarchy, based on structure and characteristics, is kingdom, phylum, class, order, family, genus, species. Binomial names give an organism's genus and species.
    • Better microscopes revealed internal structures and biochemical understanding progressed; chemical-analysis evidence led Carl Woese to propose three domains. Archaea are primitive bacteria usually living in extreme environments, bacteria are true bacteria, and eukaryota includes protists, fungi, plants and animals.
    • Evolutionary trees use current classification data for living organisms and fossils for extinct organisms. A node is a common ancestor; branches sharing a more recent node show closer relationship.
    • Optional illustration, not a named AQA recall requirement: comparing DNA sequences can provide chemical evidence about relatedness. The AQA leaf names chemical analysis generally, not DNA-sequencing methods or details.

    What to do in an exam

    • Recall the Linnaean ranks in order from broadest to most specific: kingdom, phylum, class, order, family, genus, species. In a binomial name, identify the genus and species.
    • Classify using supplied characteristics. On a tree, trace branches to their shared node; a more recent node means a closer relationship, not closer visual spacing of tips.

    In plain language

    Classification changes as evidence improves. On an evolutionary tree, a more recent shared branch point means two organisms are more closely related.

    Self-check

    What does a more recent shared node indicate about two organisms?

    Show the answer

    They share a more recent common ancestor and are more closely related.

Topic 4.7

Ecology

Paper 221 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.1.1

    Open revision guidance

    What to know

    • An ecosystem is the interaction between a community of living organisms (biotic) and the non-living (abiotic) parts of their environment. Organisation runs from individual organisms through populations and communities to the whole ecosystem.
    • Organisms need materials from their surroundings and from other organisms to survive and reproduce. Plants commonly compete for light, space, water and soil mineral ions; animals commonly compete for food, mates and territory.
    • Species in a community depend on one another for resources and interactions such as food, shelter, pollination and seed dispersal. Removing one species can affect the community; this is interdependence. A stable community has species and environmental factors in balance, so population sizes remain fairly constant.

    What to do in an exam

    • Use charts, graphs or tables to describe interactions and changes in populations; identify a trend and explain a plausible cause using evidence.
    • For an unfamiliar habitat, identify likely limiting resources and explain which organisms would compete for each.

    In plain language

    A community is not a list of species: its members affect one another. If a food source, pollinator or predator changes, other populations can change too. Competition occurs when organisms need the same limited resource; interdependence describes the wider network of reliance.

    Self-check

    Plants in a crowded habitat grow poorly. Name two resources they may be competing for and explain what interdependence means.

    Show the answer

    They may compete for light, space, water or mineral ions. Interdependence means species rely on other species, for example for food, pollination or shelter, so a change to one can affect others.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.1.2

    Open revision guidance

    What to know

    • Abiotic factors are non-living environmental conditions that affect organisms and their distribution. AQA specifies light intensity, temperature, moisture levels, soil pH and mineral content, wind intensity and direction, carbon dioxide levels for plants, and oxygen levels for aquatic animals.
    • A change in any of these conditions can alter survival, growth, reproduction or the availability of resources, so the abundance and distribution of species in a community may change.

    What to do in an exam

    • Given data or a habitat description, connect the measured factor to the species response; cite values, comparisons or trends rather than making unsupported claims.
    • Interpret tables and graphs that relate abiotic measurements to organism abundance or distribution.

    In plain language

    Abiotic means not alive. Species have ranges of conditions in which they can survive and reproduce. For example, a change in light can affect plant photosynthesis, while oxygen availability can affect aquatic animals. Explain the link between the particular factor and the organism, then use the supplied evidence.

    Self-check

    Name all seven abiotic factors listed by AQA for community effects.

    Show the answer

    Light intensity; temperature; moisture; soil pH and mineral content; wind intensity and direction; carbon dioxide levels for plants; and oxygen levels for aquatic animals.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.1.3

    Open revision guidance

    What to know

    • Biotic factors are effects caused by living organisms. AQA names availability of food, new predators arriving, new pathogens, and one species outcompeting another until numbers are no longer sufficient to breed.
    • A change to a biotic factor can affect population size and the distribution of organisms, and may cause linked changes in other species in the community.

    What to do in an exam

    • Use the context or data to explain a causal chain, such as a new predator reducing prey numbers and then affecting organisms that depend on that prey.
    • Interpret community charts, graphs and tables and distinguish a supported explanation from a possible but unproven cause.

    In plain language

    Biotic means living. Food supply, predators, pathogens and competition all involve organisms affecting other organisms. Follow the effects through the community: a population change can alter food availability or competition for another species.

    Self-check

    How can a new pathogen affect a community beyond the species it infects?

    Show the answer

    It can reduce that species' population and change food, competition or other dependencies, causing population changes in species linked to it.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.1.4

    Open revision guidance

    What to know

    • Adaptations are features that enable organisms to survive in the conditions in which they normally live. They may be structural (body form), behavioural (what an organism does) or functional (processes inside it).
    • Some organisms live in extreme environments, including conditions of high temperature, pressure or salt concentration. Such organisms are extremophiles; bacteria living in deep-sea vents are an AQA example.

    What to do in an exam

    • Given information about an organism and its environment, identify the adaptation type and explain how the feature supports survival in those conditions.
    • Do not merely name an adaptation: link feature, environmental challenge and survival or reproduction.

    In plain language

    An adaptation is useful in a particular environment, not universally useful. A structural feature is part of the body, a behaviour is an action, and a functional adaptation is how the organism works internally. Extremophiles tolerate conditions that would be extreme for most organisms.

    Self-check

    What is an extremophile, and which example does AQA name?

    Show the answer

    An extremophile lives in an extreme environment such as one with high temperature, pressure or salt concentration. AQA names bacteria living in deep-sea vents.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.2.1

    Open revision guidance

    What to know

    • Photosynthetic organisms make the biomass that supports life. Food chains represent feeding relationships and start with a producer, usually a green plant or alga that makes glucose by photosynthesis. Producers are eaten by primary consumers, then secondary consumers and possibly tertiary consumers.
    • Ecologists use methods including transects and quadrats to determine species distribution and abundance. For abundance data, understand mean, mode and median, calculate arithmetic means, and plot suitable graphs with appropriate axis scales.
    • Predators kill and eat other animals; prey are eaten. In a stable community, predator and prey numbers rise and fall in cycles; students must interpret graphs modelling these cycles.

    What to do in an exam

    • Trace a food chain with arrows in the direction of energy/biomass transfer, identify each trophic role, and distinguish predator from prey.
    • Calculate a sample mean and select a suitable graph and scale. On predator-prey graphs, compare peaks and troughs and explain linked changes without assuming simultaneous responses.

    In plain language

    A food chain starts with an organism that makes its own food. Sampling estimates which species are present and how common they are without counting every organism. Predator numbers often respond after prey numbers change, so the two curves can cycle with a time lag.

    Self-check

    A predator population rises after its prey population rises. What may happen to the prey next, and which statistic is found by adding values and dividing by their number?

    Show the answer

    More predators may increase predation and prey numbers may then fall. Adding values and dividing by their number gives the arithmetic mean.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.2.2

    Open revision guidance

    What to know

    • Many materials cycle between the abiotic and biotic parts of an ecosystem. Recycling supplies building blocks for future organisms.
    • In the carbon cycle, plants take in atmospheric carbon dioxide during photosynthesis and build carbon into plant organic compounds. Animals receive that carbon by feeding on plants or other animals. Plants, animals and decomposer microorganisms release carbon dioxide by respiration; decomposition also returns mineral ions to soil. Combustion of fossil fuels releases stored carbon as carbon dioxide.
    • In the water cycle, water evaporates from seas, lakes and other wet surfaces and plants release water vapour by transpiration. Vapour condenses into cloud droplets, then returns as precipitation. Water flows as surface runoff to rivers and seas or enters soil, where plant roots take it up; the water is transported through plants and can return to air by transpiration. These processes supply fresh water to land organisms.
    • Students are not expected to study the nitrogen cycle.

    What to do in an exam

    • Trace carbon through atmosphere, plants and food chains, then back to air through respiration and decomposition; add fossil-fuel combustion as a carbon-dioxide source.
    • Trace water through evaporation, transpiration, condensation, precipitation, runoff, soil and root uptake. Label directions clearly when completing a cycle diagram.
    • Explain why carbon and water cycling matters to living organisms; do not add nitrogen-cycle detail as required knowledge.

    In plain language

    Carbon atoms move from air into plant matter, then through feeding to animals. Respiration and decomposition return carbon dioxide to air, and burning fossil fuels adds carbon that had been stored underground. Water cycles from surface and plants into vapour, forms clouds, falls as precipitation, then runs off or enters soil for root uptake. Matter is reused rather than created anew for each organism.

    Self-check

    Trace one carbon pathway from air through organisms and back to air, and one water pathway from cloud to plant.

    Show the answer

    Carbon dioxide in air is fixed by plant photosynthesis, passed to an animal by feeding, then released as carbon dioxide by respiration or decomposition. Cloud droplets fall as precipitation; water runs off or enters soil and is absorbed by plant roots.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.2.3

    Open revision guidance

    What to know

    • Decomposition is the breakdown of biological material by microorganisms. Water is needed for microorganisms and their extracellular enzymes to function; dry conditions slow decay. Oxygen supports aerobic respiration by decomposers and usually faster aerobic decay; when oxygen is absent, anaerobic decay can produce methane.
    • As temperature rises from low values, enzyme-controlled reactions and microbial respiration generally speed up towards an optimum. Above the organisms' optimum, enzymes can denature and microorganisms may be damaged or die, so decay rate falls. The optimum depends on the organisms and conditions; do not assume that warmer always means faster.
    • Gardeners and farmers try to provide optimum conditions for rapid decay of biological waste. The compost produced is a natural fertiliser for gardens or crops. Biogas generators can use methane from anaerobic decay as a fuel.
    • Calculate decay-rate changes, translate numerical and graphical information, and plot graphs with appropriate scales.

    What to do in an exam

    • Explain how water, oxygen and temperature change microbial/enzyme activity. Describe an increase towards an optimum and a decrease above the optimum due to enzyme denaturation, using evidence from the question.
    • Calculate a rate from measured change and time, compare rates with units, and plot or translate the data with labelled axes and suitable scales.

    In plain language

    Microorganisms decompose dead material using enzyme-controlled reactions. Water allows their activity, and oxygen supports aerobic respiration. A rise in temperature speeds reactions only up to an optimum; beyond it, enzymes lose their working shape and decay can slow. Without oxygen, anaerobic decay can produce methane for a biogas generator.

    Self-check

    Why can decay speed up as temperature rises and then slow above the optimum?

    Show the answer

    Increasing temperature initially speeds enzyme-controlled reactions and microbial respiration. Above the optimum, enzymes denature and microorganisms may be damaged, reducing the rate.

  • Higher

    Scope: Higher · 4.7.2.4

    Open revision guidance

    What to know

    • Higher-tier students evaluate how environmental changes affect species distribution in an ecosystem, using appropriate information.
    • Specified changes are temperature, availability of water and composition of atmospheric gases. Changes may be seasonal, geographic or caused by human interaction.

    What to do in an exam

    • Use supplied evidence to compare where species occur before and after a change; distinguish seasonal, geographic and human-caused contexts when possible.
    • Evaluate impact rather than merely describe it: identify affected species or distributions, cite data, and state limits or alternative factors where the information is incomplete.

    In plain language

    A species is found where conditions allow it to survive and reproduce. Changing temperature, water availability or atmospheric gases can make an area more or less suitable, shifting a species' distribution. The change may be seasonal, reflect different places, or result from human activity.

    Self-check

    Name the three environmental changes specified for this Higher-only requirement.

    Show the answer

    Temperature, availability of water, and composition of atmospheric gases.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.3.1

    Open revision guidance

    What to know

    • Biodiversity is the variety of all the different species of organisms on Earth or within an ecosystem.
    • High biodiversity helps stabilise ecosystems by reducing dependence on one species for food, shelter and maintenance of the physical environment. Human survival in the future relies on maintaining a good level of biodiversity.
    • Many human activities are reducing biodiversity; measures to try to stop this reduction have only been taken recently.

    What to do in an exam

    • Explain how a variety of species can make an ecosystem less dependent on any single species and therefore more stable.
    • Use evidence to distinguish a biodiversity change (variety of species) from a change in the number of individuals of one species.

    In plain language

    Biodiversity counts variety, not simply how many individuals there are. If many species provide ecological roles, losing one may have less severe effects than losing a species on which many others depend. This is one reason biodiversity supports ecosystem stability and people.

    Self-check

    Why can high biodiversity make an ecosystem more stable?

    Show the answer

    It reduces dependence on a single species for resources and for maintaining the physical environment, so the loss or decline of one species is less likely to destabilise the whole system.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.3.2

    Open revision guidance

    What to know

    • Rapid human population growth and rising living standards increase resource use and waste. Poor handling of waste and chemical materials causes more pollution.
    • Water pollution can come from sewage, fertiliser or toxic chemicals; air pollution from smoke and acidic gases; land pollution from landfill and toxic chemicals. Pollution kills plants and animals and can therefore reduce biodiversity.

    What to do in an exam

    • Classify a pollution example by affected environment and source, then trace its effect on organisms and biodiversity.
    • Evaluate waste-management information using environmental outcomes and evidence, rather than assuming all waste has the same effect.

    In plain language

    More people and greater consumption mean more materials are used and discarded. If sewage, chemicals, fertilisers, smoke or landfill pollute habitats, organisms may be harmed or killed. Fewer surviving species means lower biodiversity.

    Self-check

    Give one AQA source of pollution for water, air and land, and the stated consequence for biodiversity.

    Show the answer

    Water: sewage, fertiliser or toxic chemicals; air: smoke or acidic gases; land: landfill or toxic chemicals. Pollution can kill plants and animals, reducing biodiversity.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.3.3

    Open revision guidance

    What to know

    • Building, quarrying, farming and dumping waste reduce land available to other plants and animals.
    • Destroying peat bogs and other peat areas to produce garden compost reduces habitat area and the variety of plant, animal and microorganism species living there. Decay or burning of peat releases carbon dioxide into the atmosphere.
    • The specification highlights a conflict between cheap, available compost to increase food production and conserving peat bogs and peatlands for biodiversity and lower carbon dioxide emissions.

    What to do in an exam

    • Evaluate a land-use decision by weighing food production or material needs against habitat loss, biodiversity and carbon dioxide emissions.
    • Explain the chain from peat extraction to smaller habitat, reduced species variety and carbon release.

    In plain language

    Land has competing uses. Peat can be sold as compost, but removing it destroys a habitat and exposes stored carbon to decay or burning. A sound evaluation explains both the human benefit and the ecological and climate costs.

    Self-check

    Why does using peat for garden compost create both a biodiversity and climate concern?

    Show the answer

    It reduces peatland habitat and its species variety, and decay or burning of peat releases carbon dioxide.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.3.4

    Open revision guidance

    What to know

    • Large-scale deforestation has occurred in tropical areas to provide land for cattle and rice fields and to grow crops for biofuels.
    • Clearing forest removes habitat and may have wider environmental consequences; AQA expects students to evaluate the environmental implications of deforestation using information.

    What to do in an exam

    • For a deforestation scenario, identify which stated land demand drives clearing and evaluate consequences using evidence about habitats, species and the environment.
    • Balance benefits such as land for food or biofuel crops against environmental costs; do not claim every consequence without support from the question.

    In plain language

    Forest is cleared to make room for activities such as cattle rearing, rice cultivation and biofuel crops. The land-use benefit must be considered alongside what is lost when a tropical ecosystem is removed.

    Self-check

    Name both reasons for tropical deforestation listed in the specification.

    Show the answer

    To provide land for cattle and rice fields, and to grow crops for biofuels.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.3.5

    Open revision guidance

    What to know

    • Atmospheric carbon dioxide and methane levels are increasing and contribute to global warming. AQA requires students to describe some biological consequences; examples include species distributions shifting towards cooler regions or higher elevations, changed temperature and rainfall altering habitats, and seasonal events such as migration, breeding or flowering occurring at different times.
    • Habitat change can make conditions unsuitable for some populations, disrupt food-web timing and increase biodiversity risks where species cannot move or adapt quickly enough. Outcomes differ among organisms and places; use the data or context rather than claiming every species responds in the same way.
    • Evidence in complex contexts may be uncertain or incomplete. The scientific consensus about global warming and climate change is based on systematic reviews of thousands of peer-reviewed publications; this evidence base coexists with uncertainty about particular local effects or projections.

    What to do in an exam

    • Describe a concrete biological consequence and explain the causal chain: warming or altered rainfall changes habitat conditions, which can shift distribution, change seasonal timing or place a population at risk.
    • Use supplied evidence to distinguish observed effects from predictions. When evaluating evidence, separate uncertainty in a particular data set or local projection from the broader peer-reviewed evidence base.

    In plain language

    As climate conditions change, a species may find its old habitat too warm or dry and shift its range. Seasonal cues can also change, so migration, breeding or flowering may happen earlier or later. If habitat disappears or species cannot move, biodiversity can be put at risk. These are examples, not identical outcomes for every species.

    Self-check

    Give two biological consequences of global warming and explain one link between climate and the consequence.

    Show the answer

    Examples include a species shifting its distribution and a change in migration, breeding or flowering time. For example, warmer temperatures can make a former habitat unsuitable, so a population may move towards a cooler region or higher elevation.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.3.6

    Open revision guidance

    What to know

    • Students describe positive and negative human interactions in ecosystems and explain their impacts on biodiversity. Scientists and concerned citizens have introduced programmes to reduce harmful effects.
    • Specified approaches are breeding programmes for endangered species; protecting and regenerating rare habitats; restoring field margins and hedgerows where farmers grow one crop; reducing deforestation and carbon dioxide emissions through some governments' actions; and recycling resources instead of sending waste to landfill.
    • These choices can involve conflicting pressures, including conservation, food production, land use, cost and resource use.

    What to do in an exam

    • Evaluate a proposed method with evidence: explain the mechanism by which it protects species or habitat, then consider limitations and competing pressures.
    • Compare alternatives and reach a conclusion that is supported by the given information rather than treating any measure as universally best.

    In plain language

    Biodiversity can be protected by helping endangered populations, restoring habitat, retaining wildlife corridors such as hedgerows, reducing damaging emissions and reusing materials. Each action has practical costs or competing needs, so evaluation means considering both ecological benefit and constraints.

    Self-check

    List three AQA measures that can reduce negative human effects on biodiversity.

    Show the answer

    Any three: endangered-species breeding programmes; protection/regeneration of rare habitats; restoring field margins and hedgerows; reducing deforestation and carbon dioxide emissions; recycling rather than landfill.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.4.1

    Open revision guidance

    What to know

    • Trophic levels number how far an organism is along a food chain. Level 1 is plants and algae (producers), which make their own food. Level 2 is herbivores (primary consumers); level 3 is carnivores eating herbivores (secondary consumers); level 4 is carnivores eating other carnivores (tertiary consumers).
    • Apex predators are carnivores with no predators. Decomposers break down dead plant and animal matter by secreting enzymes into the environment; small soluble food molecules then diffuse into the microorganism.

    What to do in an exam

    • Assign trophic-level numbers from the producer upward and classify consumers according to what they eat.
    • Explain decomposition using extracellular enzyme secretion followed by diffusion of soluble molecules into the microorganism.

    In plain language

    A trophic level tells a feeding position, not a permanent species label: it depends on the food chain. Decomposers digest outside their cells, releasing small soluble products that can diffuse in and be used.

    Self-check

    What are trophic levels 1 to 4, and how do decomposers take in digested food?

    Show the answer

    Level 1 producers (plants/algae), level 2 primary consumers (herbivores), level 3 secondary consumers, level 4 tertiary consumers. Decomposers secrete enzymes outside and small soluble products diffuse into them.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.4.2

    Open revision guidance

    What to know

    • A pyramid of biomass represents the relative amount of biomass at each trophic level in a food chain. Trophic level 1 is placed at the bottom.
    • Students must construct accurate pyramids of biomass from appropriate data; bar widths represent biomass and should be proportional to the values.

    What to do in an exam

    • Read the supplied biomass values, order them by trophic level, select a consistent scale, and draw centred bars whose widths are proportional to biomass.
    • Label trophic levels and units where supplied; check that level 1 is at the base and the drawing accurately reflects each value.

    In plain language

    The pyramid turns a table of biomass into a visual comparison. Wider bars mean more biomass. It is the amount of biomass at each feeding level that matters, not the number or size of individual organisms.

    Self-check

    Where is trophic level 1 placed on a pyramid of biomass, and what should bar width show?

    Show the answer

    Trophic level 1 is at the bottom. Bar width should be proportional to the biomass at that level.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.4.3

    Open revision guidance

    What to know

    • Students describe biomass pyramids and explain why biomass is lost between trophic levels. Producers (mostly plants and algae) transfer about 1% of incident light energy into photosynthesis; only approximately 10% of biomass at each trophic level transfers to the level above.
    • Losses occur because not all ingested material is absorbed (some is egested as faeces); absorbed material is lost as waste, including carbon dioxide and water in respiration and water and urea in urine. Large amounts of glucose are used in respiration.
    • Calculate transfer efficiency as (biomass transferred to next level ÷ biomass available at previous level) × 100%, or as the equivalent fraction. Low transfer limits the number of organisms at higher trophic levels.

    What to do in an exam

    • Use masses from consecutive trophic levels, identify the correct starting biomass and calculate a percentage or fraction; state the result clearly.
    • Explain a smaller upper-level biomass through egestion, excretion and respiration losses, then connect reduced available biomass to fewer organisms.

    In plain language

    Organisms use much of what they eat or fail to absorb it, so only a small fraction becomes new biomass available to the next consumer. For example, 20 kg transferred from 200 kg is 20 ÷ 200 × 100 = 10% efficiency.

    Self-check

    A level has 500 g biomass and the next level has 45 g. What percentage transferred?

    Show the answer

    45 ÷ 500 × 100 = 9%.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.5.1

    Open revision guidance

    What to know

    • Food security means having enough food to feed a population. Biological and related pressures include rising birth rates threatening food security in some countries; changing diets in developed countries transporting scarce food resources around the world; new pests and pathogens affecting farming; environmental changes that affect production, including famine when rains fail; the cost of agricultural inputs; and conflicts that affect water or food availability.
    • Sustainable methods must be found to feed everyone on Earth. Population and food-production statistics can be used to evaluate food security.

    What to do in an exam

    • Use statistics to compare food supply with population needs and identify which stated pressures affect production, access or distribution.
    • Evaluate sustainability with evidence and avoid treating food availability as determined by population alone.

    In plain language

    Food security is about whether a population can obtain enough food. Harvests, pests, climate, costs, conflict and where food is sent all matter. An evaluation should separate producing enough food from making it available to people.

    Self-check

    Define food security and name three factors AQA lists that threaten it.

    Show the answer

    Food security is having enough food to feed a population. Threats include rising birth rate, changing diets and transport of scarce resources, pests/pathogens, environmental change or failed rains, input costs, and conflict affecting water or food.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.5.2

    Open revision guidance

    What to know

    • Food-production efficiency can be improved by restricting energy transfer from food animals to the environment. Movement can be limited and the temperature of the animals' surroundings controlled.
    • Some animals are fed high-protein foods to increase growth. Modern intensive farming methods can raise ethical objections; evaluate advantages and disadvantages rather than considering yield alone.

    What to do in an exam

    • Explain that less energy lost to movement or maintaining body temperature can leave more energy for growth, increasing food production efficiency.
    • Evaluate methods using productivity alongside animal welfare, ethical concerns, costs and any supplied evidence.

    In plain language

    Animals use energy to move and keep their bodies warm. Limiting movement and controlling surroundings can reduce some of those energy demands so more is available for growth. These methods can improve output but also raise welfare concerns.

    Self-check

    How can limiting movement and controlling temperature improve food production efficiency?

    Show the answer

    They restrict energy transfer from the animals to the environment, leaving more energy available for growth; the methods also require evaluation for ethical and welfare concerns.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.5.3

    Open revision guidance

    What to know

    • Ocean fish stocks are declining. Stocks must be maintained at a level where breeding continues; otherwise some species may disappear altogether in some areas.
    • Controlling net size and introducing fishing quotas play important roles in conserving stocks at a sustainable level. Different fishing techniques can be evaluated for their contribution to stock recovery.

    What to do in an exam

    • Explain how net-size rules can allow smaller fish to escape and breed, and how quotas limit total catch; use supplied information when comparing schemes.
    • Evaluate whether catches allow populations to reproduce and recover rather than judging success only by short-term yield.

    In plain language

    A fishery is sustainable only if enough fish remain to reproduce and replace those caught. Net rules and quotas reduce pressure on stocks, giving populations a chance to recover.

    Self-check

    Why are net-size controls and quotas used in fisheries?

    Show the answer

    They help conserve stocks: nets can allow some fish to escape and breed, while quotas limit catches so stocks can remain at a level where reproduction continues.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.7.5.4

    Open revision guidance

    What to know

    • Students describe and explain possible biotechnological and agricultural solutions to the demands of a growing human population, including genetic modification. Modern biotechnology can culture large quantities of microorganisms for food.
    • Fusarium fungus produces mycoprotein, a protein-rich food suitable for vegetarians. It is grown on glucose syrup in aerobic conditions; biomass is harvested and purified.
    • A genetically modified bacterium produces human insulin; after harvesting and purification it is used to treat people with diabetes. GM crops could provide more food or improve nutritional value, for example golden rice.

    What to do in an exam

    • Describe a production sequence accurately: organism, growth material/conditions where specified, harvested product and use.
    • Explain how biotechnology may address food or health needs, and evaluate potential benefits and concerns using evidence rather than general claims.

    In plain language

    Microorganisms can be grown in large controlled cultures to make useful products. Fusarium biomass becomes mycoprotein; engineered bacteria make insulin; and GM crops may increase yield or nutrition. Each example has a different organism and purpose, so keep their processes distinct.

    Self-check

    How is Fusarium mycoprotein made, and what are two properties AQA states?

    Show the answer

    Fusarium is grown on glucose syrup in aerobic conditions, then its biomass is harvested and purified. Mycoprotein is protein-rich and suitable for vegetarians.

Cross-paper knowledge

Working scientifically and maths

Both papers33 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 3.1

    Open revision guidance

    What to know

    • Scientific methods and theories develop over time. New experimental or observational data can lead scientists to revise models or theories.
    • Historical example: Louis Pasteur's swan-neck flask experiment used boiled broth and a curved neck that allowed air in but trapped dust and microorganisms. The broth stayed free of microbial growth while the neck remained intact; growth followed when the broth contacted trapped dust or the neck was broken. This evidence challenged spontaneous generation and supported the idea that microorganisms come from other microorganisms in the environment. Later evidence identifying particular pathogens linked microbes with disease; one experiment alone did not establish every part of germ theory.
    • Data may support, challenge or fail to distinguish a theory; evidence must be considered rather than treating a theory as an unquestionable fact.

    What to do in an exam

    • Explain how the swan-neck flask comparison controlled exposure and why the different growth outcomes supported an alternative to spontaneous generation.
    • Decide whether supplied data supports a theory, citing the evidence and limits; describe how accumulated evidence can prompt a model or theory to change.

    In plain language

    Pasteur compared broth protected from airborne dust with broth exposed to it. Microbial growth appeared only when microorganisms could reach the broth, so the results supported contamination from existing microbes rather than life appearing spontaneously. Later work connected specific microbes with disease.

    Self-check

    What did Pasteur's swan-neck flask experiment show, and what did it not prove by itself?

    Show the answer

    Broth stayed free of growth while dust and microorganisms were kept from it, and growth followed exposure. This supported the view that microorganisms came from other microorganisms, but by itself did not prove that every disease was caused by a particular pathogen.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.1

    Open revision guidance

    What to know

    • Models may be representational, spatial, descriptive, computational or mathematical. They help solve problems, make predictions and explain familiar or unfamiliar facts.
    • Scientists interpret and draw diagrams, translate data into model representations, match model features to observations, calculate or predict from models, identify limitations and test models through observation or experiment.

    What to do in an exam

    • Choose a model that fits the data, explain what its features represent and use it to predict or calculate.
    • State what a model omits or simplifies and propose an observation or experiment that could test it.

    In plain language

    A model is a useful representation, not the real system itself. It can reveal patterns and predict outcomes, but its assumptions and missing details limit what it can show.

    Self-check

    Give two ways to test a scientific model and one reason a model may have limits.

    Show the answer

    Test it against observations or an experiment; a model may simplify a complex system or omit relevant features.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.1

    Open revision guidance

    What to know

    • Scientific questions need data, but evidence may be uncertain, incomplete or unavailable, limiting conclusions.
    • New technologies can raise ethical questions; an ethical argument considers rights, harms, benefits and competing viewpoints rather than only whether something is technically possible.

    What to do in an exam

    • Explain what further evidence is needed and why an existing data set cannot fully answer a question.
    • Outline a balanced ethical argument about a technology, making clear which claims are evidence-based and which are value judgements.

    In plain language

    Science can answer many questions, but not always completely or with certainty. Ethical decisions add questions about what should be done and who may benefit or be harmed.

    Self-check

    Why might evidence be insufficient to answer a scientific question fully?

    Show the answer

    Data may be uncertain, incomplete or unavailable, so conclusions are limited and additional evidence may be needed.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.1

    Open revision guidance

    What to know

    • Explain everyday and technological applications of science and evaluate associated personal, social, economic and environmental implications.
    • Describe and evaluate, using data where provided, methods for tackling problems caused by human impacts on the environment; decisions should follow evaluation of evidence and arguments.

    What to do in an exam

    • Identify the application, who or what is affected, and benefits and costs across the four implication categories.
    • Compare environmental solutions using the data, explain limitations and make an evidence-based decision.

    In plain language

    A technology can solve one problem while creating costs elsewhere. A strong answer weighs consequences for people, society, the economy and the environment, then reaches a justified decision.

    Self-check

    What four types of implication should be considered when evaluating a scientific application?

    Show the answer

    Personal, social, economic and environmental implications.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.1

    Open revision guidance

    What to know

    • Evaluate risks in practical science and wider society, relating perceived risk to evidence about probability and consequences.
    • Science-based technologies can have hazards that must be considered alongside benefits. Risk perception can differ from measured risk, for example voluntary versus imposed risks and familiar versus unfamiliar or visible versus invisible hazards.

    What to do in an exam

    • Identify hazard, likelihood and possible severity, then compare risk with benefit using available evidence.
    • Explain why people may perceive an unfamiliar or imposed risk differently from a familiar or voluntary one without confusing perception with measured probability.

    In plain language

    Risk is about both the chance of harm and how serious it could be. People do not judge risks only by statistics: control, familiarity and visibility influence how threatening a hazard feels.

    Self-check

    Give two contrasts that can make perceived risk differ from measured risk.

    Show the answer

    Voluntary versus imposed risk and familiar versus unfamiliar (or visible versus invisible) hazards.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.1

    Open revision guidance

    What to know

    • Peer review helps detect false claims and establish consensus about which claims should be regarded as valid.
    • Popular-media reports of scientific developments are not subject to peer review and may be oversimplified, inaccurate or biased. Scientists communicate findings to varied audiences.

    What to do in an exam

    • Explain why independent scrutiny improves confidence without claiming peer review guarantees a result is correct.
    • Assess a media claim by checking evidence, wording, omissions and possible bias against the underlying research.

    In plain language

    Other specialists examine research before its claims are accepted widely. This helps catch problems, but readers should still evaluate evidence. A headline may simplify or distort the original findings.

    Self-check

    What does peer review help do, and what limitation does AQA identify for popular-media reports?

    Show the answer

    It helps detect false claims and establish consensus; popular-media reports are not peer-reviewed and may be oversimplified, inaccurate or biased.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.2

    Open revision guidance

    What to know

    • Use scientific theories and explanations to develop hypotheses. A hypothesis gives a proposed explanation or prediction that can be investigated.

    What to do in an exam

    • Given observations or data, identify a biological mechanism and predict how changing an independent variable may affect a measured outcome.
    • Make the prediction specific enough to test and avoid presenting it as a proven conclusion.

    In plain language

    A hypothesis connects an explanation to a prediction. It should lead to observations that could support or challenge it.

    Self-check

    What makes a hypothesis scientifically useful?

    Show the answer

    It is based on a scientific explanation and makes a specific, testable prediction that evidence could support or challenge.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.2

    Open revision guidance

    What to know

    • Plan experiments or procedures to observe, produce or characterise a substance, test hypotheses, check data or explore phenomena. Manipulate the independent variable, measure the dependent variable and control relevant variables.
    • The independent variable is changed or selected by the investigator; the dependent variable is measured for each change; control variables are kept the same so the comparison is fair. Apparatus knowledge informs a procedure.

    What to do in an exam

    • Describe ordered steps for the stated purpose and identify how each variable is set, measured or kept constant.
    • Explain why the procedure answers its question and why controls, repeats and appropriate measurements are needed.

    In plain language

    A plan is a reasoned method, not just a list of equipment. Change one factor deliberately, measure the response and keep other influential conditions stable so the result can be attributed to the change.

    Self-check

    Define independent, dependent and control variables.

    Show the answer

    Independent: changed or selected; dependent: measured for each independent-variable value; control: kept the same to make the comparison fair.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.2

    Open revision guidance

    What to know

    • Select suitable techniques, instruments, apparatus and materials for a specified experimental purpose, using knowledge of their capabilities.

    What to do in an exam

    • Name the instrument or method that directly measures the required variable and explain why its range, resolution or technique suits the task.
    • Reject unsuitable apparatus when its precision, sensitivity or measurement type would not answer the question.

    In plain language

    Choose equipment because it measures the thing you need, at an appropriate scale and accuracy. Explain the fit between apparatus and purpose.

    Self-check

    What should an answer include when selecting apparatus?

    Show the answer

    The suitable technique or instrument and a reason showing how its measurement capability meets the specified purpose.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.2

    Open revision guidance

    What to know

    • Carry out experiments with correct manipulation of apparatus, accurate measurements and due regard for health and safety.
    • Identify main hazards in a specified context and suggest ways to reduce the risk of harm.

    What to do in an exam

    • Name a context-specific hazard and a practical control that reduces exposure or likelihood of harm.
    • Explain how careful apparatus use and measurement technique improve data quality as well as safety.

    In plain language

    A hazard can cause harm; a control makes harm less likely or less severe. Safety advice should match the actual substance, organism or equipment, not be generic.

    Self-check

    How should you propose reducing risk in a practical question?

    Show the answer

    Identify the actual hazard and state a suitable control that reduces the chance or severity of harm while allowing the procedure to be carried out safely.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.2

    Open revision guidance

    What to know

    • Apply sampling techniques when a sample must represent a larger population or habitat. The sample method and locations affect whether conclusions can be generalised.

    What to do in an exam

    • Select a suitable sampling approach for the question and explain how random or systematic placement, adequate sample size and consistent method reduce bias.
    • Recognise when a sample may not represent the wider population and avoid overgeneralising.

    In plain language

    Sampling makes a large population measurable, but biased or too-small samples can give a misleading picture. The method must match what is being estimated.

    Self-check

    Why is a representative sample important?

    Show the answer

    It makes conclusions about the larger population more trustworthy; biased or insufficient samples may not reflect the population.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.2

    Open revision guidance

    What to know

    • Make and record observations and measurements using a range of apparatus and methods. Read values from scales in practical contexts and record them appropriately.

    What to do in an exam

    • Read between scale markings only to a justified resolution, include units and use a clear table with headings.
    • Record qualitative observations precisely and distinguish raw readings from calculated values.

    In plain language

    A measurement is useful only if it is read consistently and recorded clearly. Units and sensible precision make results interpretable and comparable.

    Self-check

    What should accompany a measured numerical value in a results table?

    Show the answer

    An appropriate unit in the heading, and a reading recorded at a precision justified by the instrument scale.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.2

    Open revision guidance

    What to know

    • Assess whether enough measurements have been taken and whether they are sufficiently precise. Evaluate whether a method is valid for its purpose.
    • Suggest method improvements and further investigations that address weaknesses or extend the question.

    What to do in an exam

    • Identify a specific limitation, explain how it affects validity, precision or confidence, then propose a feasible targeted improvement.
    • Distinguish repeating/adding measurements from changing a method to control a confounding variable.

    In plain language

    A useful evaluation links weakness to consequence and fix. Saying “be more accurate” is not enough: explain which measurement or control should change and why.

    Self-check

    What makes an experimental-method improvement well justified?

    Show the answer

    It addresses a specific identified weakness, explains how that weakness affects results, and states how the proposed change improves validity, precision or sufficiency.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.3

    Open revision guidance

    What to know

    • Present observations and data by appropriate methods. Construct and interpret frequency tables and diagrams, bar charts and histograms, and plot two variables from experimental or other data.

    What to do in an exam

    • Choose a display suited to the variable type; label axes/categories, include units where appropriate, and use a suitable scale.
    • Use bars for categories, histogram bars for continuous grouped data, and plotted points for paired variables.

    In plain language

    The display should preserve what the data mean. Choose the graph from the kind of variables, not from appearance alone, and label it so another person can read it.

    Self-check

    What graph feature distinguishes a histogram from a bar chart?

    Show the answer

    A histogram represents continuous grouped data with adjoining bars; a bar chart represents categories and normally has separated bars.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.3

    Open revision guidance

    What to know

    • Translate data between graphical and numerical forms while preserving the values, units and relationships.

    What to do in an exam

    • Read coordinates carefully from a graph to obtain numbers, or plot tabulated values at the correct coordinates and scale.
    • Check that the translated form represents the same trend and units as the original.

    In plain language

    Translation changes how information is displayed, not the information itself. A misplaced scale or forgotten unit changes its meaning.

    Self-check

    What should remain consistent when translating a graph into a table?

    Show the answer

    The data values, variable meaning, units and relationship or trend.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.3

    Open revision guidance

    What to know

    • Carry out and represent mathematical/statistical analysis: use appropriate significant figures; calculate arithmetic mean and range; construct/interpret frequency tables, diagrams, bar charts and histograms; make order-of-magnitude calculations.
    • Change the subject of an equation; substitute values into algebraic equations with appropriate units; determine slope and intercept of a linear graph; use the slope of a tangent to a curve as a rate of change; understand the physical meaning of area between a curve and the x-axis and estimate it by counting squares where appropriate.
    • Biology example, for a tangent drawn to a curved photosynthesis-rate graph, suppose two points on the tangent are (2, 4) and (6, 12), with x in relative light-intensity units and y in oxygen bubbles per minute. The rate of change at the curve point is the tangent gradient: (12 - 4) ÷ (6 - 2) = 8 ÷ 4 = 2 bubbles per minute per light-intensity unit.
    • Biology example, on a graph of oxygen-production rate against time, if the rate rises linearly from 1 mL/min to 3 mL/min over 2 minutes, the area under the line is a trapezium: ((1 + 3) ÷ 2) × 2 = 4 mL of oxygen produced. With a grid, estimate the same area by counting squares and applying the axis scale.

    What to do in an exam

    • Show substitutions and units, retain suitable significant figures, and check the magnitude of a result.
    • For a rate at one point on a curve, draw a tangent and calculate its gradient using two points on the tangent. For a rate-time graph, calculate or estimate the area under the curve and state the accumulated biological quantity represented by the units.

    In plain language

    A gradient on a tangent estimates how quickly a biological rate is changing at one point. Area under a rate-time graph accumulates that rate over time, giving a total amount, such as total oxygen produced.

    Self-check

    A tangent to a photosynthesis-rate curve passes through (2, 4) and (6, 12). What is its gradient?

    Show the answer

    (12 - 4) ÷ (6 - 2) = 8 ÷ 4 = 2 response units per x-axis unit.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.3

    Open revision guidance

    What to know

    • Every measurement has some uncertainty. The range of a set of measurements about the mean is used as a measure of uncertainty.

    What to do in an exam

    • Recognise that a recorded value is not perfectly exact; compare repeated measurements and calculate their range when assessing spread around the mean.
    • Use the spread to comment on confidence and avoid reporting unjustified precision.

    In plain language

    An instrument and method cannot give a perfectly certain value. Repeats show how much readings vary; a larger range signals greater spread in the measurements.

    Self-check

    What measure does AQA specify for uncertainty across a set of measurements?

    Show the answer

    The range of the measurements about the mean is used as a measure of uncertainty.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.3

    Open revision guidance

    What to know

    • Interpret verbal, diagrammatic, graphical, symbolic and numerical observations/data; identify patterns and trends, make inferences, draw conclusions and make predictions from data.

    What to do in an exam

    • Describe the direction and form of a trend with values, then make a prediction within the evidence range or state when extrapolation is uncertain.
    • Separate direct observations from inferred explanations and ensure the conclusion answers the question.

    In plain language

    A conclusion states what the evidence shows; an inference proposes why. Good answers distinguish them and support each with data.

    Self-check

    What is the difference between an observation and an inference?

    Show the answer

    An observation describes the recorded evidence; an inference is an explanation interpreted from that evidence.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.3

    Open revision guidance

    What to know

    • Present reasoned explanations that relate data to hypotheses. Assess the extent to which data are consistent with a hypothesis and identify which of competing hypotheses better explains the data.

    What to do in an exam

    • Cite results that agree or disagree and use calibrated language such as strongly, partly or poorly consistent.
    • Compare rival hypotheses against the same evidence and explain which accounts for more observations, including any unresolved data.

    In plain language

    Evidence can fit a hypothesis without proving it. Compare predictions with results and explain how well each alternative accounts for the pattern.

    Self-check

    Does data being consistent with a hypothesis prove it?

    Show the answer

    No. It shows the data fit the hypothesis to some extent, but other explanations may also fit and further evidence may be needed.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.3

    Open revision guidance

    What to know

    • Accurate measurements are close to the true value; precise measurements cluster closely. Repeatability means similar results on repetition under the same conditions by the same investigator; reproducibility means similar results from different investigators with different equipment.
    • Random errors cause unpredictable variation and can be reduced by more measurements and a mean. Systematic error shifts results consistently from the true value. Examine anomalous values to identify a cause; if they result from poor measurement, ignore them.

    What to do in an exam

    • Use the correct term when judging data quality and explain the evidence for that judgement.
    • Distinguish random spread from a consistent offset; investigate anomalies before deciding whether a poor measurement should be excluded.

    In plain language

    A tightly grouped set can still be wrong if every reading is shifted. Repeats reduce the effect of random variation, but do not remove a systematic bias. Accuracy, precision and reproducibility describe different properties.

    Self-check

    Which error is reduced by taking more measurements and calculating a mean, and which is not?

    Show the answer

    Random error is reduced by more measurements and a mean; systematic error is not removed because it shifts results consistently.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.3

    Open revision guidance

    What to know

    • Communicate scientific rationale, methods, findings and reasoned conclusions through coherent, logically structured paper-based or electronic reports and presentations.
    • Use verbal, diagrammatic, graphical, numerical and symbolic forms. Apply experimental skills and data analysis to required practicals and other practical investigations when appropriate information is supplied.

    What to do in an exam

    • Structure a report so the question/rationale, method, data, analysis and conclusion connect logically.
    • Choose representations that communicate evidence clearly and support conclusions with numerical or graphical evidence.

    In plain language

    Scientific communication lets another person understand why an investigation was done, how it was performed and what the data justify. Match words, diagrams and numbers to the message.

    Self-check

    What elements should a coherent practical report connect?

    Show the answer

    The scientific rationale, method, findings/data analysis and reasoned conclusion.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.4

    Open revision guidance

    What to know

    • Use scientific vocabulary, terminology and definitions accurately. This requirement applies throughout the specification, including required practicals.

    What to do in an exam

    • Use a precise term and define it in the context of the question; distinguish similar terms rather than relying on everyday meanings.
    • Use named variables, processes and biological structures consistently in explanations.

    In plain language

    Scientific words are compact definitions. Using the right term makes clear exactly what process or relationship you mean.

    Self-check

    Why does AQA assess precise scientific terminology across practical work too?

    Show the answer

    Terms communicate the exact process, variable, observation or conclusion, so they are important in both subject explanations and practical accounts.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.4

    Open revision guidance

    What to know

    • Recognise why scientific quantities matter and understand how they are determined.

    What to do in an exam

    • Identify what a quantity measures, how it is obtained from instruments or calculation, and whether it is direct or derived.
    • Use the quantity and its unit consistently when comparing results.

    In plain language

    A number only has scientific meaning when you know what it measures and how it was obtained. Quantities make observations comparable.

    Self-check

    What should you know about a scientific quantity beyond its numerical value?

    Show the answer

    What it measures, how it was determined, and the appropriate unit.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.4

    Open revision guidance

    What to know

    • Use SI units, for example kg, g, mg; km, m, mm; kJ and J, and use IUPAC chemical nomenclature unless inappropriate.

    What to do in an exam

    • Attach the correct SI unit to measured and calculated quantities and avoid mixing units within a calculation.
    • Use standard chemical names when applicable.

    In plain language

    Standard units and naming let results be compared reliably between investigations. Convert units first when quantities do not match.

    Self-check

    Give two sets of SI unit multiples/submultiples named by AQA.

    Show the answer

    Examples include kg, g, mg; km, m, mm; and kJ, J.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.4

    Open revision guidance

    What to know

    • The AQA source names eight examples: tera = 10^12, giga = 10^9, mega = 10^6, kilo = 10^3, centi = 10^-2, milli = 10^-3, micro = 10^-6 and nano = 10^-9. Deci is not among these named examples.

    What to do in an exam

    • Convert by multiplying by the prefix's power of ten, keeping the base unit clear. For example, 2.5 micrometres = 2.5 × 10^-6 metres = 0.0000025 metres.
    • Check whether the converted number should increase or decrease: a micrometre is a millionth of a metre, whereas a kilometre is a thousand metres.

    In plain language

    A prefix tells you how many powers of ten a unit represents. Tera through kilo are large multiples; centi through nano are fractions of the base unit.

    Self-check

    How many nanometres are in 3 micrometres?

    Show the answer

    Micro is 10^-6 and nano is 10^-9, so 1 micrometre = 1000 nanometres. Therefore 3 micrometres = 3000 nanometres.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.4

    Open revision guidance

    What to know

    • Interconvert units when comparing quantities or carrying out calculations.

    What to do in an exam

    • Convert all relevant values into compatible units before using an equation; show the conversion factor and retain the requested unit.
    • Check the result's scale by estimating whether the converted value should increase or decrease.

    In plain language

    A calculation cannot compare unlike units directly. Convert first, then calculate and report the answer in the unit requested.

    Self-check

    Convert 2.5 g to milligrams.

    Show the answer

    2.5 g = 2500 mg because 1 g = 1000 mg.

  • Foundation + Higher

    Scope: Foundation and Higher · 3.4

    Open revision guidance

    What to know

    • Use an appropriate number of significant figures in a calculation. Precision should be justified by the data and measurement context.

    What to do in an exam

    • Carry guard digits through intermediate calculations, then round the final result appropriately and include units.
    • Do not imply greater measurement precision than the supplied readings justify.

    In plain language

    A calculator can display many digits, but the measurements may not support all of them. Round sensibly at the end so the answer is useful without pretending to extra precision.

    Self-check

    Why should a final calculated answer not automatically include every calculator digit?

    Show the answer

    The input measurements have limited precision, so excessive digits imply unjustified accuracy; round to an appropriate number of significant figures.

  • Foundation + Higher

    Scope: Foundation and Higher · 4.8

    Open revision guidance

    What to know

    • Biology's nine universal ideas are: molecular structure relates to function; cells are fundamental units and form adapted tissues, organs and systems; organisms form populations, communities and ecosystems; organisms are interdependent and adapted; photosynthesis by green plants and algae traps sunlight to fix carbon dioxide and combine it with hydrogen from water to make organic compounds and oxygen; organic compounds fuel cellular respiration and other life reactions; ecosystem chemicals cycle; characteristics reflect genome and environmental interaction; and evolution by natural selection explains biodiversity and relatedness.
    • The wider science key ideas include using models/theories to explain phenomena; assuming effects have causes; change arising from interactions and differences; interactions acting at a distance; science progressing through hypothesis, experimentation, observation, theory and review; and quantitative analysis central to theory and inquiry.
    • The Biology course develops conceptual knowledge, understanding of biological inquiry, practical/modelling/problem-solving skills in laboratory and field contexts, and critical qualitative and quantitative evaluation of biological claims.

    What to do in an exam

    • Connect a specific topic to one or more key ideas, explaining the biological mechanism rather than merely listing the idea.
    • Use the ideas to organise an extended response, for example, connect photosynthesis, biomass, feeding relationships and material cycling, or connect cell structure to function and organisation.

    In plain language

    These are recurring lenses, not a separate biology chapter. They help link details: molecules build cells, organisms interact in ecosystems, energy and matter move through life, and evidence-based explanations are tested and revised.

    Self-check

    Name the key idea that links photosynthesis, food chains and ecosystem material cycles.

    Show the answer

    Photosynthesis captures light energy to make organic compounds; those compounds supply biomass through food chains, while chemicals in ecosystems are continually recycled.

  • Foundation + Higher

    Scope: Foundation and Higher · 7.1

    Open revision guidance

    What to know

    • Recognise and use decimal expressions and standard form; use ratios, fractions and percentages; estimate results of simple calculations.
    • AQA's Biology mathematics demands are appropriate to tier: Foundation maths questions are not below Key Stage 3 expectation, while Higher maths questions are not below Foundation GCSE mathematics demand.

    What to do in an exam

    • Convert between decimals and standard form, use fractions/ratios to compare quantities, calculate percentages and estimate before checking an exact result.
    • Show the relation used, preserve units and check whether the answer's size is plausible.

    In plain language

    Biology data can span very small and large values. Standard form and sensible estimates help prevent misplaced powers of ten; ratios and percentages make comparisons meaningful.

    Self-check

    Write 0.00042 in standard form and estimate 18% of 250.

    Show the answer

    0.00042 = 4.2 × 10⁻⁴; 18% of 250 = 45.

  • Foundation + Higher

    Scope: Foundation and Higher · 7.2

    Open revision guidance

    What to know

    • Use appropriate significant figures; calculate arithmetic means; construct and interpret frequency tables, diagrams, bar charts and histograms; understand sampling principles and simple probability.
    • Understand mean, mode and median; use scatter diagrams to identify correlation between variables; make order-of-magnitude calculations. Simple probability is the number of equally likely favourable outcomes divided by the total number of equally likely outcomes; for a fair coin, P(heads) = 1/2.
    • Worked data example: for the ordered results 2, 2, 5, 7, 9, the mean is (2 + 2 + 5 + 7 + 9) ÷ 5 = 5, the median is 5, and the mode is 2. An order-of-magnitude estimate: 0.004 × 3000 = 4 × 10^-3 × 3 × 10^3 = 12, which is about 10^1.

    What to do in an exam

    • Choose the correct average: mean uses all values, median is the middle after ordering, and mode is the most frequent; show the calculation and retain units when relevant.
    • For simple probability, count favourable outcomes and divide by all equally likely outcomes. Select a display suited to the data, interpret correlation without claiming it proves causation, judge sampling quality and estimate the order of magnitude before calculating exactly.

    In plain language

    A mean uses every value, while median and mode describe the centre or most common result differently. Probability is a fraction of possible outcomes. Order-of-magnitude work checks whether a calculated answer is around units, tens, thousands or another power of ten.

    Self-check

    What is the probability of rolling an even number on a fair six-sided die numbered 1 to 6?

    Show the answer

    The three even outcomes are 2, 4 and 6. There are 3 favourable outcomes out of 6 equally likely outcomes, so P(even) = 3/6 = 1/2.

  • Foundation + Higher

    Scope: Foundation and Higher · 7.3

    Open revision guidance

    What to know

    • Recognise and use =, <, <<, >>, >, ∝ and ~ to express equality, inequalities, much less/greater than, proportionality and approximate relationships.
    • Solve simple algebraic equations. The specification deliberately omits inapplicable intervening algebra criteria.

    What to do in an exam

    • Interpret the symbol in the biological relationship stated, and rearrange a simple equation to find an unknown quantity.
    • Substitute values only after isolating the required variable; check the result against the original relation.

    In plain language

    Symbols describe how quantities compare. Proportional means one quantity varies in relation to another; an equation can be rearranged to make the quantity you need the subject.

    Self-check

    What does ∝ mean, and what is the first step if you need x from y = 2x?

    Show the answer

    ∝ means is proportional to. Divide both sides by 2 to obtain x = y ÷ 2.

  • Foundation + Higher

    Scope: Foundation and Higher · 7.4

    Open revision guidance

    What to know

    • Translate information between graphical and numeric forms; understand y = mx + c as a linear relationship; plot two variables from data; determine the slope (gradient) and intercept of a straight-line graph.
    • A straight-line gradient is change in y divided by change in x; the intercept is the value of y when x is zero.

    What to do in an exam

    • Plot paired data with correct axes, units and scale; read coordinates and calculate gradient from two well-separated points on the line.
    • Interpret gradient and intercept in context.

    In plain language

    A graph displays a relationship. Gradient tells how quickly y changes as x changes.

    Self-check

    A straight line passes through (2, 5) and (6, 13). Find its gradient.

    Show the answer

    (13 - 5) ÷ (6 - 2) = 8 ÷ 4 = 2.

  • Foundation + Higher

    Scope: Foundation and Higher · 7.5

    Open revision guidance

    What to know

    • Calculate areas of triangles and rectangles, and surface areas and volumes of cubes. AQA Biology lists geometry criterion 5c; non-applicable geometry criteria are omitted.

    What to do in an exam

    • Use rectangle area = length × width; triangle area = ½ × base × perpendicular height; cube surface area = 6 × side²; cube volume = side³.
    • Keep units consistent and report area in square units and volume in cubic units.

    In plain language

    Area covers a flat surface, while volume measures three-dimensional space. The units change accordingly: centimetres squared for area and centimetres cubed for volume.

    Self-check

    A cube has side length 3 cm. What are its surface area and volume?

    Show the answer

    Surface area = 6 × 3² = 54 cm²; volume = 3³ = 27 cm³.

Cross-paper knowledge

Required practicals

Both papers10 revision points
  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.1

    Open revision guidance

    What to know

    • Use a light microscope to observe a selection of plant and animal cells, draw and label them, and include a magnification scale. Relevant apparatus skills: measure length and area and use a microscope to observe specimens and produce labelled scientific drawings (AT1, AT7).
    • The practical develops estimating relative size or area of sub-cellular structures (MS1d, MS3a).

    What to do in an exam

    • Place the slide on the stage and secure it. Select the lowest-power, low-magnification objective first. While looking from the side, move the stage close to the objective without letting the lens touch the coverslip; then look through the eyepiece and use coarse focus to find the image, followed by fine focus to sharpen it. Adjust illumination as needed.
    • Centre the specimen before changing to a higher-power objective. At higher power use fine focus only; coarse focusing can drive the objective into the slide, break glass or damage the lens. Keep eyes at the eyepiece while focusing, but check clearance from the side when moving the stage. Draw with clean lines and labels; measure image and actual size in compatible units and use magnification = image size ÷ actual size.

    In plain language

    Start with the smallest objective because it gives the widest field and makes the specimen easier to find. Coarse focus brings the image into view at low power; fine focus sharpens it. At high power the lens is close to the coverslip, so fine focus protects both glass and lens.

    Self-check

    Why should coarse focus not be used with a high-power objective, and what is the safe focusing sequence?

    Show the answer

    Coarse focus can make the objective hit and break the slide or damage the lens. Start at low power, focus with coarse then fine adjustment, centre the specimen, switch to higher power and use fine focus only.

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.2

    Open revision guidance

    What to know

    • Investigate antiseptics or antibiotics on bacterial growth using agar plates and measure zones of inhibition. Develop a hypothesis, plan a fair comparison, measure length/area and growth, use bacteria safely and ethically, and apply qualitative techniques to select the most effective treatment or concentration (AT1, AT3, AT4, AT8; WS2.1, 2.2, 2.4).
    • Calculate circular cross-sectional area of bacterial culture or clear agar using A = πr² (MS5c). The larger a clear inhibition zone under controlled conditions, the greater inhibition in that test; it does not by itself establish clinical usefulness.

    What to do in an exam

    • Use matched plates, inoculum, treatment amount and incubation conditions; vary the chosen antimicrobial and measure the clear zone consistently, including repeats.
    • Measure zone diameter/radius and calculate area where asked; identify hazards and follow teacher-approved aseptic procedures and disposal rules.

    In plain language

    The antimicrobial diffuses through agar. If it inhibits bacterial growth, a clear zone forms. A fair test changes only the treatment factor and compares the measured inhibition while preventing contamination and unsafe exposure.

    Self-check

    A clear zone has radius 4 mm. What is its area to one decimal place?

    Show the answer

    A = π × 4² = 16π ≈ 50.3 mm².

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.3

    Open revision guidance

    What to know

    • Investigate the effect of a range of salt or sugar solution concentrations on plant tissue mass. Measure mass and time, observe osmosis and water uptake; plan from osmosis theory, record observations, evaluate method and present/translate data (AT1, AT3, AT5; WS2.1, 2.2, 2.4, 2.6, 2.7, 3.1, 3.2).
    • Calculate rate/compound measures where relevant, percentage mass gain or loss and mean mass; plot, draw and interpret appropriate graphs (MS1a, 1c, 2b, 4a-d).

    What to do in an exam

    • Use equal-sized tissue pieces, a range of concentrations, consistent immersion time/temperature and repeats; blot consistently before final mass measurement.
    • Percentage mass change = (final mass − initial mass) ÷ initial mass × 100. Plot concentration against mean percentage mass change with labelled axes and suitable scale; use sign and trend to infer net water movement.

    In plain language

    Water moves across partially permeable cell membranes. Tissue may gain or lose mass depending on solution concentration. Percentage change allows fair comparison between starting samples of slightly different masses.

    Self-check

    A sample's mass falls from 2.0 g to 1.8 g. What is percentage mass change?

    Show the answer

    (1.8 − 2.0) ÷ 2.0 × 100 = −10%; the sample lost 10% of its starting mass.

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.4

    Open revision guidance

    What to know

    • Use qualitative reagents to test carbohydrates, lipids and proteins. Required named tests: Benedict's test for sugars, iodine test for starch and Biuret reagent for protein.
    • Use a Bunsen burner and boiling water bath safely where heating is required (AT2); use qualitative reagents to identify biological molecules (AT8); manipulate equipment safely (WS2.4). Ethanol used in the lipid emulsion test is flammable and must be kept away from any naked flame.

    What to do in an exam

    • Prepare labelled samples and a suitable control; add the correct reagent and record observations. For Benedict's test, heat the aqueous sample and reagent in a hot-water bath; positive reducing sugar gives a green-to-brick-red precipitate. Iodine positive starch turns blue-black; Biuret positive protein turns lilac/purple.
    • For lipid, add ethanol to the sample, then add water; a cloudy white emulsion indicates lipid. Do this ethanol test away from flames. Never heat ethanol or place an ethanol-containing tube near a Bunsen burner; use a separate hot-water-bath setup for Benedict's.

    In plain language

    Each reagent gives evidence for a particular food molecule. Ethanol catches fire easily, so the lipid test is a no-flame procedure. Heat Benedict's in a water bath, with ethanol kept in a separate area away from the burner.

    Self-check

    Why must the ethanol lipid test be kept separate from Bunsen heating?

    Show the answer

    Ethanol is flammable. Keep it away from naked flames and do not heat it; heat the separate aqueous Benedict's test in a hot-water bath.

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.5

    Open revision guidance

    What to know

    • Investigate how pH affects amylase reaction rate. Determine the time for complete digestion of starch at a range of pH values using continuous sampling: test with iodine every 30 seconds. Control temperature with a water bath or electric heater.
    • Record liquid volumes, time and pH; safely use heating, measure rate by iodine colour change and use iodine continuously to detect starch (AT1, AT2, AT5, AT8). Skills include hypothesis, accurate/safe method, representative sampling, recording, graphing and rate calculation (WS2.1, 2.4, 2.5, 2.6, 3.1, 3.2; MS1a, 1c).

    What to do in an exam

    • Keep enzyme/starch amounts and temperature constant while varying pH; remove equal samples at 30-second intervals and add each to iodine until it no longer turns blue-black.
    • Calculate rate consistently from the chosen time endpoint (for example 1 ÷ time for completion), then graph amylase activity against pH and explain limitations of the sampling interval.

    In plain language

    Iodine reveals whether starch remains. Repeated timed sampling estimates when it has all been digested. Comparing completion times across pH values shows how pH affects enzyme activity, provided other conditions are controlled.

    Self-check

    How often must iodine be used to test for starch in this practical, and what indicates starch has been digested?

    Show the answer

    Test every 30 seconds. Starch has been completely digested when the sample no longer turns iodine blue-black.

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.6

    Open revision guidance

    What to know

    • Investigate light intensity's effect on photosynthesis using an aquatic organism such as pondweed. Measure oxygen production and control temperature, using a large beaker of water as a heat shield and a thermometer/water bath as appropriate.
    • Use accurate measurement, heating/temperature control, observation of oxygen production, safe and ethical plant use and rate measurement (AT1-5). Skills include hypothesis, planning, multiple samples at each intensity, recording gas and graphing/translation (WS2.1, 2.2, 2.5, 2.6, 3.1, 3.2; MS1a, 1c, 4a, 4c).

    What to do in an exam

    • Change light intensity systematically, for example by varying lamp distance, while keeping temperature, pondweed and measurement time controlled; repeat at each condition.
    • Measure oxygen volume or bubble production consistently, calculate rate per unit time and graph light intensity against rate using labelled axes, suitable units and a sensible scale.

    In plain language

    A lamp can warm the pondweed as well as provide light. A heat shield and controlled water temperature make the light-intensity comparison fair.

    Self-check

    Why use a large beaker of water as a heat shield in this investigation?

    Show the answer

    It reduces heating of the pondweed by the lamp so temperature is controlled and the light-intensity comparison is fair.

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.7

    Open revision guidance

    What to know

    • Plan and carry out an investigation into how a factor affects human reaction time. A common ruler-drop method measures the distance a ruler falls before it is caught; use a supplied distance-to-time conversion table to record reaction time rather than treating an unlisted physics equation as a required method.
    • Illustrative rounded distance-to-time lookup: 5 cm -> 0.10 s; 10 cm -> 0.14 s; 20 cm -> 0.20 s. Use the table supplied for the investigation or question for actual readings.
    • Record time with appropriate apparatus, choose a suitable technique and use human participants safely and ethically (AT1, AT3, AT4). Translate numerical and graphical information (MS4a).

    What to do in an exam

    • The participant rests a forearm with fingers open at the edge of a table. The partner holds a ruler vertically with its zero mark level with the participant's thumb and finger, releases it without warning, and the participant catches it. Record the mark at the top of the thumb/finger and use the provided conversion table to find reaction time.
    • Example lookup: if the supplied table gives 10 cm as 0.14 s, record 0.14 s (140 ms). Repeat several times for each condition, calculate a mean, and compare a chosen factor while keeping the starting position and release method consistent. Use informed, voluntary participation.

    In plain language

    The ruler falls while the participant responds, and the catch distance is converted to time using a calibration table. Repeated trials reduce the effect of chance differences; the investigation tests a chosen factor, not just who catches fastest.

    Self-check

    A participant catches the ruler at 10 cm, and the supplied conversion table maps 10 cm to 0.14 s. What reaction time should be recorded in seconds and milliseconds?

    Show the answer

    Record 0.14 s, which is 140 ms. Use the supplied table; no physics equation is required for this lookup.

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.8

    Open revision guidance

    What to know

    • Investigate the effect of light or gravity on newly germinated seedling growth. Record results both as length measurements and accurate labelled biological drawings showing effects.
    • Measure length and time, observe and measure shoot/root growth, use plants safely and ethically, and make labelled scientific drawings (AT1, AT3, AT4, AT7). Plan observations, select appropriate apparatus, record results, evaluate/improve and present in tables, graphs or drawings (WS2.2, 2.3, 2.6, 2.7, 3.1).

    What to do in an exam

    • Use comparable newly germinated seedlings, change light direction/availability or orientation to gravity, and include a suitable comparison while controlling water and growth time.
    • Measure shoot/root lengths consistently at intervals and make accurate labelled drawings; compare direction and extent of growth and suggest method improvements.

    In plain language

    Seedlings grow in response to environmental direction cues. Measurements quantify growth, while labelled drawings capture its direction and form; both are explicitly required records.

    Self-check

    What two forms must be used to record results in this practical?

    Show the answer

    Length measurements and accurate, labelled biological drawings showing the effects of light or gravity.

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.9

    Open revision guidance

    What to know

    • Measure population size of a common species in a habitat and use sampling to investigate how a factor affects its distribution. Use length/area measurements, quadrats and transects, ethical organism handling and appropriate field sampling; AT1, AT3, AT4, AT6 and AT8.
    • Develop a hypothesis, plan, select techniques and measure an abiotic factor; estimate population size, calculate arithmetic mean, understand sampling and mean/mode/median, and graph with suitable axes (WS2.1-2.3; MS1d, 3a, 2b, 2d, 2f, 4c).

    What to do in an exam

    • For population size, divide the habitat into a measured total area and place same-size quadrats at randomly selected positions. Count the target species in each, calculate the mean count per quadrat, convert to mean density per square metre by dividing by quadrat area, then multiply by total habitat area.
    • Worked estimate: counts 6, 8, 7, 9 and 10 give a mean of 40 ÷ 5 = 8 organisms per 0.5 m² quadrat. Density = 8 ÷ 0.5 = 16 per m². For a 200 m² habitat, estimated population = 16 × 200 = 3200. To test distribution against a factor, lay a transect across the gradient, place quadrats at fixed intervals, and record species abundance and the abiotic factor at each point.

    In plain language

    Random quadrats estimate abundance without counting every organism. Turn the average count into a density, then scale it up to the habitat area. A transect answers a different question: how abundance changes along a measured environmental gradient.

    Self-check

    The mean is 8 plants per 0.5 m² quadrat and the habitat is 200 m². Estimate the population.

    Show the answer

    Density = 8 ÷ 0.5 = 16 plants per m². Estimated population = 16 × 200 = 3200 plants.

  • Foundation + Higher

    Scope: Foundation and Higher · 8.2.10

    Open revision guidance

    What to know

    • Investigate how temperature affects decay rate in fresh milk by measuring pH change. Measure temperature and pH, use appropriate apparatus to observe/measure decay, handle microorganisms safely and measure rate from pH change (AT1, AT3, AT4, AT5).
    • Develop a theory-based hypothesis, manipulate apparatus accurately and safely, record observations, evaluate/improve the method, calculate rate changes and translate/plot data graphically (WS2.1, 2.4, 2.6, 2.7; MS1c, 4a, 4c).

    What to do in an exam

    • Use equal milk volumes and a consistent pH method; place samples at controlled temperatures and measure pH at regular time intervals, using safe handling and disposal procedures.
    • Calculate pH change per unit time or compare rates over the same interval; graph results with labelled axes and suitable scales, consider repeats and method precision.

    In plain language

    Microorganisms cause milk to decay, changing its acidity and lowering pH. Comparing the speed of pH change at controlled temperatures provides evidence about temperature's effect on decay rate.

    Self-check

    If pH falls by 1.2 units over 6 hours, what is the mean rate of pH change?

    Show the answer

    A decrease of 1.2 ÷ 6 = 0.20 pH units per hour.

Earlier topic checklist

These earlier checklist ticks are kept separate from reviewed revision points above. They do not contribute to the progress count.

507 earlier checklist boxes. Their numbering may be internal; these ticks are not new requirement completions. Earlier tier labels have not been reconciled here. Use the source-checked revision points above for your selected tier.

Foundation tier topics

Higher tier topics